Here is an excerpt from my code:

begin{tikzpicture}[scale=5.5]

    coordinate[label=left:$A$]  (A) at (0,0);

    coordinate[label=right:$B$]  (B) at (1,0);

    coordinate[label=:$C$]  (C) at (0.5,0.866);

    draw (A)--(B)--(C)--(A);

    end{tikzpicture}

I want to denote AB=BC using the tick mark notation. Also, point C isn't exactly where it should be. How can I fix that? I rounded sqrt(3)/2 to 0.866.

A PSTricks solution just for fun purposes.

documentclass[pstricks,12pt,border=1cm]{standalone}

usepackage{pst-eucl}

begin{document}

pspicture[MarkAngle=90](-4,4)

    pstTriangle(4;150){C}(-4,0){A}(0,0){B}

    pstSegmentMark{A}{B}

    pstSegmentMark{B}{C}

endpspicture

end{document}

Bonus

documentclass[pstricks,12pt,border=1cm]{standalone}

usepackage{pst-eucl}

begin{document}

foreach i in {90,100,...,170}{%

pspicture[MarkAngle=90](-4,4)

    pstTriangle(4;i){C}(-4,0){A}(0,0){B}

    pstSegmentMark{A}{B}

    pstSegmentMark{B}{C}

endpspicture}

end{document}

Welcome to TeX.SE! You can add these marks with decorations.markings. Since you want two of them, it is shorter to use the .list key for that. Further, TikZ understands polar coordinates, and it also understands (0.5,{sqrt(3)/2}), so there is no need to unbury your calculator. ;-)

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{decorations.markings}

begin{document}

begin{tikzpicture}[scale=5.5,equal mark/.style={postaction={decorate,

decoration={markings,mark=at position #1 with {draw (-2pt,-4pt) -- (-2pt,4pt);

draw (2pt,-4pt) -- (2pt,4pt);}}}}]

    coordinate[label=left:$A$]  (A) at (0,0);

    coordinate[label=right:$B$]  (B) at (1,0);

    coordinate[label=:$C$]  (C) at (60:1);

    draw[equal mark/.list={1/6,1/2}] (A)--(B)--(C)--cycle;

end{tikzpicture}

end{document}  

As you can see, this code starts with documentclass and ends with end{document}, and is compilable. Kurt asked you in his comment to add such a code.

And you may simplify/shorten the code using a foreach loop.

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{decorations.markings}

begin{document}

begin{tikzpicture}[scale=5.5,equal mark/.style={postaction={decorate,

decoration={markings,mark=at position #1 with {draw (-2pt,-4pt) -- (-2pt,4pt);

draw (2pt,-4pt) -- (2pt,4pt);}}}}]

    foreach X/Y in {210/A,-30/B,90/C} 

    {coordinate[label=X:$Y$]  (Y) at (X:{1/sqrt(3)});}

    draw[equal mark/.list={1/6,1/2,5/6}] (A)--(B)--(C)--cycle;

end{tikzpicture}

end{document}  

one more tikz solution:

documentclass[tikz,border=3.141592mm]{standalone}



begin{document}

    begin{tikzpicture}[scale=5.5]

coordinate[label=left:$A$]     (A) at (0,0);

coordinate[label=right:$B$]    (B) at (1,0);

coordinate[label=$C$]          (C) at (0.5,0.866);

draw (A) -- node {$|$} (B) -- node[sloped] {$|$} (C) -- (A);

    end{tikzpicture}

end{document}

(not tested since my tikz is broken :-( )