AssertionError: Index is not unique on dataframe (Entity cust) using Featuretools












1














I have a dataframe as below



customerid                                   term   age
08a858899538ddb8e015390510b321f0830199897 30 24
18a858959537a097401537a4e316e25f730196361 60 72
a8589c253ace09b0153af6ba58f1f313019822366 45 38


I am creating an entity as below using featuretools



es = es.entity_from_dataframe(entity_id = 'cust', dataframe = df, index = 'customerid')


but i get the error



AssertionError: Index is not unique on dataframe (Entity cust)


yet customerid is the identifier










share|improve this question




















  • 1




    Is it possible that customerid is not unique? You can check if that is the case with len(es) == es.customerid.nunique() (if it's False, then you have repeated customerids).
    – Julian Peller
    Nov 20 at 14:15






  • 1




    @JulianPeller is right. You should run that check on the dataframe not the entityset though, so the code would be len(df) == df.customerid.nunique()
    – Max Kanter
    Nov 20 at 14:45










  • Oh, you are right. My mistake.
    – Julian Peller
    Nov 20 at 14:48
















1














I have a dataframe as below



customerid                                   term   age
08a858899538ddb8e015390510b321f0830199897 30 24
18a858959537a097401537a4e316e25f730196361 60 72
a8589c253ace09b0153af6ba58f1f313019822366 45 38


I am creating an entity as below using featuretools



es = es.entity_from_dataframe(entity_id = 'cust', dataframe = df, index = 'customerid')


but i get the error



AssertionError: Index is not unique on dataframe (Entity cust)


yet customerid is the identifier










share|improve this question




















  • 1




    Is it possible that customerid is not unique? You can check if that is the case with len(es) == es.customerid.nunique() (if it's False, then you have repeated customerids).
    – Julian Peller
    Nov 20 at 14:15






  • 1




    @JulianPeller is right. You should run that check on the dataframe not the entityset though, so the code would be len(df) == df.customerid.nunique()
    – Max Kanter
    Nov 20 at 14:45










  • Oh, you are right. My mistake.
    – Julian Peller
    Nov 20 at 14:48














1












1








1







I have a dataframe as below



customerid                                   term   age
08a858899538ddb8e015390510b321f0830199897 30 24
18a858959537a097401537a4e316e25f730196361 60 72
a8589c253ace09b0153af6ba58f1f313019822366 45 38


I am creating an entity as below using featuretools



es = es.entity_from_dataframe(entity_id = 'cust', dataframe = df, index = 'customerid')


but i get the error



AssertionError: Index is not unique on dataframe (Entity cust)


yet customerid is the identifier










share|improve this question















I have a dataframe as below



customerid                                   term   age
08a858899538ddb8e015390510b321f0830199897 30 24
18a858959537a097401537a4e316e25f730196361 60 72
a8589c253ace09b0153af6ba58f1f313019822366 45 38


I am creating an entity as below using featuretools



es = es.entity_from_dataframe(entity_id = 'cust', dataframe = df, index = 'customerid')


but i get the error



AssertionError: Index is not unique on dataframe (Entity cust)


yet customerid is the identifier







python python-3.x feature-extraction featuretools






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 at 17:34









Max Kanter

1,10019




1,10019










asked Nov 20 at 12:27









Ian Okeyo

112




112








  • 1




    Is it possible that customerid is not unique? You can check if that is the case with len(es) == es.customerid.nunique() (if it's False, then you have repeated customerids).
    – Julian Peller
    Nov 20 at 14:15






  • 1




    @JulianPeller is right. You should run that check on the dataframe not the entityset though, so the code would be len(df) == df.customerid.nunique()
    – Max Kanter
    Nov 20 at 14:45










  • Oh, you are right. My mistake.
    – Julian Peller
    Nov 20 at 14:48














  • 1




    Is it possible that customerid is not unique? You can check if that is the case with len(es) == es.customerid.nunique() (if it's False, then you have repeated customerids).
    – Julian Peller
    Nov 20 at 14:15






  • 1




    @JulianPeller is right. You should run that check on the dataframe not the entityset though, so the code would be len(df) == df.customerid.nunique()
    – Max Kanter
    Nov 20 at 14:45










  • Oh, you are right. My mistake.
    – Julian Peller
    Nov 20 at 14:48








1




1




Is it possible that customerid is not unique? You can check if that is the case with len(es) == es.customerid.nunique() (if it's False, then you have repeated customerids).
– Julian Peller
Nov 20 at 14:15




Is it possible that customerid is not unique? You can check if that is the case with len(es) == es.customerid.nunique() (if it's False, then you have repeated customerids).
– Julian Peller
Nov 20 at 14:15




1




1




@JulianPeller is right. You should run that check on the dataframe not the entityset though, so the code would be len(df) == df.customerid.nunique()
– Max Kanter
Nov 20 at 14:45




@JulianPeller is right. You should run that check on the dataframe not the entityset though, so the code would be len(df) == df.customerid.nunique()
– Max Kanter
Nov 20 at 14:45












Oh, you are right. My mistake.
– Julian Peller
Nov 20 at 14:48




Oh, you are right. My mistake.
– Julian Peller
Nov 20 at 14:48

















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