Game of Rock paper and scissors against a random bot
$begingroup$
I have to do a project on a game of rock, paper, and scissors, and the code I have so far is a complete code for the game, but my professor does not like it since it is too redundant. Is there anyway to shorten it or make it more simple?
import random
while True:
bot = random.choice(["Rock", "Paper", "Scissors"]).lower()
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
if user_choice == bot:
print("We tied! I chose", bot," and you chose", user_choice)
elif user_choice == "rock":
if bot == "paper":
print("You lose! I chose", bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors":
print("You win! I chose", bot," and you chose", user_choice , ", Rock beat scissors!")
elif user_choice == "paper":
if bot == "rock":
print("You win! I chose",bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors:":
print("You lose! I chose", bot," and you chose", user_choice , ", Scissors beats paper")
elif user_choice == "scissors":
if bot == "paper":
print("You win! I chose", bot," and you chose",user_choice, ", Scissors beats paper")
elif bot == "rock":
print("You Lose! I chose", bot," and you chose", user_choice , ", Rock beats scissors")
else:
print("Invalid Entry, you typed:", user_choice, ", Please try again: ")
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
exit()
python homework rock-paper-scissors
New contributor
$endgroup$
add a comment |
$begingroup$
I have to do a project on a game of rock, paper, and scissors, and the code I have so far is a complete code for the game, but my professor does not like it since it is too redundant. Is there anyway to shorten it or make it more simple?
import random
while True:
bot = random.choice(["Rock", "Paper", "Scissors"]).lower()
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
if user_choice == bot:
print("We tied! I chose", bot," and you chose", user_choice)
elif user_choice == "rock":
if bot == "paper":
print("You lose! I chose", bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors":
print("You win! I chose", bot," and you chose", user_choice , ", Rock beat scissors!")
elif user_choice == "paper":
if bot == "rock":
print("You win! I chose",bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors:":
print("You lose! I chose", bot," and you chose", user_choice , ", Scissors beats paper")
elif user_choice == "scissors":
if bot == "paper":
print("You win! I chose", bot," and you chose",user_choice, ", Scissors beats paper")
elif bot == "rock":
print("You Lose! I chose", bot," and you chose", user_choice , ", Rock beats scissors")
else:
print("Invalid Entry, you typed:", user_choice, ", Please try again: ")
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
exit()
python homework rock-paper-scissors
New contributor
$endgroup$
$begingroup$
Welcome to Code Review! How much do you know about creating functions and passing arguments, has this been mentioned yet in the course?
$endgroup$
– Mast
3 hours ago
add a comment |
$begingroup$
I have to do a project on a game of rock, paper, and scissors, and the code I have so far is a complete code for the game, but my professor does not like it since it is too redundant. Is there anyway to shorten it or make it more simple?
import random
while True:
bot = random.choice(["Rock", "Paper", "Scissors"]).lower()
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
if user_choice == bot:
print("We tied! I chose", bot," and you chose", user_choice)
elif user_choice == "rock":
if bot == "paper":
print("You lose! I chose", bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors":
print("You win! I chose", bot," and you chose", user_choice , ", Rock beat scissors!")
elif user_choice == "paper":
if bot == "rock":
print("You win! I chose",bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors:":
print("You lose! I chose", bot," and you chose", user_choice , ", Scissors beats paper")
elif user_choice == "scissors":
if bot == "paper":
print("You win! I chose", bot," and you chose",user_choice, ", Scissors beats paper")
elif bot == "rock":
print("You Lose! I chose", bot," and you chose", user_choice , ", Rock beats scissors")
else:
print("Invalid Entry, you typed:", user_choice, ", Please try again: ")
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
exit()
python homework rock-paper-scissors
New contributor
$endgroup$
I have to do a project on a game of rock, paper, and scissors, and the code I have so far is a complete code for the game, but my professor does not like it since it is too redundant. Is there anyway to shorten it or make it more simple?
