In terraform, is it possible to only add an optional resource argument if a particular variable is set
On my concrete example:
I want to create a rancher environment resource with preconfigured members. But the number of members is supposed to be depending on a variable list. I'd imaging something like
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member {
count = "${length(var.memberlist)}"
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
This obviously doesn't work. Is there a trick to achieve this behaviour?
terraform rancher
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
add a comment |
On my concrete example:
I want to create a rancher environment resource with preconfigured members. But the number of members is supposed to be depending on a variable list. I'd imaging something like
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member {
count = "${length(var.memberlist)}"
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
This obviously doesn't work. Is there a trick to achieve this behaviour?
terraform rancher
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
add a comment |
On my concrete example:
I want to create a rancher environment resource with preconfigured members. But the number of members is supposed to be depending on a variable list. I'd imaging something like
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member {
count = "${length(var.memberlist)}"
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
This obviously doesn't work. Is there a trick to achieve this behaviour?
terraform rancher
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
On my concrete example:
I want to create a rancher environment resource with preconfigured members. But the number of members is supposed to be depending on a variable list. I'd imaging something like
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member {
count = "${length(var.memberlist)}"
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
This obviously doesn't work. Is there a trick to achieve this behaviour?
terraform rancher
terraform rancher
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
edited Nov 22 '18 at 12:54
Vít Kotačka
474420
474420
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
asked Nov 21 '18 at 23:50
LeoRLeoR
478416
478416
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You can use null_resource for this. Try this
resource "null_resource" "memberlist" {
count = "${length(var.memberlist)}"
triggers {
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member = ["${null_resource.memberlist.*.triggers}"]
}
answered Nov 22 '18 at 8:46
RamRam
385112
add a comment |
At long last, Terraform has just released v0.12.0-alpha1, which contains a more elegant way of solving this exact problem.
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use null_resource for this. Try this
resource "null_resource" "memberlist" {
count = "${length(var.memberlist)}"
triggers {
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member = ["${null_resource.memberlist.*.triggers}"]
}
answered Nov 22 '18 at 8:46
RamRam
385112
add a comment |
You can use null_resource for this. Try this
resource "null_resource" "memberlist" {
count = "${length(var.memberlist)}"
triggers {
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member = ["${null_resource.memberlist.*.triggers}"]
}
answered Nov 22 '18 at 8:46
RamRam
385112
add a comment |
You can use null_resource for this. Try this
resource "null_resource" "memberlist" {
count = "${length(var.memberlist)}"
triggers {
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member = ["${null_resource.memberlist.*.triggers}"]
}
answered Nov 22 '18 at 8:46
RamRam
385112
You can use null_resource for this. Try this
resource "null_resource" "memberlist" {
count = "${length(var.memberlist)}"
triggers {
external_id = "${var.memberlist[count.index]}"
external_id_type = "exttype"
role = "owner"
}
}
resource "rancher_environment" "renv" {
name = "renv"
project_template_id = "atmplid"
member = ["${null_resource.memberlist.*.triggers}"]
}
answered Nov 22 '18 at 8:46
RamRam
385112
answered Nov 22 '18 at 8:46
RamRam
385112
answered Nov 22 '18 at 8:46
RamRam
385112
answered Nov 22 '18 at 8:46
RamRam
385112
385112
add a comment |
add a comment |
At long last, Terraform has just released v0.12.0-alpha1, which contains a more elegant way of solving this exact problem.
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
add a comment |
At long last, Terraform has just released v0.12.0-alpha1, which contains a more elegant way of solving this exact problem.
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
add a comment |
At long last, Terraform has just released v0.12.0-alpha1, which contains a more elegant way of solving this exact problem.
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
At long last, Terraform has just released v0.12.0-alpha1, which contains a more elegant way of solving this exact problem.
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
answered Dec 3 '18 at 16:05
TiemenTiemen
29116
29116
add a comment |
add a comment |
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