Regular expression for capturing hashtags in groups












2















I need a regular expression to capture a #hashtag in multiple groups(group 1-"#" group 2-"hasshtag").
I tried:



"(\b#)([a-z0-9]{1,})(\b)"


But this doesn't capture anything.Any suggestions?






ios regex







share|improve this question























  • It should be: "(\B#)([a-zA-Z0-9]+)"

    – anubhava
    Nov 24 '18 at 16:25













  • Try "\B(#)(\w+)". Please also add the code to repro into the question body.

    – Wiktor Stribiżew
    Nov 24 '18 at 17:47


















2















I need a regular expression to capture a #hashtag in multiple groups(group 1-"#" group 2-"hasshtag").
I tried:



"(\b#)([a-z0-9]{1,})(\b)"


But this doesn't capture anything.Any suggestions?






ios regex







share|improve this question























  • It should be: "(\B#)([a-zA-Z0-9]+)"

    – anubhava
    Nov 24 '18 at 16:25













  • Try "\B(#)(\w+)". Please also add the code to repro into the question body.

    – Wiktor Stribiżew
    Nov 24 '18 at 17:47
















2












2








2








I need a regular expression to capture a #hashtag in multiple groups(group 1-"#" group 2-"hasshtag").
I tried:



"(\b#)([a-z0-9]{1,})(\b)"


But this doesn't capture anything.Any suggestions?






ios regex







share|improve this question














I need a regular expression to capture a #hashtag in multiple groups(group 1-"#" group 2-"hasshtag").
I tried:



"(\b#)([a-z0-9]{1,})(\b)"


But this doesn't capture anything.Any suggestions?






ios regex




ios regex






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 24 '18 at 16:24









user426132user426132

5812618




5812618













  • It should be: "(\B#)([a-zA-Z0-9]+)"

    – anubhava
    Nov 24 '18 at 16:25













  • Try "\B(#)(\w+)". Please also add the code to repro into the question body.

    – Wiktor Stribiżew
    Nov 24 '18 at 17:47





















  • It should be: "(\B#)([a-zA-Z0-9]+)"

    – anubhava
    Nov 24 '18 at 16:25













  • Try "\B(#)(\w+)". Please also add the code to repro into the question body.

    – Wiktor Stribiżew
    Nov 24 '18 at 17:47



















It should be: "(\B#)([a-zA-Z0-9]+)"

– anubhava
Nov 24 '18 at 16:25







It should be: "(\B#)([a-zA-Z0-9]+)"

– anubhava
Nov 24 '18 at 16:25















Try "\B(#)(\w+)". Please also add the code to repro into the question body.

– Wiktor Stribiżew
Nov 24 '18 at 17:47







Try "\B(#)(\w+)". Please also add the code to repro into the question body.

– Wiktor Stribiżew
Nov 24 '18 at 17:47














1 Answer
1






active

oldest

votes


















1














You may use this regex:



"(\B#)([a-zA-Z0-9]+)"


B asserts position where b does not match. Using b before # will fail the match unless there is a word character before #.



RegEx Demo






share|improve this answer



















  • 1





    works great. Thanks

    – user426132
    Nov 24 '18 at 17:59











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














You may use this regex:



"(\B#)([a-zA-Z0-9]+)"


B asserts position where b does not match. Using b before # will fail the match unless there is a word character before #.



RegEx Demo






share|improve this answer



















  • 1





    works great. Thanks

    – user426132
    Nov 24 '18 at 17:59
















1














You may use this regex:



"(\B#)([a-zA-Z0-9]+)"


B asserts position where b does not match. Using b before # will fail the match unless there is a word character before #.



RegEx Demo






share|improve this answer



















  • 1





    works great. Thanks

    – user426132
    Nov 24 '18 at 17:59














1












1








1







You may use this regex:



"(\B#)([a-zA-Z0-9]+)"


B asserts position where b does not match. Using b before # will fail the match unless there is a word character before #.



RegEx Demo






share|improve this answer













You may use this regex:



"(\B#)([a-zA-Z0-9]+)"


B asserts position where b does not match. Using b before # will fail the match unless there is a word character before #.



RegEx Demo







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 24 '18 at 16:28









anubhavaanubhava

529k46329404




529k46329404








  • 1





    works great. Thanks

    – user426132
    Nov 24 '18 at 17:59














  • 1





    works great. Thanks

    – user426132
    Nov 24 '18 at 17:59








1




1





works great. Thanks

– user426132
Nov 24 '18 at 17:59





works great. Thanks

– user426132
Nov 24 '18 at 17:59




















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