JavaScript multiple keydown












0














First, I would like to thank all for your help and replies.



I'm working on a project that required users to press a key and hold it, it will trigger an action.



When the user presses another key ( still holing the first key), it will trigger another action.



However, I'm stuck getting JavaScript to recognize two keys being pressed at the same time.






var down = false;
var keys;

document.addEventListener("keydown", function (e) {
if (down) {return;}
down = true;
keys = (keys || );
keys[e.keyCode]=true;
if (keys[87]){
console.log("1");

}
else if (keys[83]){
console.log("2");
}
else if (keys[83] && keys[87]){
console.log("sucessfull");
}
} , false);

document.addEventListener("keyup", function (e) {
down = false;
keys[e.keyCode]=false;
stop();
}, false);

<button id="up" onmousedown="Drive(1)" onmouseup="Drive(2)">UP </button>












share|improve this question
























  • When your second keydown event is received, the down boolean will be true and the function will immediately return. It looks like if you remove the down variable (and associated checks/returns) your code might achieve what you want it to already.
    – dave
    Nov 21 '18 at 5:15
















0














First, I would like to thank all for your help and replies.



I'm working on a project that required users to press a key and hold it, it will trigger an action.



When the user presses another key ( still holing the first key), it will trigger another action.



However, I'm stuck getting JavaScript to recognize two keys being pressed at the same time.






var down = false;
var keys;

document.addEventListener("keydown", function (e) {
if (down) {return;}
down = true;
keys = (keys || );
keys[e.keyCode]=true;
if (keys[87]){
console.log("1");

}
else if (keys[83]){
console.log("2");
}
else if (keys[83] && keys[87]){
console.log("sucessfull");
}
} , false);

document.addEventListener("keyup", function (e) {
down = false;
keys[e.keyCode]=false;
stop();
}, false);

<button id="up" onmousedown="Drive(1)" onmouseup="Drive(2)">UP </button>












share|improve this question
























  • When your second keydown event is received, the down boolean will be true and the function will immediately return. It looks like if you remove the down variable (and associated checks/returns) your code might achieve what you want it to already.
    – dave
    Nov 21 '18 at 5:15














0












0








0







First, I would like to thank all for your help and replies.



I'm working on a project that required users to press a key and hold it, it will trigger an action.



When the user presses another key ( still holing the first key), it will trigger another action.



However, I'm stuck getting JavaScript to recognize two keys being pressed at the same time.






var down = false;
var keys;

document.addEventListener("keydown", function (e) {
if (down) {return;}
down = true;
keys = (keys || );
keys[e.keyCode]=true;
if (keys[87]){
console.log("1");

}
else if (keys[83]){
console.log("2");
}
else if (keys[83] && keys[87]){
console.log("sucessfull");
}
} , false);

document.addEventListener("keyup", function (e) {
down = false;
keys[e.keyCode]=false;
stop();
}, false);

<button id="up" onmousedown="Drive(1)" onmouseup="Drive(2)">UP </button>












share|improve this question















First, I would like to thank all for your help and replies.



I'm working on a project that required users to press a key and hold it, it will trigger an action.



When the user presses another key ( still holing the first key), it will trigger another action.



However, I'm stuck getting JavaScript to recognize two keys being pressed at the same time.






var down = false;
var keys;

document.addEventListener("keydown", function (e) {
if (down) {return;}
down = true;
keys = (keys || );
keys[e.keyCode]=true;
if (keys[87]){
console.log("1");

}
else if (keys[83]){
console.log("2");
}
else if (keys[83] && keys[87]){
console.log("sucessfull");
}
} , false);

document.addEventListener("keyup", function (e) {
down = false;
keys[e.keyCode]=false;
stop();
}, false);

<button id="up" onmousedown="Drive(1)" onmouseup="Drive(2)">UP </button>








var down = false;
var keys;

document.addEventListener("keydown", function (e) {
if (down) {return;}
down = true;
keys = (keys || );
keys[e.keyCode]=true;
if (keys[87]){
console.log("1");

}
else if (keys[83]){
console.log("2");
}
else if (keys[83] && keys[87]){
console.log("sucessfull");
}
} , false);

document.addEventListener("keyup", function (e) {
down = false;
keys[e.keyCode]=false;
stop();
}, false);

<button id="up" onmousedown="Drive(1)" onmouseup="Drive(2)">UP </button>





var down = false;
var keys;

document.addEventListener("keydown", function (e) {
if (down) {return;}
down = true;
keys = (keys || );
keys[e.keyCode]=true;
if (keys[87]){
console.log("1");

}
else if (keys[83]){
console.log("2");
}
else if (keys[83] && keys[87]){
console.log("sucessfull");
}
} , false);

document.addEventListener("keyup", function (e) {
down = false;
keys[e.keyCode]=false;
stop();
}, false);

<button id="up" onmousedown="Drive(1)" onmouseup="Drive(2)">UP </button>






javascript html onkeydown






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share|improve this question













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share|improve this question








edited Nov 21 '18 at 5:27









Foo

1




1










asked Nov 21 '18 at 3:56









Vu Vo

265




265












  • When your second keydown event is received, the down boolean will be true and the function will immediately return. It looks like if you remove the down variable (and associated checks/returns) your code might achieve what you want it to already.
    – dave
    Nov 21 '18 at 5:15


















