Jquery on click hide the next added element
I have a button, which on every click gives the dropdown element.
Now i need to add the check box above the dropdown - which i have done, but this checkbox element should appear only for the first time.
The problem is , on every click, i get both dropdown associated with checkbox like below.
I need checkbox only for the 1st time button click- along with dropdown.
SO for the 2nd time button click, i tried to hide the checkbox, but the previous checkbox is getting hidden.
public function getPreferenceKeysAction() {
....
<div style="margin:2px 0px 15px 0px;">
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Registered Users</input><br>
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Opted Users</input><br>
}
in JS
$(add_button).click(function(e){ //on add input button click
if($("#mydd").length){
alert("The element you're testing is present.");
$("#mydd").hide();
}
else{
alert("NOt present.");
}
});
javascript php jquery html
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
add a comment |
I have a button, which on every click gives the dropdown element.
Now i need to add the check box above the dropdown - which i have done, but this checkbox element should appear only for the first time.
The problem is , on every click, i get both dropdown associated with checkbox like below.
I need checkbox only for the 1st time button click- along with dropdown.
SO for the 2nd time button click, i tried to hide the checkbox, but the previous checkbox is getting hidden.
public function getPreferenceKeysAction() {
....
<div style="margin:2px 0px 15px 0px;">
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Registered Users</input><br>
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Opted Users</input><br>
}
in JS
$(add_button).click(function(e){ //on add input button click
if($("#mydd").length){
alert("The element you're testing is present.");
$("#mydd").hide();
}
else{
alert("NOt present.");
}
});
javascript php jquery html
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
Do you use this presented JS code to find the problem or is a part of your codes?
– Ali Sheikhpour
Nov 24 '18 at 12:50
add a comment |
I have a button, which on every click gives the dropdown element.
Now i need to add the check box above the dropdown - which i have done, but this checkbox element should appear only for the first time.
The problem is , on every click, i get both dropdown associated with checkbox like below.
I need checkbox only for the 1st time button click- along with dropdown.
SO for the 2nd time button click, i tried to hide the checkbox, but the previous checkbox is getting hidden.
public function getPreferenceKeysAction() {
....
<div style="margin:2px 0px 15px 0px;">
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Registered Users</input><br>
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Opted Users</input><br>
}
in JS
$(add_button).click(function(e){ //on add input button click
if($("#mydd").length){
alert("The element you're testing is present.");
$("#mydd").hide();
}
else{
alert("NOt present.");
}
});
javascript php jquery html
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
I have a button, which on every click gives the dropdown element.
Now i need to add the check box above the dropdown - which i have done, but this checkbox element should appear only for the first time.
The problem is , on every click, i get both dropdown associated with checkbox like below.
I need checkbox only for the 1st time button click- along with dropdown.
SO for the 2nd time button click, i tried to hide the checkbox, but the previous checkbox is getting hidden.
public function getPreferenceKeysAction() {
....
<div style="margin:2px 0px 15px 0px;">
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Registered Users</input><br>
<input id = "mydd" type="checkbox" name="vehicle1" value="RegisteredUsers"> Opted Users</input><br>
}
in JS
$(add_button).click(function(e){ //on add input button click
if($("#mydd").length){
alert("The element you're testing is present.");
$("#mydd").hide();
}
else{
alert("NOt present.");
}
});
javascript php jquery html
javascript php jquery html
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
asked Nov 24 '18 at 12:40
SushivamSushivam
2411416
2411416
Do you use this presented JS code to find the problem or is a part of your codes?
– Ali Sheikhpour
Nov 24 '18 at 12:50
add a comment |
Do you use this presented JS code to find the problem or is a part of your codes?
– Ali Sheikhpour
Nov 24 '18 at 12:50
Do you use this presented JS code to find the problem or is a part of your codes?
– Ali Sheikhpour
Nov 24 '18 at 12:50
Do you use this presented JS code to find the problem or is a part of your codes?