import random
while True:
bot = random.choice(["Rock", "Paper", "Scissors"]).lower()
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
if user_choice == bot:
print("We tied! I chose", bot," and you chose", user_choice)
elif user_choice == "rock":
if bot == "paper":
print("You lose! I chose", bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors":
print("You win! I chose", bot," and you chose", user_choice , ", Rock beat scissors!")
elif user_choice == "paper":
if bot == "rock":
print("You win! I chose",bot," and you chose", user_choice , ", Paper beats rock!")
elif bot == "scissors:":
print("You lose! I chose", bot," and you chose", user_choice , ", Scissors beats paper")
elif user_choice == "scissors":
if bot == "paper":
print("You win! I chose", bot," and you chose",user_choice, ", Scissors beats paper")
elif bot == "rock":
print("You Lose! I chose", bot," and you chose", user_choice , ", Rock beats scissors")
else:
print("Invalid Entry, you typed:", user_choice, ", Please try again: ")
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
exit()
python homework rock-paper-scissors
python homework rock-paper-scissors
New contributor
New contributor
edited 11 mins ago
200_success
130k16153417
130k16153417
New contributor
asked 3 hours ago
Minh TranMinh Tran
1
1
New contributor
New contributor
$begingroup$
Welcome to Code Review! How much do you know about creating functions and passing arguments, has this been mentioned yet in the course?
$endgroup$
– Mast
3 hours ago
add a comment |
$begingroup$
Welcome to Code Review! How much do you know about creating functions and passing arguments, has this been mentioned yet in the course?
$endgroup$
– Mast
3 hours ago
$begingroup$
Welcome to Code Review! How much do you know about creating functions and passing arguments, has this been mentioned yet in the course?
$endgroup$
– Mast
3 hours ago
$begingroup$
Welcome to Code Review! How much do you know about creating functions and passing arguments, has this been mentioned yet in the course?
$endgroup$
– Mast
3 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Please run this a few times and let me know what you think. There is almost certainly a way to make this even simpler than I made it (for example, ties are being treated as a special case, but that is not necessary). However, as it is, it at least avoids some of the repetition in the original code.
# note: I'm using 4 spaces for indentations in Python, which is common.
import random
def main():
while True:
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
# if the user enters -1 this immediately ends everything (note that in your original code that was not the case)
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
break
play_game(user_choice)
def play_game(user_choice):
# In this situation there is no need for .lower(), just don't capitalize your words in the first place
# I changed bot to bot_choice so a reader (or your future self) will more immediately know what's in the variable
bot_choice = random.choice(["rock", "paper", "scissors"])
if user_choice == bot_choice:
print("We tied! I chose {} and you chose {}".format(bot_choice, user_choice))
return
win_or_lose, winning_object, loosing_object = check_for_win(bot_choice, user_choice)
if win_or_lose is not None:
print("You {}! I chose {}, and you chose {}, {} beats {}!".format(win_or_lose, bot_choice, user_choice, winning_object, loosing_object))
return
print("Invalid Entry, you typed: {}, Please try again: ".format(user_choice))
def check_for_win(bot_choice, user_choice):
# dictionary keys are tuples that have possible game-outcomes, dictionary values show winning object give the key
rules_dictionary = {('paper', 'rock'): 'paper', ('rock', 'scissors'): 'rock', ('paper', 'scissors'): 'scissors'}
# iterate through the keys of the dictionary
for two_choices_in_won_game in rules_dictionary:
if sorted((bot_choice, user_choice)) == sorted(two_choices_in_won_game):
if bot_choice == rules_dictionary[two_choices_in_won_game]:
return 'lose', bot_choice, user_choice
return 'win', user_choice, bot_choice
return None, None, None
# The below if statement will evaluate to True of your program is run from the command line
if __name__ == '__main__':
main()
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Please run this a few times and let me know what you think. There is almost certainly a way to make this even simpler than I made it (for example, ties are being treated as a special case, but that is not necessary). However, as it is, it at least avoids some of the repetition in the original code.
