Merge two arrays in R alternating their elements
Suppose I have two arrays of the same length (e.g. 1000), array1 and array2, that look like
array 1= 0.7828479 0.7782587 0.697296 0.7847533 0.7963145 0.7742886 0.6367928 ...
array 2= 0.5324373 -0.5765472 -0.5020422 -0.3265736 -0.09438474 0.1368133 ...
and I want to merge them into a new array that looks like:
first 20 elements of array 1 (i.e. array1[1], array1[2],...,array1[20])
first 10 elements of array 2 (i.e. array2[1], array2[2],...,array2[10])
second 20 elements of array 1 (i.e. array1[21], array1[2],...,array1[40])
second 10 elements of array 2 (i.e. array2[11], array2[2],...,array2[20])
and so on, until all the elements of one of the arrays had been used up. Then array1 will always be used up first and the resulting vector will have 20 and 10 consecutive items from array 1 and 2 respectively each time.
arrays r merge
asked Nov 26 '18 at 11:36
MarkMark
244215
add a comment |
Suppose I have two arrays of the same length (e.g. 1000), array1 and array2, that look like
array 1= 0.7828479 0.7782587 0.697296 0.7847533 0.7963145 0.7742886 0.6367928 ...
array 2= 0.5324373 -0.5765472 -0.5020422 -0.3265736 -0.09438474 0.1368133 ...
and I want to merge them into a new array that looks like:
first 20 elements of array 1 (i.e. array1[1], array1[2],...,array1[20])
first 10 elements of array 2 (i.e. array2[1], array2[2],...,array2[10])
second 20 elements of array 1 (i.e. array1[21], array1[2],...,array1[40])
second 10 elements of array 2 (i.e. array2[11], array2[2],...,array2[20])
and so on, until all the elements of one of the arrays had been used up. Then array1 will always be used up first and the resulting vector will have 20 and 10 consecutive items from array 1 and 2 respectively each time.
arrays r merge
asked Nov 26 '18 at 11:36
MarkMark
244215
2
Can you clarify this more? do you mean vector or (multidimensional) array? I am also not sure what you mean by "and so on"; do you mean 20 and 10 consecutive items from array 1 and 2 respectively each time? Then array 1 will always be used up first, right? (you mentioned they are equal length)
– MartijnVanAttekum
Nov 26 '18 at 11:47
@MartijnVanAttekum, thanks for the questions. I've edited my post
– Mark
Nov 26 '18 at 11:59
add a comment |
Suppose I have two arrays of the same length (e.g. 1000), array1 and array2, that look like
array 1= 0.7828479 0.7782587 0.697296 0.7847533 0.7963145 0.7742886 0.6367928 ...
array 2= 0.5324373 -0.5765472 -0.5020422 -0.3265736 -0.09438474 0.1368133 ...
and I want to merge them into a new array that looks like:
first 20 elements of array 1 (i.e. array1[1], array1[2],...,array1[20])
first 10 elements of array 2 (i.e. array2[1], array2[2],...,array2[10])
second 20 elements of array 1 (i.e. array1[21], array1[2],...,array1[40])
second 10 elements of array 2 (i.e. array2[11], array2[2],...,array2[20])
and so on, until all the elements of one of the arrays had been used up. Then array1 will always be used up first and the resulting vector will have 20 and 10 consecutive items from array 1 and 2 respectively each time.
arrays r merge
asked Nov 26 '18 at 11:36
MarkMark
244215
Suppose I have two arrays of the same length (e.g. 1000), array1 and array2, that look like
array 1= 0.7828479 0.7782587 0.697296 0.7847533 0.7963145 0.7742886 0.6367928 ...
array 2= 0.5324373 -0.5765472 -0.5020422 -0.3265736 -0.09438474 0.1368133 ...
and I want to merge them into a new array that looks like:
first 20 elements of array 1 (i.e. array1[1], array1[2],...,array1[20])
first 10 elements of array 2 (i.e. array2[1], array2[2],...,array2[10])
second 20 elements of array 1 (i.e. array1[21], array1[2],...,array1[40])
second 10 elements of array 2 (i.e. array2[11], array2[2],...,array2[20])
and so on, until all the elements of one of the arrays had been used up. Then array1 will always be used up first and the resulting vector will have 20 and 10 consecutive items from array 1 and 2 respectively each time.
