*args returns a list containing only those arguments that are even (PYTHON)











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Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)









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  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.
    – Loocid
    Nov 20 at 1:50

















up vote
3
down vote

favorite












Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)









share|improve this question
























  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.
    – Loocid
    Nov 20 at 1:50















up vote
3
down vote

favorite









up vote
3
down vote

favorite











Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)









share|improve this question















Hi i'm learning python and in an exercise they ask me to a function that takes an arbitrary number of arguments and return a list containing only those arguments that are even.



My code is wrong i know:



def myfunc(*args):
for n in args:
if n%2 == 0:
return list(args)
myfunc(1,2,3,4,5,6,7,8,9,10)






python python-3.x






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edited Nov 20 at 1:53









Austin

9,2723828




9,2723828










asked Nov 20 at 1:46









Aarón Más

183




183












  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.
    – Loocid
    Nov 20 at 1:50




















  • Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.
    – Loocid
    Nov 20 at 1:50


















Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.
– Loocid
Nov 20 at 1:50






Create a list like output = then append n into it if n is even: output.append(n). Then return output at the end of myfunc.
– Loocid
Nov 20 at 1:50














1 Answer
1






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0
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accepted










Do a list-comprehension which picks elements from args that matches our selection criteria:



def myfunc(*args):
return [n for n in args if n%2 == 0]

print(myfunc(1,2,3,4,5,6,7,8,9,10))
# [2, 4, 6, 8, 10]





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    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    0
    down vote



    accepted










    Do a list-comprehension which picks elements from args that matches our selection criteria:



    def myfunc(*args):
    return [n for n in args if n%2 == 0]

    print(myfunc(1,2,3,4,5,6,7,8,9,10))
    # [2, 4, 6, 8, 10]





    share|improve this answer

























      up vote
      0
      down vote



      accepted










      Do a list-comprehension which picks elements from args that matches our selection criteria:



      def myfunc(*args):
      return [n for n in args if n%2 == 0]

      print(myfunc(1,2,3,4,5,6,7,8,9,10))
      # [2, 4, 6, 8, 10]





      share|improve this answer























        up vote
        0
        down vote



        accepted







        up vote
        0
        down vote



        accepted






        Do a list-comprehension which picks elements from args that matches our selection criteria:



        def myfunc(*args):
        return [n for n in args if n%2 == 0]

        print(myfunc(1,2,3,4,5,6,7,8,9,10))
        # [2, 4, 6, 8, 10]





        share|improve this answer












        Do a list-comprehension which picks elements from args that matches our selection criteria:



        def myfunc(*args):
        return [n for n in args if n%2 == 0]

        print(myfunc(1,2,3,4,5,6,7,8,9,10))
        # [2, 4, 6, 8, 10]






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 20 at 1:52









        Austin

        9,2723828




        9,2723828






























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