# note: I'm using 4 spaces for indentations in Python, which is common.
import random
def main():
while True:
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
# if the user enters -1 this immediately ends everything (note that in your original code that was not the case)
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
break
play_game(user_choice)
def play_game(user_choice):
# In this situation there is no need for .lower(), just don't capitalize your words in the first place
# I changed bot to bot_choice so a reader (or your future self) will more immediately know what's in the variable
bot_choice = random.choice(["rock", "paper", "scissors"])
if user_choice == bot_choice:
print("We tied! I chose {} and you chose {}".format(bot_choice, user_choice))
return
win_or_lose, winning_object, loosing_object = check_for_win(bot_choice, user_choice)
if win_or_lose is not None:
print("You {}! I chose {}, and you chose {}, {} beats {}!".format(win_or_lose, bot_choice, user_choice, winning_object, loosing_object))
return
print("Invalid Entry, you typed: {}, Please try again: ".format(user_choice))
def check_for_win(bot_choice, user_choice):
# dictionary keys are tuples that have possible game-outcomes, dictionary values show winning object give the key
rules_dictionary = {('paper', 'rock'): 'paper', ('rock', 'scissors'): 'rock', ('paper', 'scissors'): 'scissors'}
# iterate through the keys of the dictionary
for two_choices_in_won_game in rules_dictionary:
if sorted((bot_choice, user_choice)) == sorted(two_choices_in_won_game):
if bot_choice == rules_dictionary[two_choices_in_won_game]:
return 'lose', bot_choice, user_choice
return 'win', user_choice, bot_choice
return None, None, None
# The below if statement will evaluate to True of your program is run from the command line
if __name__ == '__main__':
main()
$endgroup$
add a comment |
$begingroup$
Please run this a few times and let me know what you think. There is almost certainly a way to make this even simpler than I made it (for example, ties are being treated as a special case, but that is not necessary). However, as it is, it at least avoids some of the repetition in the original code.
# note: I'm using 4 spaces for indentations in Python, which is common.
import random
def main():
while True:
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
# if the user enters -1 this immediately ends everything (note that in your original code that was not the case)
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
break
play_game(user_choice)
def play_game(user_choice):
# In this situation there is no need for .lower(), just don't capitalize your words in the first place
# I changed bot to bot_choice so a reader (or your future self) will more immediately know what's in the variable
bot_choice = random.choice(["rock", "paper", "scissors"])
if user_choice == bot_choice:
print("We tied! I chose {} and you chose {}".format(bot_choice, user_choice))
return
win_or_lose, winning_object, loosing_object = check_for_win(bot_choice, user_choice)
if win_or_lose is not None:
print("You {}! I chose {}, and you chose {}, {} beats {}!".format(win_or_lose, bot_choice, user_choice, winning_object, loosing_object))
return
print("Invalid Entry, you typed: {}, Please try again: ".format(user_choice))
def check_for_win(bot_choice, user_choice):
# dictionary keys are tuples that have possible game-outcomes, dictionary values show winning object give the key
rules_dictionary = {('paper', 'rock'): 'paper', ('rock', 'scissors'): 'rock', ('paper', 'scissors'): 'scissors'}
# iterate through the keys of the dictionary
for two_choices_in_won_game in rules_dictionary:
if sorted((bot_choice, user_choice)) == sorted(two_choices_in_won_game):
if bot_choice == rules_dictionary[two_choices_in_won_game]:
return 'lose', bot_choice, user_choice
return 'win', user_choice, bot_choice
return None, None, None
# The below if statement will evaluate to True of your program is run from the command line
if __name__ == '__main__':
main()
$endgroup$
add a comment |
$begingroup$
Please run this a few times and let me know what you think. There is almost certainly a way to make this even simpler than I made it (for example, ties are being treated as a special case, but that is not necessary). However, as it is, it at least avoids some of the repetition in the original code.
