Breadth First Search Counter Example











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Statement:



"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."



I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.



I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.



Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.










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  • Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
    – bishop
    Nov 20 at 2:05















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0
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favorite












Statement:



"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."



I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.



I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.



Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.










share|improve this question
























  • Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
    – bishop
    Nov 20 at 2:05













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Statement:



"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."



I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.



I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.



Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.










share|improve this question















Statement:



"Consider an arbitrary graph G=(V,E) and a source vertex s that is in V. For each shortest paths tree rooted at s, there exists an ordering of the vertices in an adjacency list representation of G which results in precisely this shortest-paths tree when BFS is run from s."



I am struggling to come up with a counter-example for this statement that I have taken for face value to be FALSE.



I understand that the ordering matters when it comes to the shortest-paths tree derived from BFS assuming that the order of the vertex's in the adjacency list is the order BFS follows but can't seem to think of a counter-example that violates this statement.



Edit: I am not asking how to find the other shortest-tree paths, but an example that shows that there are OTHER shortest-tree paths that are not found by BFS.







graph-theory






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edited Nov 20 at 2:18

























asked Nov 20 at 2:01









John Larkos

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177












  • Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
    – bishop
    Nov 20 at 2:05


















  • Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
    – bishop
    Nov 20 at 2:05
















Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 at 2:05




Possible duplicate of Finding all the shortest paths between two nodes in unweighted undirected graph
– bishop
Nov 20 at 2:05












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Confirm your graph is unweighted and undirected ?






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    Confirm your graph is unweighted and undirected ?






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      Confirm your graph is unweighted and undirected ?






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        up vote
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        Confirm your graph is unweighted and undirected ?






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        Confirm your graph is unweighted and undirected ?







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        answered Nov 22 at 15:37









        TheWildHealer

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