Creating string index array from string
0
I have a string which i want to convert into a string indexed array for easy use.
Below is my expectations and outcomes.
Can someone guide me through this?
String: Dim QueryResponse = "TVShow=Adventure Time" & vbCrLf & "Color=Red"
Array:
Array
(
["TVShow"] => "Adventure Time"
["Color"] => "Red"
)
My current code:
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Current code array:
Array
(
[0] => "TVShow=Adventure Time"
[1] => "Color=Red"
)
Would love some opinions on this one, thanks!
arrays vb.net
asked Nov 26 '18 at 11:33
WilliamWilliam
72
add a comment |
0
I have a string which i want to convert into a string indexed array for easy use.
Below is my expectations and outcomes.
Can someone guide me through this?
String: Dim QueryResponse = "TVShow=Adventure Time" & vbCrLf & "Color=Red"
Array:
Array
(
["TVShow"] => "Adventure Time"
["Color"] => "Red"
)
My current code:
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Current code array:
Array
(
[0] => "TVShow=Adventure Time"
[1] => "Color=Red"
)
Would love some opinions on this one, thanks!
arrays vb.net
asked Nov 26 '18 at 11:33
WilliamWilliam
72
4
Your expected result is more a Dictionary<string,string> than an array
– Steve
Nov 26 '18 at 11:37
Perfect! I have implemented that, now just researching some small things and im away :D Thanks!
– William
Nov 26 '18 at 12:12
add a comment |
0
0
0
I have a string which i want to convert into a string indexed array for easy use.
Below is my expectations and outcomes.
Can someone guide me through this?
String: Dim QueryResponse = "TVShow=Adventure Time" & vbCrLf & "Color=Red"
Array:
Array
(
["TVShow"] => "Adventure Time"
["Color"] => "Red"
)
My current code:
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Current code array:
Array
(
[0] => "TVShow=Adventure Time"
[1] => "Color=Red"
)
Would love some opinions on this one, thanks!
arrays vb.net
asked Nov 26 '18 at 11:33
WilliamWilliam
72
I have a string which i want to convert into a string indexed array for easy use.
Below is my expectations and outcomes.
Can someone guide me through this?
String: Dim QueryResponse = "TVShow=Adventure Time" & vbCrLf & "Color=Red"
Array:
Array
(
["TVShow"] => "Adventure Time"
["Color"] => "Red"
)
My current code:
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Current code array:
Array
(
[0] => "TVShow=Adventure Time"
[1] => "Color=Red"
)
Would love some opinions on this one, thanks!
arrays vb.net
arrays vb.net
asked Nov 26 '18 at 11:33
WilliamWilliam
72
asked Nov 26 '18 at 11:33
WilliamWilliam
72
asked Nov 26 '18 at 11:33
WilliamWilliam
72
asked Nov 26 '18 at 11:33
WilliamWilliam
72
asked Nov 26 '18 at 11:33
WilliamWilliam
72
72
4
Your expected result is more a Dictionary<string,string> than an array
– Steve
Nov 26 '18 at 11:37
Perfect! I have implemented that, now just researching some small things and im away :D Thanks!
– William
Nov 26 '18 at 12:12
add a comment |
4
Your expected result is more a Dictionary<string,string> than an array
– Steve
Nov 26 '18 at 11:37
Perfect! I have implemented that, now just researching some small things and im away :D Thanks!
– William
Nov 26 '18 at 12:12
4
4
Your expected result is more a Dictionary<string,string> than an array
– Steve
Nov 26 '18 at 11:37
Your expected result is more a Dictionary<string,string> than an array
– Steve
Nov 26 '18 at 11:37
Perfect! I have implemented that, now just researching some small things and im away :D Thanks!
– William
Nov 26 '18 at 12:12
Perfect! I have implemented that, now just researching some small things and im away :D Thanks!
