thread starts running before calling Thread.start
t1=threading.Thread(target=self.read())
print "something"
t2=threading.Thread(target=self.runChecks(), args=(self))
self.read runs indefinitely, so the program won't ever reach the print line. How is this possible without calling t1.start()? (Even if I call that, it shold start running and go on to the next line, shouldn't it?)
python multithreading python-multithreading
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
add a comment |
t1=threading.Thread(target=self.read())
print "something"
t2=threading.Thread(target=self.runChecks(), args=(self))
self.read runs indefinitely, so the program won't ever reach the print line. How is this possible without calling t1.start()? (Even if I call that, it shold start running and go on to the next line, shouldn't it?)
python multithreading python-multithreading
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
add a comment |
t1=threading.Thread(target=self.read())
print "something"
t2=threading.Thread(target=self.runChecks(), args=(self))
self.read runs indefinitely, so the program won't ever reach the print line. How is this possible without calling t1.start()? (Even if I call that, it shold start running and go on to the next line, shouldn't it?)
python multithreading python-multithreading
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
t1=threading.Thread(target=self.read())
print "something"
t2=threading.Thread(target=self.runChecks(), args=(self))
self.read runs indefinitely, so the program won't ever reach the print line. How is this possible without calling t1.start()? (Even if I call that, it shold start running and go on to the next line, shouldn't it?)
python multithreading python-multithreading
python multithreading python-multithreading
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
edited Mar 30 '18 at 21:54
martineau
68.2k1090183
68.2k1090183
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
asked Aug 3 '12 at 9:05
Tyler DurdenTyler Durden
5963724
5963724
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You're passing the result of self.read to the target argument of Thread. Thread expects to be passed a function to call, so just remove the parentheses and remember to start the Thread:
t1=threading.Thread(target=self.read)
t1.start()
print "something"
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
add a comment |
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1 Answer
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1 Answer
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active
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You're passing the result of self.read to the target argument of Thread. Thread expects to be passed a function to call, so just remove the parentheses and remember to start the Thread:
t1=threading.Thread(target=self.read)
t1.start()
print "something"
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
add a comment |
You're passing the result of self.read to the target argument of Thread. Thread expects to be passed a function to call, so just remove the parentheses and remember to start the Thread:
t1=threading.Thread(target=self.read)
t1.start()
print "something"
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
add a comment |
You're passing the result of self.read to the target argument of Thread. Thread expects to be passed a function to call, so just remove the parentheses and remember to start the Thread:
t1=threading.Thread(target=self.read)
t1.start()
print "something"
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
You're passing the result of self.read to the target argument of Thread. Thread expects to be passed a function to call, so just remove the parentheses and remember to start the Thread:
t1=threading.Thread(target=self.read)
t1.start()
print "something"
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
answered Aug 3 '12 at 9:10
user634175user634175
2,4521627
2,4521627
add a comment |
add a comment |
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