– Ali Sheikhpour
Nov 24 '18 at 12:50
add a comment |
2 Answers
2
active
oldest
votes
Why not add a class to the element or a data attribute.
With jQuery both are easy to achive.
If you want to use a class just change data method to hasClass and addClass
just do a
$btn = $(this);
// Check if the element has data attribute used
if ( $btn.data('used') != 'true' ) {
// Add data attribute used to element
$btn.data('used', 'true')
// Do whats needed for the first time it's clicked.
} else {
// The element has been used already
}
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
add a comment |
Change you id="mydd" to class="mydd", you should use id with a unique value, doing that you can hide the elements skipping 2 of them, like this.
$('.mydd').slice(2).hide();
If you want to hide the div wrapping your checkbox, add .parent()
$('.mydd').parent().slice(1).hide();
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Why not add a class to the element or a data attribute.
With jQuery both are easy to achive.
If you want to use a class just change data method to hasClass and addClass
just do a
$btn = $(this);
// Check if the element has data attribute used
if ( $btn.data('used') != 'true' ) {
// Add data attribute used to element
$btn.data('used', 'true')
// Do whats needed for the first time it's clicked.
} else {
// The element has been used already
}
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
add a comment |
Why not add a class to the element or a data attribute.
With jQuery both are easy to achive.
If you want to use a class just change data method to hasClass and addClass
just do a
$btn = $(this);
// Check if the element has data attribute used
if ( $btn.data('used') != 'true' ) {
// Add data attribute used to element
$btn.data('used', 'true')
// Do whats needed for the first time it's clicked.
} else {
// The element has been used already
}
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
add a comment |
Why not add a class to the element or a data attribute.
With jQuery both are easy to achive.
If you want to use a class just change data method to hasClass and addClass
just do a
$btn = $(this);
// Check if the element has data attribute used
if ( $btn.data('used') != 'true' ) {
// Add data attribute used to element
$btn.data('used', 'true')
// Do whats needed for the first time it's clicked.
} else {
// The element has been used already
}
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
Why not add a class to the element or a data attribute.
With jQuery both are easy to achive.
If you want to use a class just change data method to hasClass and addClass
just do a
$btn = $(this);
// Check if the element has data attribute used
if ( $btn.data('used') != 'true' ) {
// Add data attribute used to element
$btn.data('used', 'true')
// Do whats needed for the first time it's clicked.
} else {
// The element has been used already
}
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
edited Nov 24 '18 at 12:55
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
answered Nov 24 '18 at 12:47
Robin JohanssonRobin Johansson
657
657
add a comment |
add a comment |
Change you id="mydd" to class="mydd", you should use id with a unique value, doing that you can hide the elements skipping 2 of them, like this.
$('.mydd').slice(2).hide();
If you want to hide the div wrapping your checkbox, add .parent()
$('.mydd').parent().slice(1).hide();
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
add a comment |
Change you id="mydd" to class="mydd", you should use id with a unique value, doing that you can hide the elements skipping 2 of them, like this.
$('.mydd').slice(2).hide();
If you want to hide the div wrapping your checkbox, add .parent()
$('.mydd').parent().slice(1).hide();
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
add a comment |
Change you id="mydd" to class="mydd", you should use id with a unique value, doing that you can hide the elements skipping 2 of them, like this.
$('.mydd').slice(2).hide();
If you want to hide the div wrapping your checkbox, add .parent()
$('.mydd').parent().slice(1).hide();
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
Change you id="mydd" to class="mydd", you should use id with a unique value, doing that you can hide the elements skipping 2 of them, like this.
$('.mydd').slice(2).hide();
If you want to hide the div wrapping your checkbox, add .parent()
$('.mydd').parent().slice(1).hide();
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
answered Nov 24 '18 at 13:44
Gustavo PereiraGustavo Pereira
12
12
add a comment |
add a comment |
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Do you use this presented JS code to find the problem or is a part of your codes?
– Ali Sheikhpour
Nov 24 '18 at 12:50