Nsryjdtyk

Let me start by saying I've googled extensively for quite a few hours before asking this here, and I'm quite desperate if I've chosen to post here.

I have a few strings with the following format (approximated):

"firstword text ONE lastword"

"firstword text TWO lastword"

I need to extract the text after the 'firstword' and before 'ONE' or 'TWO'.

So my output for the aforementioned strings would have to be:

"text"

How do I split or partition the string so I can:

• remove the first word (I already know how to do this with str.split(' '))


• retain the text which comes before any of the 'ONE' or 'TWO'. (I thought it was supposed to look something like str.split('ONE' |
  'TWO'), but that obviously doesn't work and I haven't managed to find
  a solution right now.

If possible, I would like to solve it with split() or partition(), but regex would be fine as well.

Thank you for your help and sorry if this is a dumb question.

You can use this regex, which does a positive lookahead and positive lookbehind,

(?<=firstword)s*(.*?)s*(?=ONE|TWO)

Demo

Explanation:

• 
  (?<=firstword) --> Positive look behind to ensure the matched text is followed by firstword


• 
  s* --> Eats any white space


• 
  (.*?) --> Captures your intended data


• 
  s* --> Eats any white space


• 
  (?=ONE|TWO) --> Positive lookahead to ensure the matched text is followed by ONE or TWO

When you split it with space you have a list of all the words then you can choose which word you want :

s = "firstword text TWO lastword"

l = s.split(" ") # l = ["firstword" , "text" , "TWO" , "lastword"]

print l[1] # l[1] = "text"

or

s = "firstword text TWO lastword"

print s.split(" ")[1]

Try This

str_list = ["firstword text ONE lastword","firstword text TWO lastword","any text u entered before firstword text ONE","firstword text TWO any text After"]

end_key_lst = ['ONE','TWO']

print map(lambda x:x.split('firstword')[-1].strip(),[''.join(val.split(end_key)[:-1]) for val in str_list for i,end_key in enumerate(end_key_lst) if end_key in val.split()])



Result:['text', 'text', 'text', 'text']

How i do this:
May You have number of strings like those,So i kept them in list and Arrange Our End Keys like ONE,TWO in one list.
I use list Compression and Map function to get our desired target list.

You can use regex like:

import re

string = "firstword text TWO lastword"

re.search('firstwords+(w+)s+[ONE|TWO]', string).group(1)

'text'

Actually there's no need to use regex. You can store required separators into a list and then check if they exist.

orig_text = "firstword text ONE lastword"



first_separator = "firstword"

#Place all "end words" here

last_separators = ["ONE", "TWO"]



output = 



#Splitting the original text into list

orig_text = orig_text.split(" ")



#Checking if there's the "firstword" just in case

if first_separator in orig_text:

    #Here we check if there's "ONE" or "TWO" in the text

    for i in last_separators:

        if i in orig_text:

            #taking everything between "firstword" and "ONE"/"TWO"

            output = orig_text[orig_text.index(first_separator)+1 : orig_text.index(i)]

            break



#Converting to string

output = " ".join(output)



print(output)

Here's an example of outputs:

"firstword text TWO lastword" -> "text"

"firstword hello world ONE" -> "hello world"

"first text ONE" -> ""

"firstword text" -> ""