How can i filter javascript Object? [on hold]

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-3
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var obj =;

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-2"] = { "name": "gopal", "age" : 15, "dept" : "testing" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

obj["emp-4"] = { "name": "prakash", "age" : 25, "dept" : "designing" };

How to retrieve employees from dept="development" like

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

edited 2 days ago

asked 2 days ago

Gogul

New contributor

put on hold as unclear what you're asking by Toby Speight, πάντα ῥεῖ, t3chb0t, konijn, RobH 2 days ago

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

Hi! We only review existing and working code. This question will get closed.
– konijn
2 days ago

add a comment |

up vote
-3
down vote

favorite

var obj =;

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-2"] = { "name": "gopal", "age" : 15, "dept" : "testing" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

obj["emp-4"] = { "name": "prakash", "age" : 25, "dept" : "designing" };

How to retrieve employees from dept="development" like

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

edited 2 days ago

asked 2 days ago

Gogul

New contributor

put on hold as unclear what you're asking by Toby Speight, πάντα ῥεῖ, t3chb0t, konijn, RobH 2 days ago

Hi! We only review existing and working code. This question will get closed.
– konijn
2 days ago

add a comment |

up vote
-3
down vote

favorite

var obj =;

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-2"] = { "name": "gopal", "age" : 15, "dept" : "testing" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

obj["emp-4"] = { "name": "prakash", "age" : 25, "dept" : "designing" };

How to retrieve employees from dept="development" like

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

edited 2 days ago

asked 2 days ago

Gogul

New contributor

var obj =;

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-2"] = { "name": "gopal", "age" : 15, "dept" : "testing" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

obj["emp-4"] = { "name": "prakash", "age" : 25, "dept" : "designing" };

How to retrieve employees from dept="development" like

obj["emp-1"] = { "name": "gogul", "age" : 10 , "dept" : "development" };

obj["emp-3"] = { "name": "gowtham", "age" : 20, "dept" : "development" };

javascript object-oriented array

edited 2 days ago

asked 2 days ago

Gogul

New contributor

edited 2 days ago

asked 2 days ago

Gogul

New contributor

edited 2 days ago

asked 2 days ago

Gogul

New contributor

asked 2 days ago

Gogul

asked 2 days ago

Gogul

New contributor

Gogul is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

put on hold as unclear what you're asking by Toby Speight, πάντα ῥεῖ, t3chb0t, konijn, RobH 2 days ago

Hi! We only review existing and working code. This question will get closed.
– konijn
2 days ago

add a comment |

Hi! We only review existing and working code. This question will get closed.
– konijn
2 days ago

Hi! We only review existing and working code. This question will get closed.
– konijn
2 days ago

add a comment |

1 Answer
1

active

oldest

votes

up vote
-1
down vote

for (var i = 0; i < obj.length; i++) {

            if (obj[i].dept == "development") {

                // filtered data                    

            }

        }

if you want to use this data in another block you can create new array and push every filtered data.

answered 2 days ago

xamt

New contributor

1

Welcome to Code Review. Please refuse to answer off-topic questions.
– Heslacher
2 days ago

Welcome to Code Review! Please refrain from answering low-quality questions that are likely to get closed. Once, you've answered, that limits what can be done to improve the question, making it more likely that your efforts are wasted. It's better to wait until the question is properly ready before you answer!
– Toby Speight
2 days ago

add a comment |

1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

up vote
-1
down vote

for (var i = 0; i < obj.length; i++) {

            if (obj[i].dept == "development") {

                // filtered data                    

            }

        }

if you want to use this data in another block you can create new array and push every filtered data.

answered 2 days ago

xamt

New contributor

1

Welcome to Code Review. Please refuse to answer off-topic questions.
– Heslacher
2 days ago

Welcome to Code Review! Please refrain from answering low-quality questions that are likely to get closed. Once, you've answered, that limits what can be done to improve the question, making it more likely that your efforts are wasted. It's better to wait until the question is properly ready before you answer!
– Toby Speight
2 days ago

add a comment |

up vote
-1
down vote

for (var i = 0; i < obj.length; i++) {

            if (obj[i].dept == "development") {

                // filtered data                    

            }

        }

if you want to use this data in another block you can create new array and push every filtered data.

answered 2 days ago

xamt

New contributor

1

Welcome to Code Review. Please refuse to answer off-topic questions.
– Heslacher
2 days ago

Welcome to Code Review! Please refrain from answering low-quality questions that are likely to get closed. Once, you've answered, that limits what can be done to improve the question, making it more likely that your efforts are wasted. It's better to wait until the question is properly ready before you answer!
– Toby Speight
2 days ago

add a comment |

up vote
-1
down vote

for (var i = 0; i < obj.length; i++) {

            if (obj[i].dept == "development") {

                // filtered data                    

            }

        }

if you want to use this data in another block you can create new array and push every filtered data.

answered 2 days ago

xamt

New contributor

for (var i = 0; i < obj.length; i++) {

            if (obj[i].dept == "development") {

                // filtered data                    

            }

        }

if you want to use this data in another block you can create new array and push every filtered data.

answered 2 days ago

xamt

New contributor

answered 2 days ago

xamt

New contributor

answered 2 days ago

xamt

answered 2 days ago

xamt

New contributor

xamt is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

1

Welcome to Code Review. Please refuse to answer off-topic questions.
– Heslacher
2 days ago

Welcome to Code Review! Please refrain from answering low-quality questions that are likely to get closed. Once, you've answered, that limits what can be done to improve the question, making it more likely that your efforts are wasted. It's better to wait until the question is properly ready before you answer!
– Toby Speight
2 days ago

add a comment |

1

Welcome to Code Review. Please refuse to answer off-topic questions.
– Heslacher
2 days ago

Welcome to Code Review! Please refrain from answering low-quality questions that are likely to get closed. Once, you've answered, that limits what can be done to improve the question, making it more likely that your efforts are wasted. It's better to wait until the question is properly ready before you answer!
– Toby Speight
2 days ago

Welcome to Code Review. Please refuse to answer off-topic questions.
– Heslacher
2 days ago

Welcome to Code Review! Please refrain from answering low-quality questions that are likely to get closed. Once, you've answered, that limits what can be done to improve the question, making it more likely that your efforts are wasted. It's better to wait until the question is properly ready before you answer!
– Toby Speight
2 days ago

add a comment |

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