$replaceRoot in mongodb aggregation
up vote
1
down vote
favorite
I have a collection like this:
{
"_id" : ObjectId("5bd1686ba64b9206349284db"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b2"
}
]
}
{
"_id" : ObjectId("5bd16ab8a64b92068d485054"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b3"
}
]
}
The following structure is what I want:
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b3"
}
I tried this aggregate operations:
db.getCollection('t_system_code').aggregate([
{"$unwind":"$codeInstances"},
{$match:{"codeInstances.name":"b","type" : "Package"}},
{"$project":{"codeInstances":1,"_id":0}}
]);
But thatundefineds not the structure I want:
{
"codeInstances" : {
"name" : "b",
"description" : "b1"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b2"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b3"
}
}
Help. Thank you.
mongodb mongodb-query aggregation-framework
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
asked Oct 30 at 7:32
赵彬杰
83
add a comment |
up vote
1
down vote
favorite
I have a collection like this:
{
"_id" : ObjectId("5bd1686ba64b9206349284db"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b2"
}
]
}
{
"_id" : ObjectId("5bd16ab8a64b92068d485054"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b3"
}
]
}
The following structure is what I want:
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b3"
}
I tried this aggregate operations:
db.getCollection('t_system_code').aggregate([
{"$unwind":"$codeInstances"},
{$match:{"codeInstances.name":"b","type" : "Package"}},
{"$project":{"codeInstances":1,"_id":0}}
]);
But thatundefineds not the structure I want:
{
"codeInstances" : {
"name" : "b",
"description" : "b1"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b2"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b3"
}
}
Help. Thank you.
mongodb mongodb-query aggregation-framework
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
asked Oct 30 at 7:32
赵彬杰
83
make corrections：The following structure is what I want: { "name" : "b", "description" : "b1" }, { "name" : "b", "description" : "b2" }, { "name" : "b", "description" : "b3" }
– 赵彬杰
Oct 30 at 7:35
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I have a collection like this:
{
"_id" : ObjectId("5bd1686ba64b9206349284db"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b2"
}
]
}
{
"_id" : ObjectId("5bd16ab8a64b92068d485054"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b3"
}
]
}
The following structure is what I want:
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b3"
}
I tried this aggregate operations:
db.getCollection('t_system_code').aggregate([
{"$unwind":"$codeInstances"},
{$match:{"codeInstances.name":"b","type" : "Package"}},
{"$project":{"codeInstances":1,"_id":0}}
]);
But thatundefineds not the structure I want:
{
"codeInstances" : {
"name" : "b",
"description" : "b1"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b2"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b3"
}
}
Help. Thank you.
mongodb mongodb-query aggregation-framework
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
asked Oct 30 at 7:32
赵彬杰
83
I have a collection like this:
{
"_id" : ObjectId("5bd1686ba64b9206349284db"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b2"
}
]
}
{
"_id" : ObjectId("5bd16ab8a64b92068d485054"),
"type" : "Package",
"codeInstances" : [
{
"name" : "a",
"description" : "a"
},
{
"name" : "b",
"description" : "b3"
}
]
}
The following structure is what I want:
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b1"
},
{
"name" : "b",
"description" : "b3"
}
I tried this aggregate operations:
db.getCollection('t_system_code').aggregate([
{"$unwind":"$codeInstances"},
{$match:{"codeInstances.name":"b","type" : "Package"}},
{"$project":{"codeInstances":1,"_id":0}}
]);
But thatundefineds not the structure I want:
{
"codeInstances" : {
"name" : "b",
"description" : "b1"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b2"
}
}
{
"codeInstances" : {
"name" : "b",
"description" : "b3"
}
}
Help. Thank you.
