Get outputs from jq on a single line












27















I got below output using: https://stackoverflow.com/a/40330344




(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})


Output:



 {  
"key": "SEA-739",
"status": "Open",
"assignee": null
}
{
"key": "SEA-738",
"status": "Resolved",
"assignee": "user2@mycompany.com"
}



But I need to parse each and every line but it's tough to identify which assignee is for which key as far as key group is concerned. Is this possible to make one bunch in one row using jq?



Expected output:



{ "key": "SEA-739", "status": "Open", "assignee": null }
{ "key": "SEA-738", "status": "Resolved", "assignee": "user2@mycompany.com"}


OR



{ "SEA-739", "Open", null }
{ "SEA-738", "Resolved", user2@mycompany.com }









share|improve this question





























    27















    I got below output using: https://stackoverflow.com/a/40330344




    (.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})


    Output:



     {  
    "key": "SEA-739",
    "status": "Open",
    "assignee": null
    }
    {
    "key": "SEA-738",
    "status": "Resolved",
    "assignee": "user2@mycompany.com"
    }



    But I need to parse each and every line but it's tough to identify which assignee is for which key as far as key group is concerned. Is this possible to make one bunch in one row using jq?



    Expected output:



    { "key": "SEA-739", "status": "Open", "assignee": null }
    { "key": "SEA-738", "status": "Resolved", "assignee": "user2@mycompany.com"}


    OR



    { "SEA-739", "Open", null }
    { "SEA-738", "Resolved", user2@mycompany.com }









    share|improve this question



























      27












      27








      27


      5






      I got below output using: https://stackoverflow.com/a/40330344




      (.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})


      Output:



       {  
      "key": "SEA-739",
      "status": "Open",
      "assignee": null
      }
      {
      "key": "SEA-738",
      "status": "Resolved",
      "assignee": "user2@mycompany.com"
      }



      But I need to parse each and every line but it's tough to identify which assignee is for which key as far as key group is concerned. Is this possible to make one bunch in one row using jq?



      Expected output:



      { "key": "SEA-739", "status": "Open", "assignee": null }
      { "key": "SEA-738", "status": "Resolved", "assignee": "user2@mycompany.com"}


      OR



      { "SEA-739", "Open", null }
      { "SEA-738", "Resolved", user2@mycompany.com }









      share|improve this question
















      I got below output using: https://stackoverflow.com/a/40330344




      (.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})


      Output:



       {  
      "key": "SEA-739",
      "status": "Open",
      "assignee": null
      }
      {
      "key": "SEA-738",
      "status": "Resolved",
      "assignee": "user2@mycompany.com"
      }



      But I need to parse each and every line but it's tough to identify which assignee is for which key as far as key group is concerned. Is this possible to make one bunch in one row using jq?



      Expected output:



      { "key": "SEA-739", "status": "Open", "assignee": null }
      { "key": "SEA-738", "status": "Resolved", "assignee": "user2@mycompany.com"}


      OR



      { "SEA-739", "Open", null }
      { "SEA-738", "Resolved", user2@mycompany.com }






      json jq






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited May 23 '17 at 10:31









      Community

      11




      11










      asked Nov 3 '16 at 8:01









      Jitesh SojitraJitesh Sojitra

      1,23411733




      1,23411733
























          1 Answer
          1






          active

          oldest

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          57














          -c is what you likely need



          Using the output you posted above, you can process it further:





          jq -c . input


          To Give;



          {"key":"SEA-739","status":"Open","assignee":null}
          {"key":"SEA-738","status":"Resolved","assignee":"user2@mycompany.com"}


          Or you can just change your original command





          FROM





          jq -r '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'



          TO




          jq -c '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'





          share|improve this answer

























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            1 Answer
            1






            active

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            active

            oldest

            votes









            57














            -c is what you likely need



            Using the output you posted above, you can process it further:





            jq -c . input


            To Give;



            {"key":"SEA-739","status":"Open","assignee":null}
            {"key":"SEA-738","status":"Resolved","assignee":"user2@mycompany.com"}


            Or you can just change your original command





            FROM





            jq -r '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'



            TO




            jq -c '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'





            share|improve this answer






























              57














              -c is what you likely need



              Using the output you posted above, you can process it further:





              jq -c . input


              To Give;



              {"key":"SEA-739","status":"Open","assignee":null}
              {"key":"SEA-738","status":"Resolved","assignee":"user2@mycompany.com"}


              Or you can just change your original command





              FROM





              jq -r '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'



              TO




              jq -c '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'





              share|improve this answer




























                57












                57








                57







                -c is what you likely need



                Using the output you posted above, you can process it further:





                jq -c . input


                To Give;



                {"key":"SEA-739","status":"Open","assignee":null}
                {"key":"SEA-738","status":"Resolved","assignee":"user2@mycompany.com"}


                Or you can just change your original command





                FROM





                jq -r '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'



                TO




                jq -c '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'





                share|improve this answer















                -c is what you likely need



                Using the output you posted above, you can process it further:





                jq -c . input


                To Give;



                {"key":"SEA-739","status":"Open","assignee":null}
                {"key":"SEA-738","status":"Resolved","assignee":"user2@mycompany.com"}


                Or you can just change your original command





                FROM





                jq -r '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'



                TO




                jq -c '(.issues | {key, status: .fields.status.name, assignee: .fields.assignee.emailAddress})'






                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 26 '18 at 3:14

























                answered Nov 3 '16 at 8:09









                hmedia1hmedia1

                2,18111117




                2,18111117
































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