Nsryjdtyk

I was studying Java and I saw this example in a book:

int x=2, n=3;

    int result=1;

    for (int i=1; i<=n; i++)

        result*=x;

    System.out.println(result);

This calculates 2 to the power of 3. What I do not understand is how it does it in detail. I guess that for (int i=1; i<=n; i++) decides how many times int x=2 is going to be repeated, in this case, "3", then it gets int result=1 and multiply it by int x=2, and multiply int x=2 by itself three times. Maybe I am correct, but I do not understand how it happens, and why, as it is not possible to see the process step by step in the program (is it?). Could any one help me and tell what makes int x=2 repeat three times here, and how? And what exactly these expressions *= and result*=x; do? I saw everywhere that a*=b is the same as a=a*b, but it does not explain much how it works and in which cases I should use it, and I would really like to understand it, to know how to use it in future, in the case of I need to create a program and it may help me.

In this loop:

for (int i=1; i<=n; i++)

    result*=x;

i is not used, and we know that n=3, so we could rewrite the code as:

int x = 2

int result = 1;

result *= x; // result is 2

result *= x; // result is 4

result *= x; // result is 8

System.out.println(result);

Regarding a*=b being the same as a=a*b, it's not exactly the same, but close enough. a*=b is the same as a=a*(typeOfA)b where (typeOfA) is a cast to the type of a, eg a=a*(int)b. This rarely causes a different result because usually the types of a and b are the same, but may have an effect due to the java's automatic widening/casting when types of a and b differ.

Let's take it step by step:

int x=2, n=3;

int result=1;

These two lines could be simplified at most into:

int x;

int n;

int result;

x = 2;

n = 3;

result = 1;

The int constructs (e.g. int x) define a variable of type int (e.g. x). This means x can hold an integer number.

Then the x = 2 construct sets the value of x to 2.

Doing int x=2 is a short form for that.

You're able to define and set more than one variable using the int x=2, n=3 construct as a shorthand.

The for-loop, here with curly braces to mark the beginning and end of the block (the part of code repeating in the for-loop):

for (int i=1; i<=n; i++) {

    result*=x;

}

Using no curly braces means repeat the next ONE instruction.

As you pointed out yourself, the for clause loops three times.

The loop consists of the following segments:

for ([variable instantiations]; [condition]; [loop instruction])

The variable instantiations can (but does not have to) be used for setting up variables, usually a single variable to use as the index of the loop. In your case a new instantiation of a variable i with the value 1.

The loop condition is used to test if the loop should continue. As long as this statement is true, the loop will. In your case a test is made of i against n. As long as i is less than or equal to (<=) n the loop continues.

The final loop instruction is a bit of code that will be performed once for each loop. In your case it will increment (++) i with one. (i++ is equivalent to i = i + 1).

The instruction in the for-loop, result *= x means that result will be multiplied by x (2) and the result will be stored back in result (i.e. result = result * 2)

Finally, the result will be printed to the console:

System.out.println(result);

If I'm not completely mistaken you should get: 8.