  • When your second keydown event is received, the down boolean will be true and the function will immediately return. It looks like if you remove the down variable (and associated checks/returns) your code might achieve what you want it to already.
    – dave
    Nov 21 '18 at 5:15
















When your second keydown event is received, the down boolean will be true and the function will immediately return. It looks like if you remove the down variable (and associated checks/returns) your code might achieve what you want it to already.
– dave
Nov 21 '18 at 5:15




When your second keydown event is received, the down boolean will be true and the function will immediately return. It looks like if you remove the down variable (and associated checks/returns) your code might achieve what you want it to already.
– dave
Nov 21 '18 at 5:15












1 Answer
1






active

oldest

votes


















1















  1. Removed the 'down' variable checks

  2. Removed the mouse button element thing - didn't seem relevant to your problem?

  3. Removed the extra HTML body


  4. Got rid of the else branching as it would be satisfied (by 87 or 83) before ever getting to the && condition



        var keys;

    document.addEventListener("keydown", function (e) {
    keys = (keys || );
    keys[e.keyCode]=true;
    if (keys[87]){
    console.log("1");

    }

    if (keys[83]){
    console.log("2");
    }

    if (keys[83] && keys[87]){
    console.log("sucessfull");
    }
    } , false);

    document.addEventListener("keyup", function (e) {
    keys[e.keyCode]=false;
    stop();
    }, false);







share|improve this answer





















  • The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
    – Vu Vo
    Nov 21 '18 at 9:37













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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1















  1. Removed the 'down' variable checks

  2. Removed the mouse button element thing - didn't seem relevant to your problem?

  3. Removed the extra HTML body


  4. Got rid of the else branching as it would be satisfied (by 87 or 83) before ever getting to the && condition



        var keys;

    document.addEventListener("keydown", function (e) {
    keys = (keys || );
    keys[e.keyCode]=true;
    if (keys[87]){
    console.log("1");

    }

    if (keys[83]){
    console.log("2");
    }

    if (keys[83] && keys[87]){
    console.log("sucessfull");
    }
    } , false);

    document.addEventListener("keyup", function (e) {
    keys[e.keyCode]=false;
    stop();
    }, false);







share|improve this answer





















  • The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
    – Vu Vo
    Nov 21 '18 at 9:37


















1















  1. Removed the 'down' variable checks

  2. Removed the mouse button element thing - didn't seem relevant to your problem?

  3. Removed the extra HTML body


  4. Got rid of the else branching as it would be satisfied (by 87 or 83) before ever getting to the && condition



        var keys;

    document.addEventListener("keydown", function (e) {
    keys = (keys || );
    keys[e.keyCode]=true;
    if (keys[87]){
    console.log("1");

    }

    if (keys[83]){
    console.log("2");
    }

    if (keys[83] && keys[87]){
    console.log("sucessfull");
    }
    } , false);

    document.addEventListener("keyup", function (e) {
    keys[e.keyCode]=false;
    stop();
    }, false);







share|improve this answer





















  • The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
    – Vu Vo
    Nov 21 '18 at 9:37
















1












1








1







  1. Removed the 'down' variable checks

  2. Removed the mouse button element thing - didn't seem relevant to your problem?

  3. Removed the extra HTML body


  4. Got rid of the else branching as it would be satisfied (by 87 or 83) before ever getting to the && condition



        var keys;

    document.addEventListener("keydown", function (e) {
    keys = (keys || );
    keys[e.keyCode]=true;
    if (keys[87]){
    console.log("1");

    }

    if (keys[83]){
    console.log("2");
    }

    if (keys[83] && keys[87]){
    console.log("sucessfull");
    }
    } , false);

    document.addEventListener("keyup", function (e) {
    keys[e.keyCode]=false;
    stop();
    }, false);







share|improve this answer













  1. Removed the 'down' variable checks

  2. Removed the mouse button element thing - didn't seem relevant to your problem?

  3. Removed the extra HTML body


  4. Got rid of the else branching as it would be satisfied (by 87 or 83) before ever getting to the && condition



        var keys;

    document.addEventListener("keydown", function (e) {
    keys = (keys || );
    keys[e.keyCode]=true;
    if (keys[87]){
    console.log("1");

    }

    if (keys[83]){
    console.log("2");
    }

    if (keys[83] && keys[87]){
    console.log("sucessfull");
    }
    } , false);

    document.addEventListener("keyup", function (e) {
    keys[e.keyCode]=false;
    stop();
    }, false);








share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 21 '18 at 5:23









dave

5341515




5341515












  • The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
    – Vu Vo
    Nov 21 '18 at 9:37




















  • The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
    – Vu Vo
    Nov 21 '18 at 9:37


















The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
– Vu Vo
Nov 21 '18 at 9:37






The reason why I add boolean there because I don't want HTML to repeat action when holding a key.
– Vu Vo
Nov 21 '18 at 9:37




















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