mongodb mongodb-query aggregation-framework
mongodb mongodb-query aggregation-framework
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
asked Oct 30 at 7:32
赵彬杰
83
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
asked Oct 30 at 7:32
赵彬杰
83
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
edited Nov 20 at 17:36
Anthony Winzlet
13k41139
13k41139
asked Oct 30 at 7:32
赵彬杰
83
asked Oct 30 at 7:32
赵彬杰
83
asked Oct 30 at 7:32
赵彬杰
83
83
make corrections：The following structure is what I want: { "name" : "b", "description" : "b1" }, { "name" : "b", "description" : "b2" }, { "name" : "b", "description" : "b3" }
– 赵彬杰
Oct 30 at 7:35
add a comment |
make corrections：The following structure is what I want: { "name" : "b", "description" : "b1" }, { "name" : "b", "description" : "b2" }, { "name" : "b", "description" : "b3" }
– 赵彬杰
Oct 30 at 7:35
make corrections：The following structure is what I want: { "name" : "b", "description" : "b1" }, { "name" : "b", "description" : "b2" }, { "name" : "b", "description" : "b3" }
– 赵彬杰
Oct 30 at 7:35
make corrections：The following structure is what I want: { "name" : "b", "description" : "b1" }, { "name" : "b", "description" : "b2" }, { "name" : "b", "description" : "b3" }
– 赵彬杰
Oct 30 at 7:35
add a comment |
2 Answers
2
active
oldest
votes
up vote
1
down vote
accepted
You can try below aggregation using $replaceRoot
db.collection.aggregate([
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$unwind": "$codeInstances" },
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$replaceRoot": { "newRoot": "$codeInstances" }}
])
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
add a comment |
up vote
1
down vote
You just need to project for name and description instead of whole codeInstances. Check below
db.collection.aggregate([
{ $unwind: "$codeInstances" },
{ $match: { "codeInstances.name": "b", "type": "Package" }},
{ $project: {
"name": "$codeInstances.name",
"description": "$codeInstances.description",
"_id": 0
}}
])
Output:
[
{ "description": "b1", "name": "b" },
{ "description": "b2", "name": "b" },
{ "description": "b3", "name": "b" }
]
answered Oct 30 at 7:36
Hardik Shah
1,6532723
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
You can try below aggregation using $replaceRoot
db.collection.aggregate([
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$unwind": "$codeInstances" },
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$replaceRoot": { "newRoot": "$codeInstances" }}
])
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
add a comment |
up vote
1
down vote
accepted
You can try below aggregation using $replaceRoot
db.collection.aggregate([
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$unwind": "$codeInstances" },
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$replaceRoot": { "newRoot": "$codeInstances" }}
])
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
You can try below aggregation using $replaceRoot
db.collection.aggregate([
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$unwind": "$codeInstances" },
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$replaceRoot": { "newRoot": "$codeInstances" }}
])
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
You can try below aggregation using $replaceRoot
db.collection.aggregate([
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$unwind": "$codeInstances" },
{ "$match": { "codeInstances.name": "b", "type": "Package" }},
{ "$replaceRoot": { "newRoot": "$codeInstances" }}
])
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
answered Oct 30 at 8:42
Anthony Winzlet
13k41139
13k41139
add a comment |
add a comment |
up vote
1
down vote
You just need to project for name and description instead of whole codeInstances. Check below
db.collection.aggregate([
{ $unwind: "$codeInstances" },
{ $match: { "codeInstances.name": "b", "type": "Package" }},
{ $project: {
"name": "$codeInstances.name",
"description": "$codeInstances.description",
"_id": 0
}}
])
Output:
[
{ "description": "b1", "name": "b" },
{ "description": "b2", "name": "b" },
{ "description": "b3", "name": "b" }
]
answered Oct 30 at 7:36
Hardik Shah
1,6532723
add a comment |
up vote
1
down vote
You just need to project for name and description instead of whole codeInstances. Check below
db.collection.aggregate([
{ $unwind: "$codeInstances" },
{ $match: { "codeInstances.name": "b", "type": "Package" }},
{ $project: {
"name": "$codeInstances.name",
"description": "$codeInstances.description",
"_id": 0
}}
])
Output:
[
{ "description": "b1", "name": "b" },
{ "description": "b2", "name": "b" },
{ "description": "b3", "name": "b" }
]
answered Oct 30 at 7:36
Hardik Shah
1,6532723
add a comment |
up vote
1
down vote
up vote
1
down vote
You just need to project for name and description instead of whole codeInstances. Check below
db.collection.aggregate([
{ $unwind: "$codeInstances" },
{ $match: { "codeInstances.name": "b", "type": "Package" }},
{ $project: {
"name": "$codeInstances.name",
"description": "$codeInstances.description",
"_id": 0
}}
])
Output:
[
{ "description": "b1", "name": "b" },
{ "description": "b2", "name": "b" },
{ "description": "b3", "name": "b" }
]
answered Oct 30 at 7:36
Hardik Shah
1,6532723
You just need to project for name and description instead of whole codeInstances. Check below
db.collection.aggregate([
{ $unwind: "$codeInstances" },
{ $match: { "codeInstances.name": "b", "type": "Package" }},
{ $project: {
"name": "$codeInstances.name",
"description": "$codeInstances.description",
"_id": 0
}}
])
Output:
[
{ "description": "b1", "name": "b" },
{ "description": "b2", "name": "b" },
{ "description": "b3", "name": "b" }
]
answered Oct 30 at 7:36
Hardik Shah
1,6532723
edited Oct 30 at 7:42
answered Oct 30 at 7:36
Hardik Shah
1,6532723
answered Oct 30 at 7:36
Hardik Shah
1,6532723
answered Oct 30 at 7:36
Hardik Shah
1,6532723
1,6532723
add a comment |
add a comment |
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make corrections：The following structure is what I want: { "name" : "b", "description" : "b1" }, { "name" : "b", "description" : "b2" }, { "name" : "b", "description" : "b3" }
– 赵彬杰
Oct 30 at 7:35