Is there any way to make the execution faster in the below Java code?












0












$begingroup$


My Java code is as below.



boolean almostIncreasingSequence(int sequence) {

Integer arr = new Integer[sequence.length];

for(int ctr = 0; ctr < sequence.length; ctr++) {
arr[ctr] = Integer.valueOf(sequence[ctr]); // returns Integer value
}
System.out.println("Integer :: " + arr);
List<Integer> al = new ArrayList<Integer>();

// adding elements of array to arrayList.
Collections.addAll(al, arr);
System.out.println("list :: " + al);
int save, flag = 0;
for(int i=0; i<al.size(); i++) {
save = al.get(i);
al.remove(i);
if(al.size()==1) return true;
for(int j=0; j<al.size()-1; j++) {
if(al.get(j+1) > al.get(j)) {
flag = 0;
continue;
}
else {
flag = 1;
break;
}
}
if(flag == 0) {
return true;
}
al.add(i,save);
}

if(flag == 1)
return false;
return true;
}


The code is for a Problem "Given a sequence of integers as an array, determine whether it is possible to obtain a strictly increasing sequence by removing no more than one element from the array."



For some of the test cases, it shows that it takes more than 3 seconds to execute this. But, I'm not sure where can I make a change to execute it faster. I don't have access to the test case.



Here, I have created 2 for loops because in the first loop I'm generating the list where each index will be removed and in the second loop I'm iterating over the new list which has removed the element.



like sample array is {1,2,4,3} then in the first loop I'm creating an array which will be {2,4,3},{1,4,3},{1,2,3} and {1,2,4}. In the second loop I'm iterating over all these 4 arrays to compare each element.









share







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    0












    $begingroup$


    My Java code is as below.



    boolean almostIncreasingSequence(int sequence) {

    Integer arr = new Integer[sequence.length];

    for(int ctr = 0; ctr < sequence.length; ctr++) {
    arr[ctr] = Integer.valueOf(sequence[ctr]); // returns Integer value
    }
    System.out.println("Integer :: " + arr);
    List<Integer> al = new ArrayList<Integer>();

    // adding elements of array to arrayList.
    Collections.addAll(al, arr);
    System.out.println("list :: " + al);
    int save, flag = 0;
    for(int i=0; i<al.size(); i++) {
    save = al.get(i);
    al.remove(i);
    if(al.size()==1) return true;
    for(int j=0; j<al.size()-1; j++) {
    if(al.get(j+1) > al.get(j)) {
    flag = 0;
    continue;
    }
    else {
    flag = 1;
    break;
    }
    }
    if(flag == 0) {
    return true;
    }
    al.add(i,save);
    }

    if(flag == 1)
    return false;
    return true;
    }


    The code is for a Problem "Given a sequence of integers as an array, determine whether it is possible to obtain a strictly increasing sequence by removing no more than one element from the array."



    For some of the test cases, it shows that it takes more than 3 seconds to execute this. But, I'm not sure where can I make a change to execute it faster. I don't have access to the test case.



    Here, I have created 2 for loops because in the first loop I'm generating the list where each index will be removed and in the second loop I'm iterating over the new list which has removed the element.



    like sample array is {1,2,4,3} then in the first loop I'm creating an array which will be {2,4,3},{1,4,3},{1,2,3} and {1,2,4}. In the second loop I'm iterating over all these 4 arrays to compare each element.









    share







    New contributor




    Virus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$















      0












      0








      0





      $begingroup$


      My Java code is as below.



      boolean almostIncreasingSequence(int sequence) {

      Integer arr = new Integer[sequence.length];

      for(int ctr = 0; ctr < sequence.length; ctr++) {
      arr[ctr] = Integer.valueOf(sequence[ctr]); // returns Integer value
      }
      System.out.println("Integer :: " + arr);
      List<Integer> al = new ArrayList<Integer>();

      // adding elements of array to arrayList.
      Collections.addAll(al, arr);
      System.out.println("list :: " + al);
      int save, flag = 0;
      for(int i=0; i<al.size(); i++) {
      save = al.get(i);
      al.remove(i);
      if(al.size()==1) return true;
      for(int j=0; j<al.size()-1; j++) {
      if(al.get(j+1) > al.get(j)) {
      flag = 0;
      continue;
      }
      else {
      flag = 1;
      break;
      }
      }
      if(flag == 0) {
      return true;
      }
      al.add(i,save);
      }

      if(flag == 1)
      return false;
      return true;
      }


      The code is for a Problem "Given a sequence of integers as an array, determine whether it is possible to obtain a strictly increasing sequence by removing no more than one element from the array."



      For some of the test cases, it shows that it takes more than 3 seconds to execute this. But, I'm not sure where can I make a change to execute it faster. I don't have access to the test case.



      Here, I have created 2 for loops because in the first loop I'm generating the list where each index will be removed and in the second loop I'm iterating over the new list which has removed the element.



      like sample array is {1,2,4,3} then in the first loop I'm creating an array which will be {2,4,3},{1,4,3},{1,2,3} and {1,2,4}. In the second loop I'm iterating over all these 4 arrays to compare each element.









      share







      New contributor




      Virus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      My Java code is as below.



      boolean almostIncreasingSequence(int sequence) {

      Integer arr = new Integer[sequence.length];

      for(int ctr = 0; ctr < sequence.length; ctr++) {
      arr[ctr] = Integer.valueOf(sequence[ctr]); // returns Integer value
      }
      System.out.println("Integer :: " + arr);
      List<Integer> al = new ArrayList<Integer>();

      // adding elements of array to arrayList.
      Collections.addAll(al, arr);
      System.out.println("list :: " + al);
      int save, flag = 0;
      for(int i=0; i<al.size(); i++) {
      save = al.get(i);
      al.remove(i);
      if(al.size()==1) return true;
      for(int j=0; j<al.size()-1; j++) {
      if(al.get(j+1) > al.get(j)) {
      flag = 0;
      continue;
      }
      else {
      flag = 1;
      break;
      }
      }
      if(flag == 0) {
      return true;
      }
      al.add(i,save);
      }

      if(flag == 1)
      return false;
      return true;
      }


      The code is for a Problem "Given a sequence of integers as an array, determine whether it is possible to obtain a strictly increasing sequence by removing no more than one element from the array."



      For some of the test cases, it shows that it takes more than 3 seconds to execute this. But, I'm not sure where can I make a change to execute it faster. I don't have access to the test case.



      Here, I have created 2 for loops because in the first loop I'm generating the list where each index will be removed and in the second loop I'm iterating over the new list which has removed the element.



      like sample array is {1,2,4,3} then in the first loop I'm creating an array which will be {2,4,3},{1,4,3},{1,2,3} and {1,2,4}. In the second loop I'm iterating over all these 4 arrays to compare each element.







      java performance





      share







      New contributor




      Virus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      Virus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






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      asked 9 mins ago









      VirusVirus

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      Virus is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






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