Consequences of projecting data onto lower dimensions












1















import numpy as np
import matplotlib.pyplot as plt
import matplotlib.mlab as mlab
import math

na = 400

ma = [2, 1]

Sa = [[3, -2], [-2, 3]]

sigma1 = [3, 3]

nb = 400

mb = [8, 6]

Sb = [[3, -2], [-2, 3]]

xa, ya = np.random.multivariate_normal(ma, Sa, na).T

xb, yb = np.random.multivariate_normal(mb, Sb, nb).T

plt.plot(xa, ya, 'x')
plt.plot(xb, yb, 'x')
plt.axis('equal')
plt.show()


I have randomly generated data from 2-dimensional Gaussian Distributions and need to project this on w=[0, 1] and plot the histogram. I tried using plt.hist but it does not allow the multiplication.










share|improve this question

























  • see stats.stackexchange.com/questions/201921/…

    – teng
    Nov 24 '18 at 0:02











  • Thanks for the link it was very useful. My difficulty is how I am going to be able to break down the 2d array to be able to do the dot product as my data when np= 10 is like this. [array([ 1.63383494, 4.6541953 , 2.10788923, 2.46806161, 1.87287563, 0.76323836, 2.95160091, 1.74592451, -1.27726486, 4.22058637]), array([ 2.48245559, 1.57752103, -1.23525301, -1.76199059, -0.38459408, 1.78905969, -2.03621301, 1.23246001, 1.89331416, -0.71733151])]. I know that the first projection should come out as [11/5; 5.75/5] when taking w as [2;1]

    – Michelle Abela
    Nov 24 '18 at 0:54













  • you'll need to cast the arrays as np.array and for dot product, use np.dot.

    – teng
    Nov 24 '18 at 0:57






  • 1





    Question has nothing to do with machine-learning - kindly do not spam the tag (removed).

    – desertnaut
    Nov 24 '18 at 0:58
















1















import numpy as np
import matplotlib.pyplot as plt
import matplotlib.mlab as mlab
import math

na = 400

ma = [2, 1]

Sa = [[3, -2], [-2, 3]]

sigma1 = [3, 3]

nb = 400

mb = [8, 6]

Sb = [[3, -2], [-2, 3]]

xa, ya = np.random.multivariate_normal(ma, Sa, na).T

xb, yb = np.random.multivariate_normal(mb, Sb, nb).T

plt.plot(xa, ya, 'x')
plt.plot(xb, yb, 'x')
plt.axis('equal')
plt.show()


I have randomly generated data from 2-dimensional Gaussian Distributions and need to project this on w=[0, 1] and plot the histogram. I tried using plt.hist but it does not allow the multiplication.










share|improve this question

























  • see stats.stackexchange.com/questions/201921/…

    – teng
    Nov 24 '18 at 0:02











  • Thanks for the link it was very useful. My difficulty is how I am going to be able to break down the 2d array to be able to do the dot product as my data when np= 10 is like this. [array([ 1.63383494, 4.6541953 , 2.10788923, 2.46806161, 1.87287563, 0.76323836, 2.95160091, 1.74592451, -1.27726486, 4.22058637]), array([ 2.48245559, 1.57752103, -1.23525301, -1.76199059, -0.38459408, 1.78905969, -2.03621301, 1.23246001, 1.89331416, -0.71733151])]. I know that the first projection should come out as [11/5; 5.75/5] when taking w as [2;1]

    – Michelle Abela
    Nov 24 '18 at 0:54













  • you'll need to cast the arrays as np.array and for dot product, use np.dot.

    – teng
    Nov 24 '18 at 0:57






  • 1





    Question has nothing to do with machine-learning - kindly do not spam the tag (removed).

    – desertnaut
    Nov 24 '18 at 0:58














1












1








1








import numpy as np
import matplotlib.pyplot as plt
import matplotlib.mlab as mlab
import math

na = 400

ma = [2, 1]

Sa = [[3, -2], [-2, 3]]

sigma1 = [3, 3]

nb = 400

mb = [8, 6]

Sb = [[3, -2], [-2, 3]]

xa, ya = np.random.multivariate_normal(ma, Sa, na).T

xb, yb = np.random.multivariate_normal(mb, Sb, nb).T

plt.plot(xa, ya, 'x')
plt.plot(xb, yb, 'x')
plt.axis('equal')
plt.show()


