How to know if today is second or forth Saturday
0
$begingroup$
This is working. Is it ok?
import calendar
from datetime import datetime
def second_fourth_saturday(year):
holidays = {}
for month in range(1, 13):
holidays[month] =
cal = calendar.monthcalendar(year, month)
if cal[0][calendar.SATURDAY]:
holidays[month] = (
cal[1][calendar.SATURDAY],
cal[3][calendar.SATURDAY]
)
else:
holidays[month] = (
cal[2][calendar.SATURDAY],
cal[4][calendar.SATURDAY]
)
return holidays
if __name__ == "__main__":
today = datetime.today().day
tomonth = datetime.today().month
if today in second_fourth_saturday(2019)[tomonth]:
print("Enjoy")
else:
print("Start Working")
python python-3.x
asked 11 mins ago
Rahul PatelRahul Patel
220413
$endgroup$
add a comment |
0
$begingroup$
This is working. Is it ok?
import calendar
from datetime import datetime
def second_fourth_saturday(year):
holidays = {}
for month in range(1, 13):
holidays[month] =
cal = calendar.monthcalendar(year, month)
if cal[0][calendar.SATURDAY]:
holidays[month] = (
cal[1][calendar.SATURDAY],
cal[3][calendar.SATURDAY]
)
else:
holidays[month] = (
cal[2][calendar.SATURDAY],
cal[4][calendar.SATURDAY]
)
return holidays
if __name__ == "__main__":
today = datetime.today().day
tomonth = datetime.today().month
if today in second_fourth_saturday(2019)[tomonth]:
print("Enjoy")
else:
print("Start Working")
python python-3.x
asked 11 mins ago
Rahul PatelRahul Patel
220413
$endgroup$
add a comment |
0
0
0
$begingroup$
This is working. Is it ok?
import calendar
from datetime import datetime
def second_fourth_saturday(year):
holidays = {}
for month in range(1, 13):
holidays[month] =
cal = calendar.monthcalendar(year, month)
if cal[0][calendar.SATURDAY]:
holidays[month] = (
cal[1][calendar.SATURDAY],
cal[3][calendar.SATURDAY]
)
else:
holidays[month] = (
cal[2][calendar.SATURDAY],
cal[4][calendar.SATURDAY]
)
return holidays
if __name__ == "__main__":
today = datetime.today().day
tomonth = datetime.today().month
if today in second_fourth_saturday(2019)[tomonth]:
print("Enjoy")
else:
print("Start Working")
python python-3.x
asked 11 mins ago
Rahul PatelRahul Patel
220413
$endgroup$
This is working. Is it ok?
import calendar
from datetime import datetime
def second_fourth_saturday(year):
holidays = {}
for month in range(1, 13):
holidays[month] =
cal = calendar.monthcalendar(year, month)
if cal[0][calendar.SATURDAY]:
holidays[month] = (
cal[1][calendar.SATURDAY],
cal[3][calendar.SATURDAY]
)
else:
holidays[month] = (
cal[2][calendar.SATURDAY],
cal[4][calendar.SATURDAY]
)
return holidays
if __name__ == "__main__":
today = datetime.today().day
tomonth = datetime.today().month
if today in second_fourth_saturday(2019)[tomonth]:
print("Enjoy")
else:
print("Start Working")
python python-3.x
python python-3.x
asked 11 mins ago
Rahul PatelRahul Patel
220413
asked 11 mins ago
Rahul PatelRahul Patel
220413
asked 11 mins ago
Rahul PatelRahul Patel
220413
asked 11 mins ago
Rahul PatelRahul Patel
220413
asked 11 mins ago
Rahul PatelRahul Patel
220413
220413
add a comment |
add a comment |
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