arrays r merge
arrays r merge
asked Nov 26 '18 at 11:36
MarkMark
244215
asked Nov 26 '18 at 11:36
MarkMark
244215
edited Nov 26 '18 at 11:59
Mark
asked Nov 26 '18 at 11:36
MarkMark
244215
asked Nov 26 '18 at 11:36
MarkMark
244215
asked Nov 26 '18 at 11:36
MarkMark
244215
244215
2
Can you clarify this more? do you mean vector or (multidimensional) array? I am also not sure what you mean by "and so on"; do you mean 20 and 10 consecutive items from array 1 and 2 respectively each time? Then array 1 will always be used up first, right? (you mentioned they are equal length)
– MartijnVanAttekum
Nov 26 '18 at 11:47
@MartijnVanAttekum, thanks for the questions. I've edited my post
– Mark
Nov 26 '18 at 11:59
add a comment |
2
Can you clarify this more? do you mean vector or (multidimensional) array? I am also not sure what you mean by "and so on"; do you mean 20 and 10 consecutive items from array 1 and 2 respectively each time? Then array 1 will always be used up first, right? (you mentioned they are equal length)
– MartijnVanAttekum
Nov 26 '18 at 11:47
@MartijnVanAttekum, thanks for the questions. I've edited my post
– Mark
Nov 26 '18 at 11:59
2
2
Can you clarify this more? do you mean vector or (multidimensional) array? I am also not sure what you mean by "and so on"; do you mean 20 and 10 consecutive items from array 1 and 2 respectively each time? Then array 1 will always be used up first, right? (you mentioned they are equal length)
– MartijnVanAttekum
Nov 26 '18 at 11:47
Can you clarify this more? do you mean vector or (multidimensional) array? I am also not sure what you mean by "and so on"; do you mean 20 and 10 consecutive items from array 1 and 2 respectively each time? Then array 1 will always be used up first, right? (you mentioned they are equal length)
– MartijnVanAttekum
Nov 26 '18 at 11:47
@MartijnVanAttekum, thanks for the questions. I've edited my post
– Mark
Nov 26 '18 at 11:59
@MartijnVanAttekum, thanks for the questions. I've edited my post
– Mark
Nov 26 '18 at 11:59
add a comment |
1 Answer
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votes
It seems that you use vectors then. Does this work? (I use some randomly initialized vectors). This assumes that the size of your vectors is a multiple of the number of elements you want to take each time.
vec1 <- rnorm(100)
vec2 <- rnorm(100)
step1 <- 20
step2 <- 10
as.vector(sapply(0 : (length(vec1) / step1 - 1), function(idx){
c(vec1[1 : step1 + (idx * step1)], vec2[1 : step2 + (idx * step2)])}))
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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oldest
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active
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It seems that you use vectors then. Does this work? (I use some randomly initialized vectors). This assumes that the size of your vectors is a multiple of the number of elements you want to take each time.
vec1 <- rnorm(100)
vec2 <- rnorm(100)
step1 <- 20
step2 <- 10
as.vector(sapply(0 : (length(vec1) / step1 - 1), function(idx){
c(vec1[1 : step1 + (idx * step1)], vec2[1 : step2 + (idx * step2)])}))
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
add a comment |
It seems that you use vectors then. Does this work? (I use some randomly initialized vectors). This assumes that the size of your vectors is a multiple of the number of elements you want to take each time.
vec1 <- rnorm(100)
vec2 <- rnorm(100)
step1 <- 20
step2 <- 10
as.vector(sapply(0 : (length(vec1) / step1 - 1), function(idx){
c(vec1[1 : step1 + (idx * step1)], vec2[1 : step2 + (idx * step2)])}))
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
add a comment |
It seems that you use vectors then. Does this work? (I use some randomly initialized vectors). This assumes that the size of your vectors is a multiple of the number of elements you want to take each time.
vec1 <- rnorm(100)
vec2 <- rnorm(100)
step1 <- 20
step2 <- 10
as.vector(sapply(0 : (length(vec1) / step1 - 1), function(idx){
c(vec1[1 : step1 + (idx * step1)], vec2[1 : step2 + (idx * step2)])}))
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
It seems that you use vectors then. Does this work? (I use some randomly initialized vectors). This assumes that the size of your vectors is a multiple of the number of elements you want to take each time.
vec1 <- rnorm(100)
vec2 <- rnorm(100)
step1 <- 20
step2 <- 10
as.vector(sapply(0 : (length(vec1) / step1 - 1), function(idx){
c(vec1[1 : step1 + (idx * step1)], vec2[1 : step2 + (idx * step2)])}))
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
answered Nov 26 '18 at 12:14
MartijnVanAttekumMartijnVanAttekum
531211
531211
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
add a comment |
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
Thank you @MartijnVanAttekum
– Mark
Nov 26 '18 at 12:36
add a comment |
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2
Can you clarify this more? do you mean vector or (multidimensional) array? I am also not sure what you mean by "and so on"; do you mean 20 and 10 consecutive items from array 1 and 2 respectively each time? Then array 1 will always be used up first, right? (you mentioned they are equal length)
– MartijnVanAttekum
Nov 26 '18 at 11:47
@MartijnVanAttekum, thanks for the questions. I've edited my post
– Mark
Nov 26 '18 at 11:59