get deferred promise value jQuery
0
I have below function
function commentCount(id) {
var deferred = new $.Deferred()
var url =
_spPageContextInfo.siteAbsoluteUrl +
"/_api/lists/getByTitle('Comments')/items?$select=Id&$filter=ItemID eq " +
id +
" and Title eq 'Colleague'"
getData(url).then(function(data) {
deferred.resolve(data.d.results.length)
})
return deferred.promise()
}
Now I want to return that value in HTML string as below but it shows [object object]
'<div class="card-footer"> <div class="row "><div class="col-lg mobile-center"><a href="#">' + commentCount(item.Id)
How can I get value like that
javascript jquery es6-promise jquery-deferred
asked Nov 23 '18 at 23:31
MilindMilind
60021441
|
show 1 more comment
0
I have below function
function commentCount(id) {
var deferred = new $.Deferred()
var url =
_spPageContextInfo.siteAbsoluteUrl +
"/_api/lists/getByTitle('Comments')/items?$select=Id&$filter=ItemID eq " +
id +
" and Title eq 'Colleague'"
getData(url).then(function(data) {
deferred.resolve(data.d.results.length)
})
return deferred.promise()
}
Now I want to return that value in HTML string as below but it shows [object object]
'<div class="card-footer"> <div class="row "><div class="col-lg mobile-center"><a href="#">' + commentCount(item.Id)
How can I get value like that
javascript jquery es6-promise jquery-deferred
asked Nov 23 '18 at 23:31
MilindMilind
60021441
It is integer value
– Milind
Nov 23 '18 at 23:36
1
commentCountis going to return a promise,.. Using deferred doesn't change things here, you could have just donereturn getData(url).
– Keith
Nov 23 '18 at 23:36
Can you please show me example
– Milind
Nov 23 '18 at 23:38
Unless you say usedasync / awaityour can't do something like"some string" + somePromise(), you need to resolve your promise first. If usingasync / await, this could be done ->"some string" + await somePromise()
– Keith
Nov 23 '18 at 23:40
How we can do that
– Milind
Nov 23 '18 at 23:42
|
show 1 more comment
0
0
0
I have below function
function commentCount(id) {
var deferred = new $.Deferred()
var url =
_spPageContextInfo.siteAbsoluteUrl +
"/_api/lists/getByTitle('Comments')/items?$select=Id&$filter=ItemID eq " +
id +
" and Title eq 'Colleague'"
getData(url).then(function(data) {
deferred.resolve(data.d.results.length)
})
return deferred.promise()
}
Now I want to return that value in HTML string as below but it shows [object object]
'<div class="card-footer"> <div class="row "><div class="col-lg mobile-center"><a href="#">' + commentCount(item.Id)
How can I get value like that
javascript jquery es6-promise jquery-deferred
asked Nov 23 '18 at 23:31
MilindMilind
60021441
I have below function
function commentCount(id) {
var deferred = new $.Deferred()
var url =
_spPageContextInfo.siteAbsoluteUrl +
"/_api/lists/getByTitle('Comments')/items?$select=Id&$filter=ItemID eq " +
id +
" and Title eq 'Colleague'"
getData(url).then(function(data) {
deferred.resolve(data.d.results.length)
})
return deferred.promise()
}
Now I want to return that value in HTML string as below but it shows [object object]
'<div class="card-footer"> <div class="row "><div class="col-lg mobile-center"><a href="#">' + commentCount(item.Id)
How can I get value like that
javascript jquery es6-promise jquery-deferred
javascript jquery es6-promise jquery-deferred
asked Nov 23 '18 at 23:31
MilindMilind
60021441
asked Nov 23 '18 at 23:31
MilindMilind
60021441
asked Nov 23 '18 at 23:31
MilindMilind
60021441
asked Nov 23 '18 at 23:31
MilindMilind
60021441
asked Nov 23 '18 at 23:31
MilindMilind
60021441
60021441
It is integer value
– Milind
Nov 23 '18 at 23:36
1
commentCountis going to return a promise,.. Using deferred doesn't change things here, you could have just donereturn getData(url).
