Regex - matching brazilian phone numbers
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
|
show 1 more comment
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
If you match the whole string by enclosing the whole regex with^and$, will it be OK?
– Wiktor Stribiżew
Nov 21 '18 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 '18 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 '18 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 '18 at 17:19
1
Try(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 '18 at 17:21
|
show 1 more comment
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
I'm trying to use Regex to validate brazilian phone numbers.
For some reason, I cannot use b to indicate the beginning and the end for the match. In this case, my Regex selects some invalid phone numbers as valid.
RegEX:
(?([0-9]{2,3}|0{1}((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}
Valid numbers:
(00)0000-0000; true
(00)000000000; true
(00) 00000 0000; true
00 00000 0000; true
(000)00000 0000; true
Invalid numbers:
23232443243243423432; true
(0000)000000000; true
a00 00000-0000 ; true
Thanks!
javascript regex
javascript regex
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
edited Nov 21 '18 at 18:12
Poul Bak
5,45831232
5,45831232
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
asked Nov 21 '18 at 17:12
Zeca NovaesZeca Novaes
14510
14510
If you match the whole string by enclosing the whole regex with^and$, will it be OK?
– Wiktor Stribiżew
Nov 21 '18 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 '18 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 '18 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 '18 at 17:19
1
Try(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 '18 at 17:21
|
show 1 more comment
If you match the whole string by enclosing the whole regex with^and$, will it be OK?
– Wiktor Stribiżew
Nov 21 '18 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 '18 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 '18 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 '18 at 17:19
1
Try(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.
– Wiktor Stribiżew
Nov 21 '18 at 17:21
If you match the whole string by enclosing the whole regex with
^ and $, will it be OK?– Wiktor Stribiżew
Nov 21 '18 at 17:15
If you match the whole string by enclosing the whole regex with
^ and $, will it be OK?– Wiktor Stribiżew
Nov 21 '18 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 '18 at 17:16
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 '18 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 '18 at 17:19
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 '18 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 '18 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 '18 at 17:19
1
1
Try
(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.– Wiktor Stribiżew
Nov 21 '18 at 17:21
Try
(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.– Wiktor Stribiżew
Nov 21 '18 at 17:21
|
show 1 more comment
1 Answer
1
active
oldest
votes
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
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oldest
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active
oldest
votes
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
add a comment |
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
add a comment |
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
You should place word boundaries at the "right" places. They must placed at the first obligatory word char matching pattern and after the last obligatory word char.
(?b([0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b
^^ ^^
See the regex demo
If you put b before (?, when there is a ( before a digit, the word boundary will invalidate the match if there is no word char right before the (.
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
answered Nov 21 '18 at 17:25
Wiktor StribiżewWiktor Stribiżew
311k16132207
311k16132207
add a comment |
add a comment |
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If you match the whole string by enclosing the whole regex with
^and$, will it be OK?– Wiktor Stribiżew
Nov 21 '18 at 17:15
Parentheses, spaces and dashes don't actually mean anything as far as telephone devices are concerned, you could very well strip those from the string before validating.
– Havenard
Nov 21 '18 at 17:16
@Havenard, I'm using this Regex as Watson Assistant pattern. That's the problem.
– Zeca Novaes
Nov 21 '18 at 17:19
@WiktorStribiżew Not working :(
– Zeca Novaes
Nov 21 '18 at 17:19
1
Try
(?(b[0-9]{2,3}|0((x|[0-9]){2,3}[0-9]{2})))?s*[0-9]{4,5}[- ]*[0-9]{4}b. See demo.– Wiktor Stribiżew
Nov 21 '18 at 17:21