QT read/write from QDataStream












0















I think i am having a fundamental misunderstanding of how all of this works, I am trying to combine 2 hexfiles in my QDataStream and then output them to a new QFile.



QFile filea( file1 );
QFile fileb( file2 );
QByteArray ba;
QDataStream ds(ba);
ds << filea.readAll();
ds << fileb.readAll();
QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");
result.open(QIODevice::ReadWrite);
result.write(ba);


The result is just an empty file, any suggestions?










share|improve this question





























    0















    I think i am having a fundamental misunderstanding of how all of this works, I am trying to combine 2 hexfiles in my QDataStream and then output them to a new QFile.



    QFile filea( file1 );
    QFile fileb( file2 );
    QByteArray ba;
    QDataStream ds(ba);
    ds << filea.readAll();
    ds << fileb.readAll();
    QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");
    result.open(QIODevice::ReadWrite);
    result.write(ba);


    The result is just an empty file, any suggestions?










    share|improve this question



























      0












      0








      0








      I think i am having a fundamental misunderstanding of how all of this works, I am trying to combine 2 hexfiles in my QDataStream and then output them to a new QFile.



      QFile filea( file1 );
      QFile fileb( file2 );
      QByteArray ba;
      QDataStream ds(ba);
      ds << filea.readAll();
      ds << fileb.readAll();
      QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");
      result.open(QIODevice::ReadWrite);
      result.write(ba);


      The result is just an empty file, any suggestions?










      share|improve this question
















      I think i am having a fundamental misunderstanding of how all of this works, I am trying to combine 2 hexfiles in my QDataStream and then output them to a new QFile.



      QFile filea( file1 );
      QFile fileb( file2 );
      QByteArray ba;
      QDataStream ds(ba);
      ds << filea.readAll();
      ds << fileb.readAll();
      QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");
      result.open(QIODevice::ReadWrite);
      result.write(ba);


      The result is just an empty file, any suggestions?







      c++ qt qt5 qdatastream






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 26 '18 at 3:10









      eyllanesc

      84k103562




      84k103562










      asked Aug 2 '18 at 21:19









      Aaron ManillAaron Manill

      84




      84
























          1 Answer
          1






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          oldest

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          0














          You have the following errors:




          • If you are only going to read a file, you must open it with the ReadOnly mode, if you are going to write it you must use WriteOnly, in your case you do not have it with filea, fileb and result.


          • The QByteArray you are using it to read the data of the filea and fileb files, and then write it to result, so it must be read and write. You are using the following QDataStream constructor:




          QDataStream::QDataStream(const QByteArray &a)



          Constructs a read-only data stream that operates on byte array a. Use
          QDataStream(QByteArray*, int) if you want to write to a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          And since the QByteArray is read only because it is not the appropriate constructor, you must use the other constructor:




          QDataStream::QDataStream(QByteArray *a, QIODevice::OpenMode mode)



          Constructs a data stream that operates on a byte array, a. The mode
          describes how the device is to be used.



          Alternatively, you can use QDataStream(const QByteArray &) if you just
          want to read from a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          Using the above we obtain the following:



          QFile filea( file1 );
          QFile fileb( file2 );
          QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");

          if(filea.open(QIODevice::ReadOnly) && fileb.open(QIODevice::ReadOnly) && result.open(QIODevice::WriteOnly)){
          QByteArray ba;
          QDataStream ds(&ba, QIODevice::ReadWrite);
          ds << filea.readAll();
          ds << fileb.readAll();
          result.write(ba);
          result.flush();
          }





          share|improve this answer
























          • Thank you very much!

            – Aaron Manill
            Aug 2 '18 at 21:56











          Your Answer






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          1 Answer
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          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          You have the following errors:




          • If you are only going to read a file, you must open it with the ReadOnly mode, if you are going to write it you must use WriteOnly, in your case you do not have it with filea, fileb and result.


          • The QByteArray you are using it to read the data of the filea and fileb files, and then write it to result, so it must be read and write. You are using the following QDataStream constructor:




          QDataStream::QDataStream(const QByteArray &a)



          Constructs a read-only data stream that operates on byte array a. Use
          QDataStream(QByteArray*, int) if you want to write to a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          And since the QByteArray is read only because it is not the appropriate constructor, you must use the other constructor:




          QDataStream::QDataStream(QByteArray *a, QIODevice::OpenMode mode)



          Constructs a data stream that operates on a byte array, a. The mode
          describes how the device is to be used.



          Alternatively, you can use QDataStream(const QByteArray &) if you just
          want to read from a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          Using the above we obtain the following:



          QFile filea( file1 );
          QFile fileb( file2 );
          QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");

          if(filea.open(QIODevice::ReadOnly) && fileb.open(QIODevice::ReadOnly) && result.open(QIODevice::WriteOnly)){
          QByteArray ba;
          QDataStream ds(&ba, QIODevice::ReadWrite);
          ds << filea.readAll();
          ds << fileb.readAll();
          result.write(ba);
          result.flush();
          }





          share|improve this answer
























          • Thank you very much!

