Not matching string of regular expression in C programing
Requirement is,
In a string (plan is the variable), For which does not have the sub string "TT", should return success message in the pattern matching ("Regular expression not having TT" message in the console).
I tried [^(TT)], I tried negation,
I tried ^(?!.*TT).$
#include <stdio.h>
#include "regex.h"
int main()
{
regex_t exps;
int r1 =-1;
int r2= -1;
char *pattern="\^(\?\!.*TT).*\$";
char *plan="TEST QBSE US 5USD charge sample conv offer";
r1=regcomp(&exps, pattern, REG_EXTENDED | REG_NOSUB);
if (r1 == 0)
{
printf("Regular expression is parsed sucessfully:%s n",pattern);
}
else
{
printf("Regular expression parsing failed.n");
}
r2=regexec(&exps, plan, (size_t)0, NULL, 0);
if (r2 == 0)
{
printf("Regular expression not having TT n");
}
else
{
printf("Regular expression is not matched.n");
}
regfree(&exps);
return 0;
}
current output:
Regular expression is parsed sucessfully :^(?!.TT).$
Regular expression is not matched.
regex
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
add a comment |
Requirement is,
In a string (plan is the variable), For which does not have the sub string "TT", should return success message in the pattern matching ("Regular expression not having TT" message in the console).
I tried [^(TT)], I tried negation,
I tried ^(?!.*TT).$
#include <stdio.h>
#include "regex.h"
int main()
{
regex_t exps;
int r1 =-1;
int r2= -1;
char *pattern="\^(\?\!.*TT).*\$";
char *plan="TEST QBSE US 5USD charge sample conv offer";
r1=regcomp(&exps, pattern, REG_EXTENDED | REG_NOSUB);
if (r1 == 0)
{
printf("Regular expression is parsed sucessfully:%s n",pattern);
}
else
{
printf("Regular expression parsing failed.n");
}
r2=regexec(&exps, plan, (size_t)0, NULL, 0);
if (r2 == 0)
{
printf("Regular expression not having TT n");
}
else
{
printf("Regular expression is not matched.n");
}
regfree(&exps);
return 0;
}
current output:
Regular expression is parsed sucessfully :^(?!.TT).$
Regular expression is not matched.
regex
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
May I ask why you need the negation? Is it not easier to check ifTTis in the string instead?
– Jerry
Jan 10 at 13:04
add a comment |
Requirement is,
In a string (plan is the variable), For which does not have the sub string "TT", should return success message in the pattern matching ("Regular expression not having TT" message in the console).
I tried [^(TT)], I tried negation,
I tried ^(?!.*TT).$
#include <stdio.h>
#include "regex.h"
int main()
{
regex_t exps;
int r1 =-1;
int r2= -1;
char *pattern="\^(\?\!.*TT).*\$";
char *plan="TEST QBSE US 5USD charge sample conv offer";
r1=regcomp(&exps, pattern, REG_EXTENDED | REG_NOSUB);
if (r1 == 0)
{
printf("Regular expression is parsed sucessfully:%s n",pattern);
}
else
{
printf("Regular expression parsing failed.n");
}
r2=regexec(&exps, plan, (size_t)0, NULL, 0);
if (r2 == 0)
{
printf("Regular expression not having TT n");
}
else
{
printf("Regular expression is not matched.n");
}
regfree(&exps);
return 0;
}
current output:
Regular expression is parsed sucessfully :^(?!.TT).$
Regular expression is not matched.
regex
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
Requirement is,
In a string (plan is the variable), For which does not have the sub string "TT", should return success message in the pattern matching ("Regular expression not having TT" message in the console).
I tried [^(TT)], I tried negation,
I tried ^(?!.*TT).$
#include <stdio.h>
#include "regex.h"
int main()
{
regex_t exps;
int r1 =-1;
int r2= -1;
char *pattern="\^(\?\!.*TT).*\$";
char *plan="TEST QBSE US 5USD charge sample conv offer";
r1=regcomp(&exps, pattern, REG_EXTENDED | REG_NOSUB);
if (r1 == 0)
{
printf("Regular expression is parsed sucessfully:%s n",pattern);
}
else
{
printf("Regular expression parsing failed.n");
}
r2=regexec(&exps, plan, (size_t)0, NULL, 0);
if (r2 == 0)
{
printf("Regular expression not having TT n");
}
else
{
printf("Regular expression is not matched.n");
}
regfree(&exps);
return 0;
}
current output:
Regular expression is parsed sucessfully :^(?!.TT).$
Regular expression is not matched.
regex
regex
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
edited Nov 26 '18 at 5:55
Kingsley
3,23821428
3,23821428
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
asked Nov 26 '18 at 3:26
YuvatejaYuvateja
61
61
May I ask why you need the negation? Is it not easier to check ifTTis in the string instead?
– Jerry
Jan 10 at 13:04
add a comment |
May I ask why you need the negation? Is it not easier to check ifTTis in the string instead?
– Jerry
Jan 10 at 13:04
May I ask why you need the negation? Is it not easier to check if
TT is in the string instead?– Jerry
Jan 10 at 13:04
May I ask why you need the negation? Is it not easier to check if
TT is in the string instead?– Jerry
Jan 10 at 13:04
add a comment |
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May I ask why you need the negation? Is it not easier to check if
TTis in the string instead?– Jerry
Jan 10 at 13:04