Regular Expression for filtering invalid windows characters in Java
up vote
2
down vote
favorite
I am looking for a regular expression which will allow me to check if the String has invalid (Windows) Characters.
Here is my sample code:-
public class Test {
public static void main(String args) {
String folderName = ">aa?|<";
Pattern p = Pattern.compile(".[\\/:"*<>|].*$");
Matcher m = p.matcher(folderName);
if (m.matches()) {
System.out.println("Match");
} else {
System.out.println("Un-match");
}
}
}
The pattern works fine if the special characters are in between the alphabets ( like for ex. "a>a")
Can anyone please suggest the appropriate expression.
I have searched many links but couldn't get a solution.
Thanks in advance!
java regex
edited Nov 20 at 4:34
A J
5091319
asked Nov 20 at 3:14
Raghu G
132
add a comment |
up vote
2
down vote
favorite
I am looking for a regular expression which will allow me to check if the String has invalid (Windows) Characters.
Here is my sample code:-
public class Test {
public static void main(String args) {
String folderName = ">aa?|<";
Pattern p = Pattern.compile(".[\\/:"*<>|].*$");
Matcher m = p.matcher(folderName);
if (m.matches()) {
System.out.println("Match");
} else {
System.out.println("Un-match");
}
}
}
The pattern works fine if the special characters are in between the alphabets ( like for ex. "a>a")
Can anyone please suggest the appropriate expression.
I have searched many links but couldn't get a solution.
Thanks in advance!
java regex
edited Nov 20 at 4:34
A J
5091319
asked Nov 20 at 3:14
Raghu G
132
What is the rule here?
– rv7
Nov 20 at 5:06
Check if the given string has characters that are not allowed by windows.
– Raghu G
Nov 20 at 11:23
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I am looking for a regular expression which will allow me to check if the String has invalid (Windows) Characters.
Here is my sample code:-
public class Test {
public static void main(String args) {
String folderName = ">aa?|<";
Pattern p = Pattern.compile(".[\\/:"*<>|].*$");
Matcher m = p.matcher(folderName);
if (m.matches()) {
System.out.println("Match");
} else {
System.out.println("Un-match");
}
}
}
The pattern works fine if the special characters are in between the alphabets ( like for ex. "a>a")
Can anyone please suggest the appropriate expression.
I have searched many links but couldn't get a solution.
Thanks in advance!
java regex
edited Nov 20 at 4:34
A J
5091319
asked Nov 20 at 3:14
Raghu G
132
I am looking for a regular expression which will allow me to check if the String has invalid (Windows) Characters.
Here is my sample code:-
public class Test {
public static void main(String args) {
String folderName = ">aa?|<";
Pattern p = Pattern.compile(".[\\/:"*<>|].*$");
Matcher m = p.matcher(folderName);
if (m.matches()) {
System.out.println("Match");
} else {
System.out.println("Un-match");
}
}
}
The pattern works fine if the special characters are in between the alphabets ( like for ex. "a>a")
Can anyone please suggest the appropriate expression.
I have searched many links but couldn't get a solution.
Thanks in advance!
java regex
java regex
edited Nov 20 at 4:34
A J
5091319
asked Nov 20 at 3:14
Raghu G
132
edited Nov 20 at 4:34
A J
5091319
asked Nov 20 at 3:14
Raghu G
132
edited Nov 20 at 4:34
A J
5091319
edited Nov 20 at 4:34
A J
5091319
edited Nov 20 at 4:34
A J
5091319
5091319
asked Nov 20 at 3:14
Raghu G
132
asked Nov 20 at 3:14
Raghu G
132
asked Nov 20 at 3:14
Raghu G
132
132
What is the rule here?
– rv7
Nov 20 at 5:06
Check if the given string has characters that are not allowed by windows.
– Raghu G
Nov 20 at 11:23
add a comment |
What is the rule here?
– rv7
Nov 20 at 5:06
Check if the given string has characters that are not allowed by windows.
– Raghu G
Nov 20 at 11:23
What is the rule here?
– rv7
Nov 20 at 5:06
What is the rule here?
– rv7
Nov 20 at 5:06
Check if the given string has characters that are not allowed by windows.
– Raghu G
Nov 20 at 11:23
Check if the given string has characters that are not allowed by windows.
– Raghu G
Nov 20 at 11:23
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
accepted
This is because your initial dot is matching exactly one character. Change it to .* to match it zero or more characters.
So change .[\\/:"*<>|].*$ to .*[\\/:"*<>|].*$.
answered Nov 20 at 3:39
Kartik
2,51731331
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
works for me..String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$");gives output asUn-match
– Kartik
Nov 20 at 22:52
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
This is because your initial dot is matching exactly one character. Change it to .* to match it zero or more characters.
So change .[\\/:"*<>|].*$ to .*[\\/:"*<>|].*$.
answered Nov 20 at 3:39
Kartik
2,51731331
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
works for me..String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$");gives output asUn-match
– Kartik
Nov 20 at 22:52
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
add a comment |
up vote
0
down vote
accepted
This is because your initial dot is matching exactly one character. Change it to .* to match it zero or more characters.
So change .[\\/:"*<>|].*$ to .*[\\/:"*<>|].*$.
answered Nov 20 at 3:39
Kartik
2,51731331
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
works for me..String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$");gives output asUn-match
– Kartik
Nov 20 at 22:52
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
add a comment |
up vote
0
down vote
accepted
up vote
0
down vote
accepted
This is because your initial dot is matching exactly one character. Change it to .* to match it zero or more characters.
So change .[\\/:"*<>|].*$ to .*[\\/:"*<>|].*$.
answered Nov 20 at 3:39
Kartik
2,51731331
This is because your initial dot is matching exactly one character. Change it to .* to match it zero or more characters.
So change .[\\/:"*<>|].*$ to .*[\\/:"*<>|].*$.
answered Nov 20 at 3:39
Kartik
2,51731331
answered Nov 20 at 3:39
Kartik
2,51731331
answered Nov 20 at 3:39
Kartik
2,51731331
answered Nov 20 at 3:39
Kartik
2,51731331
2,51731331
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
works for me..String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$");gives output asUn-match
– Kartik
Nov 20 at 22:52
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
add a comment |
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
works for me..String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$");gives output asUn-match
– Kartik
Nov 20 at 22:52
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
If I do that, even if the string dosent contain any invalid characters it shows a match.
– Raghu G
Nov 20 at 11:21
works for me..
String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$"); gives output as Un-match– Kartik
Nov 20 at 22:52
works for me..
String folderName = "aaaa";Pattern p = Pattern.compile(".*[\\/:"*<>|].*$"); gives output as Un-match– Kartik
Nov 20 at 22:52
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
Yeah it worked. Thanks a ton. Instead of matches() method we can also use the find() method and keep the actual regex as [\\/:"*<>|]. This will check if there is any special character present.
– Raghu G
Nov 21 at 1:03
add a comment |
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What is the rule here?
– rv7
Nov 20 at 5:06
Check if the given string has characters that are not allowed by windows.
– Raghu G
Nov 20 at 11:23