# note: I'm using 4 spaces for indentations in Python, which is common.
import random
def main():
while True:
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
# if the user enters -1 this immediately ends everything (note that in your original code that was not the case)
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
break
play_game(user_choice)
def play_game(user_choice):
# In this situation there is no need for .lower(), just don't capitalize your words in the first place
# I changed bot to bot_choice so a reader (or your future self) will more immediately know what's in the variable
bot_choice = random.choice(["rock", "paper", "scissors"])
if user_choice == bot_choice:
print("We tied! I chose {} and you chose {}".format(bot_choice, user_choice))
return
win_or_lose, winning_object, loosing_object = check_for_win(bot_choice, user_choice)
if win_or_lose is not None:
print("You {}! I chose {}, and you chose {}, {} beats {}!".format(win_or_lose, bot_choice, user_choice, winning_object, loosing_object))
return
print("Invalid Entry, you typed: {}, Please try again: ".format(user_choice))
def check_for_win(bot_choice, user_choice):
# dictionary keys are tuples that have possible game-outcomes, dictionary values show winning object give the key
rules_dictionary = {('paper', 'rock'): 'paper', ('rock', 'scissors'): 'rock', ('paper', 'scissors'): 'scissors'}
# iterate through the keys of the dictionary
for two_choices_in_won_game in rules_dictionary:
if sorted((bot_choice, user_choice)) == sorted(two_choices_in_won_game):
if bot_choice == rules_dictionary[two_choices_in_won_game]:
return 'lose', bot_choice, user_choice
return 'win', user_choice, bot_choice
return None, None, None
# The below if statement will evaluate to True of your program is run from the command line
if __name__ == '__main__':
main()
$endgroup$
Please run this a few times and let me know what you think. There is almost certainly a way to make this even simpler than I made it (for example, ties are being treated as a special case, but that is not necessary). However, as it is, it at least avoids some of the repetition in the original code.
# note: I'm using 4 spaces for indentations in Python, which is common.
import random
def main():
while True:
user_choice = input("Choose between Rock, Paper, and Scissors or -1 to exit: n ").lower()
# if the user enters -1 this immediately ends everything (note that in your original code that was not the case)
if user_choice == '-1':
print("You selected -1 to exit, Goodbye!")
break
play_game(user_choice)
def play_game(user_choice):
# In this situation there is no need for .lower(), just don't capitalize your words in the first place
# I changed bot to bot_choice so a reader (or your future self) will more immediately know what's in the variable
bot_choice = random.choice(["rock", "paper", "scissors"])
if user_choice == bot_choice:
print("We tied! I chose {} and you chose {}".format(bot_choice, user_choice))
return
win_or_lose, winning_object, loosing_object = check_for_win(bot_choice, user_choice)
if win_or_lose is not None:
print("You {}! I chose {}, and you chose {}, {} beats {}!".format(win_or_lose, bot_choice, user_choice, winning_object, loosing_object))
return
print("Invalid Entry, you typed: {}, Please try again: ".format(user_choice))
def check_for_win(bot_choice, user_choice):
# dictionary keys are tuples that have possible game-outcomes, dictionary values show winning object give the key
rules_dictionary = {('paper', 'rock'): 'paper', ('rock', 'scissors'): 'rock', ('paper', 'scissors'): 'scissors'}
# iterate through the keys of the dictionary
for two_choices_in_won_game in rules_dictionary:
if sorted((bot_choice, user_choice)) == sorted(two_choices_in_won_game):
if bot_choice == rules_dictionary[two_choices_in_won_game]:
return 'lose', bot_choice, user_choice
return 'win', user_choice, bot_choice
return None, None, None
# The below if statement will evaluate to True of your program is run from the command line
if __name__ == '__main__':
main()
answered 1 hour ago
okcappokcapp
626
626
add a comment |
add a comment |
Minh Tran is a new contributor. Be nice, and check out our Code of Conduct.
Minh Tran is a new contributor. Be nice, and check out our Code of Conduct.
Minh Tran is a new contributor. Be nice, and check out our Code of Conduct.
Minh Tran is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
Welcome to Code Review! How much do you know about creating functions and passing arguments, has this been mentioned yet in the course?
$endgroup$
– Mast
3 hours ago