            – Aaron Manill
            Aug 2 '18 at 21:56
















          0














          You have the following errors:




          • If you are only going to read a file, you must open it with the ReadOnly mode, if you are going to write it you must use WriteOnly, in your case you do not have it with filea, fileb and result.


          • The QByteArray you are using it to read the data of the filea and fileb files, and then write it to result, so it must be read and write. You are using the following QDataStream constructor:




          QDataStream::QDataStream(const QByteArray &a)



          Constructs a read-only data stream that operates on byte array a. Use
          QDataStream(QByteArray*, int) if you want to write to a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          And since the QByteArray is read only because it is not the appropriate constructor, you must use the other constructor:




          QDataStream::QDataStream(QByteArray *a, QIODevice::OpenMode mode)



          Constructs a data stream that operates on a byte array, a. The mode
          describes how the device is to be used.



          Alternatively, you can use QDataStream(const QByteArray &) if you just
          want to read from a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          Using the above we obtain the following:



          QFile filea( file1 );
          QFile fileb( file2 );
          QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");

          if(filea.open(QIODevice::ReadOnly) && fileb.open(QIODevice::ReadOnly) && result.open(QIODevice::WriteOnly)){
          QByteArray ba;
          QDataStream ds(&ba, QIODevice::ReadWrite);
          ds << filea.readAll();
          ds << fileb.readAll();
          result.write(ba);
          result.flush();
          }





          share|improve this answer
























          • Thank you very much!

            – Aaron Manill
            Aug 2 '18 at 21:56














          0












          0








          0







          You have the following errors:




          • If you are only going to read a file, you must open it with the ReadOnly mode, if you are going to write it you must use WriteOnly, in your case you do not have it with filea, fileb and result.


          • The QByteArray you are using it to read the data of the filea and fileb files, and then write it to result, so it must be read and write. You are using the following QDataStream constructor:




          QDataStream::QDataStream(const QByteArray &a)



          Constructs a read-only data stream that operates on byte array a. Use
          QDataStream(QByteArray*, int) if you want to write to a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          And since the QByteArray is read only because it is not the appropriate constructor, you must use the other constructor:




          QDataStream::QDataStream(QByteArray *a, QIODevice::OpenMode mode)



          Constructs a data stream that operates on a byte array, a. The mode
          describes how the device is to be used.



          Alternatively, you can use QDataStream(const QByteArray &) if you just
          want to read from a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          Using the above we obtain the following:



          QFile filea( file1 );
          QFile fileb( file2 );
          QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");

          if(filea.open(QIODevice::ReadOnly) && fileb.open(QIODevice::ReadOnly) && result.open(QIODevice::WriteOnly)){
          QByteArray ba;
          QDataStream ds(&ba, QIODevice::ReadWrite);
          ds << filea.readAll();
          ds << fileb.readAll();
          result.write(ba);
          result.flush();
          }





          share|improve this answer













          You have the following errors:




          • If you are only going to read a file, you must open it with the ReadOnly mode, if you are going to write it you must use WriteOnly, in your case you do not have it with filea, fileb and result.


          • The QByteArray you are using it to read the data of the filea and fileb files, and then write it to result, so it must be read and write. You are using the following QDataStream constructor:




          QDataStream::QDataStream(const QByteArray &a)



          Constructs a read-only data stream that operates on byte array a. Use
          QDataStream(QByteArray*, int) if you want to write to a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          And since the QByteArray is read only because it is not the appropriate constructor, you must use the other constructor:




          QDataStream::QDataStream(QByteArray *a, QIODevice::OpenMode mode)



          Constructs a data stream that operates on a byte array, a. The mode
          describes how the device is to be used.



          Alternatively, you can use QDataStream(const QByteArray &) if you just
          want to read from a byte array.



          Since QByteArray is not a QIODevice subclass, internally a QBuffer is
          created to wrap the byte array.




          Using the above we obtain the following:



          QFile filea( file1 );
          QFile fileb( file2 );
          QFile result("C:/Users/Aaron/Desktop/mergedfile.txt");

          if(filea.open(QIODevice::ReadOnly) && fileb.open(QIODevice::ReadOnly) && result.open(QIODevice::WriteOnly)){
          QByteArray ba;
          QDataStream ds(&ba, QIODevice::ReadWrite);
          ds << filea.readAll();
          ds << fileb.readAll();
          result.write(ba);
          result.flush();
          }






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Aug 2 '18 at 21:41









          eyllanesceyllanesc

          84k103562




          84k103562













          • Thank you very much!

            – Aaron Manill
            Aug 2 '18 at 21:56



















          • Thank you very much!

            – Aaron Manill
            Aug 2 '18 at 21:56

















          Thank you very much!

          – Aaron Manill
          Aug 2 '18 at 21:56





          Thank you very much!

          – Aaron Manill
          Aug 2 '18 at 21:56




















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