I have randomly generated data from 2-dimensional Gaussian Distributions and need to project this on w=[0, 1] and plot the histogram. I tried using plt.hist but it does not allow the multiplication.










share|improve this question
















import numpy as np
import matplotlib.pyplot as plt
import matplotlib.mlab as mlab
import math

na = 400

ma = [2, 1]

Sa = [[3, -2], [-2, 3]]

sigma1 = [3, 3]

nb = 400

mb = [8, 6]

Sb = [[3, -2], [-2, 3]]

xa, ya = np.random.multivariate_normal(ma, Sa, na).T

xb, yb = np.random.multivariate_normal(mb, Sb, nb).T

plt.plot(xa, ya, 'x')
plt.plot(xb, yb, 'x')
plt.axis('equal')
plt.show()


I have randomly generated data from 2-dimensional Gaussian Distributions and need to project this on w=[0, 1] and plot the histogram. I tried using plt.hist but it does not allow the multiplication.







python matplotlib






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 24 '18 at 0:59









desertnaut

18.2k73872




18.2k73872










asked Nov 23 '18 at 23:44









Michelle AbelaMichelle Abela

134




134













  • see stats.stackexchange.com/questions/201921/…

    – teng
    Nov 24 '18 at 0:02











  • Thanks for the link it was very useful. My difficulty is how I am going to be able to break down the 2d array to be able to do the dot product as my data when np= 10 is like this. [array([ 1.63383494, 4.6541953 , 2.10788923, 2.46806161, 1.87287563, 0.76323836, 2.95160091, 1.74592451, -1.27726486, 4.22058637]), array([ 2.48245559, 1.57752103, -1.23525301, -1.76199059, -0.38459408, 1.78905969, -2.03621301, 1.23246001, 1.89331416, -0.71733151])]. I know that the first projection should come out as [11/5; 5.75/5] when taking w as [2;1]

    – Michelle Abela
    Nov 24 '18 at 0:54













  • you'll need to cast the arrays as np.array and for dot product, use np.dot.

    – teng
    Nov 24 '18 at 0:57






  • 1





    Question has nothing to do with machine-learning - kindly do not spam the tag (removed).

    – desertnaut
    Nov 24 '18 at 0:58



















  • see stats.stackexchange.com/questions/201921/…

    – teng
    Nov 24 '18 at 0:02











  • Thanks for the link it was very useful. My difficulty is how I am going to be able to break down the 2d array to be able to do the dot product as my data when np= 10 is like this. [array([ 1.63383494, 4.6541953 , 2.10788923, 2.46806161, 1.87287563, 0.76323836, 2.95160091, 1.74592451, -1.27726486, 4.22058637]), array([ 2.48245559, 1.57752103, -1.23525301, -1.76199059, -0.38459408, 1.78905969, -2.03621301, 1.23246001, 1.89331416, -0.71733151])]. I know that the first projection should come out as [11/5; 5.75/5] when taking w as [2;1]

    – Michelle Abela
    Nov 24 '18 at 0:54













  • you'll need to cast the arrays as np.array and for dot product, use np.dot.

    – teng
    Nov 24 '18 at 0:57






  • 1





    Question has nothing to do with machine-learning - kindly do not spam the tag (removed).

    – desertnaut
    Nov 24 '18 at 0:58

















see stats.stackexchange.com/questions/201921/…

– teng
Nov 24 '18 at 0:02





see stats.stackexchange.com/questions/201921/…

– teng
Nov 24 '18 at 0:02













Thanks for the link it was very useful. My difficulty is how I am going to be able to break down the 2d array to be able to do the dot product as my data when np= 10 is like this. [array([ 1.63383494, 4.6541953 , 2.10788923, 2.46806161, 1.87287563, 0.76323836, 2.95160091, 1.74592451, -1.27726486, 4.22058637]), array([ 2.48245559, 1.57752103, -1.23525301, -1.76199059, -0.38459408, 1.78905969, -2.03621301, 1.23246001, 1.89331416, -0.71733151])]. I know that the first projection should come out as [11/5; 5.75/5] when taking w as [2;1]

– Michelle Abela
Nov 24 '18 at 0:54







Thanks for the link it was very useful. My difficulty is how I am going to be able to break down the 2d array to be able to do the dot product as my data when np= 10 is like this. [array([ 1.63383494, 4.6541953 , 2.10788923, 2.46806161, 1.87287563, 0.76323836, 2.95160091, 1.74592451, -1.27726486, 4.22058637]), array([ 2.48245559, 1.57752103, -1.23525301, -1.76199059, -0.38459408, 1.78905969, -2.03621301, 1.23246001, 1.89331416, -0.71733151])]. I know that the first projection should come out as [11/5; 5.75/5] when taking w as [2;1]

– Michelle Abela
Nov 24 '18 at 0:54















you'll need to cast the arrays as np.array and for dot product, use np.dot.

