JS Double Fetch condition












0















I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")
.then(res => {
if(res.status != 404)
res.json()
else
fetch("../myJson.json")
.then(res => res.json())
.then(data => console.log(data))
.catch(err => console.error(err));
})
.then(data => console.log(data))
.catch(err => console.error(err));


Thanks!










share|improve this question




















  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12
















0















I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")
.then(res => {
if(res.status != 404)
res.json()
else
fetch("../myJson.json")
.then(res => res.json())
.then(data => console.log(data))
.catch(err => console.error(err));
})
.then(data => console.log(data))
.catch(err => console.error(err));


Thanks!










share|improve this question




















  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12














0












0








0








I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")
.then(res => {
if(res.status != 404)
res.json()
else
fetch("../myJson.json")
.then(res => res.json())
.then(data => console.log(data))
.catch(err => console.error(err));
})
.then(data => console.log(data))
.catch(err => console.error(err));


Thanks!










share|improve this question
















I'm working in get a list from a local file. But the folder sometimes can change. So come here to ask you guys if it's correct, because I think there is a better way to do it, idk. Please help me :)



  fetch("./myJson.json")
.then(res => {
if(res.status != 404)
res.json()
else
fetch("../myJson.json")
.then(res => res.json())
.then(data => console.log(data))
.catch(err => console.error(err));
})
.then(data => console.log(data))
.catch(err => console.error(err));


Thanks!







javascript fetch-api






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 16:49









Bergi

374k60565897




374k60565897










asked Nov 24 '18 at 15:59









JohnsonJohnson

2371619




2371619








  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12














  • 1





    You will need to return the nested promises from the callback

    – Bergi
    Nov 24 '18 at 16:12








1




1





You will need to return the nested promises from the callback

– Bergi
Nov 24 '18 at 16:12





You will need to return the nested promises from the callback

– Bergi
Nov 24 '18 at 16:12












1 Answer
1






active

oldest

votes


















3














You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 
if (res.ok)
return res.json()
else
return fetch("../myJson.json").then(res => res.json());
}).then(console.log, console.error);





share|improve this answer
























  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3














You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 
if (res.ok)
return res.json()
else
return fetch("../myJson.json").then(res => res.json());
}).then(console.log, console.error);





share|improve this answer
























  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00
















3














You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 
if (res.ok)
return res.json()
else
return fetch("../myJson.json").then(res => res.json());
}).then(console.log, console.error);





share|improve this answer
























  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00














3












3








3







You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 
if (res.ok)
return res.json()
else
return fetch("../myJson.json").then(res => res.json());
}).then(console.log, console.error);





share|improve this answer













You will need to return the nested promises from the callback and use the promise chaining feature:



fetch("./myJson.json").then(res => { 
if (res.ok)
return res.json()
else
return fetch("../myJson.json").then(res => res.json());
}).then(console.log, console.error);






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 24 '18 at 16:14









BergiBergi

374k60565897




374k60565897













  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00



















  • Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

    – Johnson
    Nov 24 '18 at 16:39






  • 1





    The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

    – Bergi
    Nov 24 '18 at 16:48













  • Hmmm got it ! Thanks a lot man :) !!

    – Johnson
    Nov 24 '18 at 17:00

















Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

– Johnson
Nov 24 '18 at 16:39





Nice Bergi!! Thanks!! Just a detail... If the first fetch fails, an error 404 shows up in console. Can I tell him that "if the first fetch fails, the second one will solve it. You don't have to show any error in console about this first fetch."

– Johnson
Nov 24 '18 at 16:39




1




1





The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

– Bergi
Nov 24 '18 at 16:48







The 404 will always show up in the console, you cannot prevent that from JS. You will need to use different console settings. Or actually handle the logic on the server side with a redirect.

– Bergi
Nov 24 '18 at 16:48















Hmmm got it ! Thanks a lot man :) !!

– Johnson
Nov 24 '18 at 17:00





Hmmm got it ! Thanks a lot man :) !!

– Johnson
Nov 24 '18 at 17:00




















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