How to continue a failed loop php











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how do you continue a loop that an iteration has failed but still want the remaining part of the loop to be run.



$arr = [1, 2, 3, 4];



foreach($arr as $val) {

    if($val == 2) {

        throw new Exception('Value = 2');

    }



    try {

        echo $val;

    }

    catch(Execption $e) {

        echo $e;

    }

}


How do i go about this






php laravel loops foreach







share|improve this question
























  • You're trying to catch an exception thrown outside your try block. That's not how exceptions work.
    – Jeto
    Nov 20 at 4:47








  • 1




    $arr = [1,2,3,4]; foreach($arr as $val){ if($val == 2) continue; echo $val; }
    – sh4rifi
    Nov 20 at 4:50










  • Why do you throw an exception if you want your code to continue running?
    – Nico Haase
    Nov 20 at 8:29










  • i am not actually throwing the exception manually, i am just trying to recreate a type of situation am in my code, i am sending emails instead, of exceptions, but the emails return error from time to time and i want to be able to handle this.
    – Maxwell
    Nov 20 at 8:34















up vote
0
down vote

favorite












how do you continue a loop that an iteration has failed but still want the remaining part of the loop to be run.



$arr = [1, 2, 3, 4];



foreach($arr as $val) {

    if($val == 2) {

        throw new Exception('Value = 2');

    }



    try {

        echo $val;

    }

    catch(Execption $e) {

        echo $e;

    }

}


How do i go about this






php laravel loops foreach







share|improve this question
























  • You're trying to catch an exception thrown outside your try block. That's not how exceptions work.
    – Jeto
    Nov 20 at 4:47








  • 1




    $arr = [1,2,3,4]; foreach($arr as $val){ if($val == 2) continue; echo $val; }
    – sh4rifi
    Nov 20 at 4:50










  • Why do you throw an exception if you want your code to continue running?
    – Nico Haase
    Nov 20 at 8:29










  • i am not actually throwing the exception manually, i am just trying to recreate a type of situation am in my code, i am sending emails instead, of exceptions, but the emails return error from time to time and i want to be able to handle this.
    – Maxwell
    Nov 20 at 8:34













up vote
0
down vote

favorite









up vote
0
down vote

favorite











how do you continue a loop that an iteration has failed but still want the remaining part of the loop to be run.



$arr = [1, 2, 3, 4];



foreach($arr as $val) {

    if($val == 2) {

        throw new Exception('Value = 2');

    }



    try {

        echo $val;

    }

    catch(Execption $e) {

        echo $e;

    }

}


How do i go about this






php laravel loops foreach







share|improve this question















how do you continue a loop that an iteration has failed but still want the remaining part of the loop to be run.



$arr = [1, 2, 3, 4];



foreach($arr as $val) {

    if($val == 2) {

        throw new Exception('Value = 2');

    }



    try {

        echo $val;

    }

    catch(Execption $e) {

        echo $e;

    }

}


How do i go about this






php laravel loops foreach




php laravel loops foreach






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 at 8:28

























asked Nov 20 at 4:40









Maxwell

319




319












  • You're trying to catch an exception thrown outside your try block. That's not how exceptions work.
    – Jeto
    Nov 20 at 4:47








  • 1




    $arr = [1,2,3,4]; foreach($arr as $val){ if($val == 2) continue; echo $val; }
    – sh4rifi
    Nov 20 at 4:50










  • Why do you throw an exception if you want your code to continue running?
    – Nico Haase
    Nov 20 at 8:29










  • i am not actually throwing the exception manually, i am just trying to recreate a type of situation am in my code, i am sending emails instead, of exceptions, but the emails return error from time to time and i want to be able to handle this.
    – Maxwell
    Nov 20 at 8:34


















  • You're trying to catch an exception thrown outside your try block. That's not how exceptions work.
    – Jeto
    Nov 20 at 4:47