– teng
Nov 24 '18 at 0:57





you'll need to cast the arrays as np.array and for dot product, use np.dot.

– teng
Nov 24 '18 at 0:57




1




1





Question has nothing to do with machine-learning - kindly do not spam the tag (removed).

– desertnaut
Nov 24 '18 at 0:58





Question has nothing to do with machine-learning - kindly do not spam the tag (removed).

– desertnaut
Nov 24 '18 at 0:58












1 Answer
1






active

oldest

votes


















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Below links may be useful for learning numpy.



https://docs.scipy.org/doc/numpy-1.15.0/user/basics.creation.html
https://jakevdp.github.io/PythonDataScienceHandbook/02.02-the-basics-of-numpy-arrays.html



I think what you are asking is the below:



w = np.array([2,1])
a = np.array([xa,ya]).T
b = np.array([xb,yb]).T

aw = np.dot(a,w)
bw = np.dot(b,w)

plt.figure(0)
plt.hist(aw,label='a',histtype='step')
plt.hist(bw,label='b',histtype='step')
plt.title('projected')
plt.legend()





share|improve this answer























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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Below links may be useful for learning numpy.



    https://docs.scipy.org/doc/numpy-1.15.0/user/basics.creation.html
    https://jakevdp.github.io/PythonDataScienceHandbook/02.02-the-basics-of-numpy-arrays.html



    I think what you are asking is the below:



    w = np.array([2,1])
    a = np.array([xa,ya]).T
    b = np.array([xb,yb]).T

    aw = np.dot(a,w)
    bw = np.dot(b,w)

    plt.figure(0)
    plt.hist(aw,label='a',histtype='step')
    plt.hist(bw,label='b',histtype='step')
    plt.title('projected')
    plt.legend()





    share|improve this answer




























      0














      Below links may be useful for learning numpy.



      https://docs.scipy.org/doc/numpy-1.15.0/user/basics.creation.html
      https://jakevdp.github.io/PythonDataScienceHandbook/02.02-the-basics-of-numpy-arrays.html



      I think what you are asking is the below:



      w = np.array([2,1])
      a = np.array([xa,ya]).T
      b = np.array([xb,yb]).T

      aw = np.dot(a,w)
      bw = np.dot(b,w)

      plt.figure(0)
      plt.hist(aw,label='a',histtype='step')
      plt.hist(bw,label='b',histtype='step')
      plt.title('projected')
      plt.legend()





      share|improve this answer


























        0












        0








        0







        Below links may be useful for learning numpy.



        https://docs.scipy.org/doc/numpy-1.15.0/user/basics.creation.html
        https://jakevdp.github.io/PythonDataScienceHandbook/02.02-the-basics-of-numpy-arrays.html



        I think what you are asking is the below:



        w = np.array([2,1])
        a = np.array([xa,ya]).T
        b = np.array([xb,yb]).T

        aw = np.dot(a,w)
        bw = np.dot(b,w)

        plt.figure(0)
        plt.hist(aw,label='a',histtype='step')
        plt.hist(bw,label='b',histtype='step')
        plt.title('projected')
        plt.legend()





        share|improve this answer













        Below links may be useful for learning numpy.



        https://docs.scipy.org/doc/numpy-1.15.0/user/basics.creation.html
        https://jakevdp.github.io/PythonDataScienceHandbook/02.02-the-basics-of-numpy-arrays.html



        I think what you are asking is the below:



        w = np.array([2,1])
        a = np.array([xa,ya]).T
        b = np.array([xb,yb]).T

        aw = np.dot(a,w)
        bw = np.dot(b,w)

        plt.figure(0)
        plt.hist(aw,label='a',histtype='step')
        plt.hist(bw,label='b',histtype='step')
        plt.title('projected')
        plt.legend()






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 24 '18 at 1:07









        tengteng

        840721




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