– William
Nov 26 '18 at 12:12
add a comment |
1 Answer
1
active
oldest
votes
1
Use a dictionary instead of an array
Dim dictionary1 As New Dictionary(Of String, String)
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Dim res1 As String = result(0)
Dim res2 As String = result(1)
'Split res1 and res2 into arrays using '=' as delimeter
Dim res1s() As String = Split(res1,"=")
Dim res2s() As String = Split(res2,"=")
dictionary1.Add(res1(0),res1(1))
dictionary1.Add(res2(0),res2(1))
To access the dictionary entries, use
Dim pair As KeyValuePair(Of String, String)
For Each pair In dictionary1
You can access the values here using `pair.key` and `pair.value`
'Eg Label1.Text = pair.key or Console.WriteLine(pair.value)
Next
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Use a dictionary instead of an array
Dim dictionary1 As New Dictionary(Of String, String)
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Dim res1 As String = result(0)
Dim res2 As String = result(1)
'Split res1 and res2 into arrays using '=' as delimeter
Dim res1s() As String = Split(res1,"=")
Dim res2s() As String = Split(res2,"=")
dictionary1.Add(res1(0),res1(1))
dictionary1.Add(res2(0),res2(1))
To access the dictionary entries, use
Dim pair As KeyValuePair(Of String, String)
For Each pair In dictionary1
You can access the values here using `pair.key` and `pair.value`
'Eg Label1.Text = pair.key or Console.WriteLine(pair.value)
Next
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
add a comment |
1
Use a dictionary instead of an array
Dim dictionary1 As New Dictionary(Of String, String)
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Dim res1 As String = result(0)
Dim res2 As String = result(1)
'Split res1 and res2 into arrays using '=' as delimeter
Dim res1s() As String = Split(res1,"=")
Dim res2s() As String = Split(res2,"=")
dictionary1.Add(res1(0),res1(1))
dictionary1.Add(res2(0),res2(1))
To access the dictionary entries, use
Dim pair As KeyValuePair(Of String, String)
For Each pair In dictionary1
You can access the values here using `pair.key` and `pair.value`
'Eg Label1.Text = pair.key or Console.WriteLine(pair.value)
Next
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
add a comment |
1
1
1
Use a dictionary instead of an array
Dim dictionary1 As New Dictionary(Of String, String)
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Dim res1 As String = result(0)
Dim res2 As String = result(1)
'Split res1 and res2 into arrays using '=' as delimeter
Dim res1s() As String = Split(res1,"=")
Dim res2s() As String = Split(res2,"=")
dictionary1.Add(res1(0),res1(1))
dictionary1.Add(res2(0),res2(1))
To access the dictionary entries, use
Dim pair As KeyValuePair(Of String, String)
For Each pair In dictionary1
You can access the values here using `pair.key` and `pair.value`
'Eg Label1.Text = pair.key or Console.WriteLine(pair.value)
Next
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
Use a dictionary instead of an array
Dim dictionary1 As New Dictionary(Of String, String)
Dim result() As String = QueryResponse.Split({vbCrLf}, StringSplitOptions.RemoveEmptyEntries)
Dim res1 As String = result(0)
Dim res2 As String = result(1)
'Split res1 and res2 into arrays using '=' as delimeter
Dim res1s() As String = Split(res1,"=")
Dim res2s() As String = Split(res2,"=")
dictionary1.Add(res1(0),res1(1))
dictionary1.Add(res2(0),res2(1))
To access the dictionary entries, use
Dim pair As KeyValuePair(Of String, String)
For Each pair In dictionary1
You can access the values here using `pair.key` and `pair.value`
'Eg Label1.Text = pair.key or Console.WriteLine(pair.value)
Next
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
answered Nov 26 '18 at 12:17
preciousbetinepreciousbetine
1,5772418
1,5772418
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
add a comment |
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
Was writing up my own answer which is technically similar so i will accept this, saves me writing the rest up :D Thanks!
– William
Nov 26 '18 at 12:22
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
You welcome @William
– preciousbetine
Nov 26 '18 at 12:23
add a comment |
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4
Your expected result is more a Dictionary<string,string> than an array
– Steve
Nov 26 '18 at 11:37
Perfect! I have implemented that, now just researching some small things and im away :D Thanks!
– William
Nov 26 '18 at 12:12