  • 1




    $arr = [1,2,3,4]; foreach($arr as $val){ if($val == 2) continue; echo $val; }
    – sh4rifi
    Nov 20 at 4:50










  • Why do you throw an exception if you want your code to continue running?
    – Nico Haase
    Nov 20 at 8:29










  • i am not actually throwing the exception manually, i am just trying to recreate a type of situation am in my code, i am sending emails instead, of exceptions, but the emails return error from time to time and i want to be able to handle this.
    – Maxwell
    Nov 20 at 8:34
















You're trying to catch an exception thrown outside your try block. That's not how exceptions work.
– Jeto
Nov 20 at 4:47






You're trying to catch an exception thrown outside your try block. That's not how exceptions work.
– Jeto
Nov 20 at 4:47






1




1




$arr = [1,2,3,4]; foreach($arr as $val){ if($val == 2) continue; echo $val; }
– sh4rifi
Nov 20 at 4:50




$arr = [1,2,3,4]; foreach($arr as $val){ if($val == 2) continue; echo $val; }
– sh4rifi
Nov 20 at 4:50












Why do you throw an exception if you want your code to continue running?
– Nico Haase
Nov 20 at 8:29




Why do you throw an exception if you want your code to continue running?
– Nico Haase
Nov 20 at 8:29












i am not actually throwing the exception manually, i am just trying to recreate a type of situation am in my code, i am sending emails instead, of exceptions, but the emails return error from time to time and i want to be able to handle this.
– Maxwell
Nov 20 at 8:34




i am not actually throwing the exception manually, i am just trying to recreate a type of situation am in my code, i am sending emails instead, of exceptions, but the emails return error from time to time and i want to be able to handle this.
– Maxwell
Nov 20 at 8:34












2 Answers
2






active

oldest

votes

















up vote
1
down vote













You can try something like this pattern if want to follow the pattern.



$arr = [1, 2, 3, 4];



foreach($arr as $a) {

    try {

        if ( $a == 2 ) {

            throw new Exception('Exception');

        }



        echo $a.' ';     

    }

    catch(Exception $e) {

        echo 'Message ';

    }



    echo PHP_EOL;

}


it will help for not breaking the loop



Result will be as:



1 Message 3 4


Hope it helps.






share|improve this answer






























    up vote
    0
    down vote













    Rather than throw an exception you can create a Log



    Log::error('Array value = ' . $val);
    
continue;


    This will record the issue but still allow the processing of the rest of the array



    There is more details here:



    https://laravel.com/docs/5.7/logging






    share|improve this answer























    • i am not actually throwing the exception manually, i am just trying to create a type of situation am in
      – Maxwell
      Nov 20 at 8:16










    • If you can give us more details about your situation then we might be able to help you more
      – Josh
      Nov 21 at 2:13











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    2 Answers
    2






    active

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    2 Answers
    2






    active

    oldest

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    votes






    active

    oldest

    votes








    up vote
    1
    down vote













    You can try something like this pattern if want to follow the pattern.



    $arr = [1, 2, 3, 4];
    

    
foreach($arr as $a) {
    
    try {
    
        if ( $a == 2 ) {
    
            throw new Exception('Exception');
    
        }
    

    
        echo $a.' ';     
    
    }
    
    catch(Exception $e) {
    
        echo 'Message ';
    
    }
    

    
    echo PHP_EOL;
    
}


    it will help for not breaking the loop



    Result will be as:



    1 Message 3 4


    Hope it helps.






    share|improve this answer



























      up vote
      1
      down vote













      You can try something like this pattern if want to follow the pattern.



      $arr = [1, 2, 3, 4];
      

      
foreach($arr as $a) {
      
    try {
      
        if ( $a == 2 ) {
      
            throw new Exception('Exception');
      
        }
      

      
        echo $a.' ';     
      
    }
      
    catch(Exception $e) {
      
        echo 'Message ';
      
    }
      

      
    echo PHP_EOL;
      
}


      it will help for not breaking the loop



      Result will be as:



      1 Message 3 4


      Hope it helps.






      share|improve this answer

























        up vote
        1
        down vote










        up vote
        1
        down vote









        You can try something like this pattern if want to follow the pattern.



        $arr = [1, 2, 3, 4];
        

        
foreach($arr as $a) {
        
    try {
        
        if ( $a == 2 ) {
        
            throw new Exception('Exception');
        
        }
        

        
        echo $a.' ';     
        
    }
        
    catch(Exception $e) {
        
        echo 'Message ';
        
    }
        

        
    echo PHP_EOL;
        
}


        it will help for not breaking the loop



        Result will be as:



        1 Message 3 4


        Hope it helps.






        share|improve this answer














        You can try something like this pattern if want to follow the pattern.



        $arr = [1, 2, 3, 4];
        

        
foreach($arr as $a) {
        
    try {
        
        if ( $a == 2 ) {
        
            throw new Exception('Exception');
        
        }
        

        
        echo $a.' ';     
        
    }
        
    catch(Exception $e) {
        
        echo 'Message ';
        
    }
        

        
    echo PHP_EOL;
        
}


        it will help for not breaking the loop



        Result will be as:



        1 Message 3 4


        Hope it helps.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 20 at 6:12









        DestinatioN

        1,2501326




        1,2501326










        answered Nov 20 at 5:58









        kshitij

        18210




        18210
























            up vote
            0
            down vote













            Rather than throw an exception you can create a Log



            Log::error('Array value = ' . $val);
            
continue;


            This will record the issue but still allow the processing of the rest of the array



            There is more details here:



            https://laravel.com/docs/5.7/logging






            share|improve this answer























            • i am not actually throwing the exception manually, i am just trying to create a type of situation am in
              – Maxwell
              Nov 20 at 8:16










            • If you can give us more details about your situation then we might be able to help you more
              – Josh
              Nov 21 at 2:13















            up vote
            0
            down vote













            Rather than throw an exception you can create a Log



            Log::error('Array value = ' . $val);
            
continue;


            This will record the issue but still allow the processing of the rest of the array



            There is more details here:



            https://laravel.com/docs/5.7/logging






            share|improve this answer























            • i am not actually throwing the exception manually, i am just trying to create a type of situation am in
              – Maxwell
              Nov 20 at 8:16










            • If you can give us more details about your situation then we might be able to help you more
              – Josh
              Nov 21 at 2:13













            up vote
            0
            down vote










            up vote
            0
            down vote









            Rather than throw an exception you can create a Log



            Log::error('Array value = ' . $val);
            
continue;


            This will record the issue but still allow the processing of the rest of the array



            There is more details here:



            https://laravel.com/docs/5.7/logging






            share|improve this answer














            Rather than throw an exception you can create a Log



            Log::error('Array value = ' . $val);
            
continue;


            This will record the issue but still allow the processing of the rest of the array



            There is more details here:



            https://laravel.com/docs/5.7/logging







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 20 at 5:40

























            answered Nov 20 at 5:33









            Josh

            590111




            590111












            • i am not actually throwing the exception manually, i am just trying to create a type of situation am in
              – Maxwell
              Nov 20 at 8:16










            • If you can give us more details about your situation then we might be able to help you more
              – Josh
              Nov 21 at 2:13


















            • i am not actually throwing the exception manually, i am just trying to create a type of situation am in
              – Maxwell
              Nov 20 at 8:16










            • If you can give us more details about your situation then we might be able to help you more
              – Josh
              Nov 21 at 2:13
















            i am not actually throwing the exception manually, i am just trying to create a type of situation am in
            – Maxwell
            Nov 20 at 8:16




            i am not actually throwing the exception manually, i am just trying to create a type of situation am in
            – Maxwell
            Nov 20 at 8:16












            If you can give us more details about your situation then we might be able to help you more
            – Josh
            Nov 21 at 2:13




            If you can give us more details about your situation then we might be able to help you more
            – Josh
            Nov 21 at 2:13


















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