– Keith
Nov 23 '18 at 23:36
Can you please show me example
– Milind
Nov 23 '18 at 23:38
Unless you say usedasync / awaityour can't do something like"some string" + somePromise(), you need to resolve your promise first. If usingasync / await, this could be done ->"some string" + await somePromise()
– Keith
Nov 23 '18 at 23:40
How we can do that
– Milind
Nov 23 '18 at 23:42
|
show 1 more comment
It is integer value
– Milind
Nov 23 '18 at 23:36
1
commentCountis going to return a promise,.. Using deferred doesn't change things here, you could have just donereturn getData(url).
– Keith
Nov 23 '18 at 23:36
Can you please show me example
– Milind
Nov 23 '18 at 23:38
Unless you say usedasync / awaityour can't do something like"some string" + somePromise(), you need to resolve your promise first. If usingasync / await, this could be done ->"some string" + await somePromise()
– Keith
Nov 23 '18 at 23:40
How we can do that
– Milind
Nov 23 '18 at 23:42
It is integer value
– Milind
Nov 23 '18 at 23:36
It is integer value
– Milind
Nov 23 '18 at 23:36
1
1
commentCount is going to return a promise,.. Using deferred doesn't change things here, you could have just done return getData(url).– Keith
Nov 23 '18 at 23:36
commentCount is going to return a promise,.. Using deferred doesn't change things here, you could have just done return getData(url).– Keith
Nov 23 '18 at 23:36
Can you please show me example
– Milind
Nov 23 '18 at 23:38
Can you please show me example
– Milind
Nov 23 '18 at 23:38
Unless you say used
async / await your can't do something like "some string" + somePromise(), you need to resolve your promise first. If using async / await, this could be done -> "some string" + await somePromise()– Keith
Nov 23 '18 at 23:40
Unless you say used
async / await your can't do something like "some string" + somePromise(), you need to resolve your promise first. If using async / await, this could be done -> "some string" + await somePromise()– Keith
Nov 23 '18 at 23:40
How we can do that
– Milind
Nov 23 '18 at 23:42
How we can do that
– Milind
Nov 23 '18 at 23:42
|
show 1 more comment
1 Answer
1
active
oldest
votes
1
Your function is returning a promise and you have to resolve that promise before you can get at the data
It is also using a needless $.Deferred since getData() returns a promise
Needs to be something like:
function commentCount(id) {
var url ='....';
// return the getData promise
return getData(url).then(function(data) {
// return the count to next `then()` in chain
return data.d.results.length
})
}
commentCount(someId).then(function(count){
// do stuff with your html here
var str ='<div> Count:' + count + '</div>';
})
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Your function is returning a promise and you have to resolve that promise before you can get at the data
It is also using a needless $.Deferred since getData() returns a promise
Needs to be something like:
function commentCount(id) {
var url ='....';
// return the getData promise
return getData(url).then(function(data) {
// return the count to next `then()` in chain
return data.d.results.length
})
}
commentCount(someId).then(function(count){
// do stuff with your html here
var str ='<div> Count:' + count + '</div>';
})
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
add a comment |
1
Your function is returning a promise and you have to resolve that promise before you can get at the data
It is also using a needless $.Deferred since getData() returns a promise
Needs to be something like:
function commentCount(id) {
var url ='....';
// return the getData promise
return getData(url).then(function(data) {
// return the count to next `then()` in chain
return data.d.results.length
})
}
commentCount(someId).then(function(count){
// do stuff with your html here
var str ='<div> Count:' + count + '</div>';
})
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
add a comment |
1
1
1
Your function is returning a promise and you have to resolve that promise before you can get at the data
It is also using a needless $.Deferred since getData() returns a promise
Needs to be something like:
function commentCount(id) {
var url ='....';
// return the getData promise
return getData(url).then(function(data) {
// return the count to next `then()` in chain
return data.d.results.length
})
}
commentCount(someId).then(function(count){
// do stuff with your html here
var str ='<div> Count:' + count + '</div>';
})
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
Your function is returning a promise and you have to resolve that promise before you can get at the data
It is also using a needless $.Deferred since getData() returns a promise
Needs to be something like:
function commentCount(id) {
var url ='....';
// return the getData promise
return getData(url).then(function(data) {
// return the count to next `then()` in chain
return data.d.results.length
})
}
commentCount(someId).then(function(count){
// do stuff with your html here
var str ='<div> Count:' + count + '</div>';
})
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
edited Nov 23 '18 at 23:50
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
answered Nov 23 '18 at 23:44
charlietflcharlietfl
139k1389122
139k1389122
add a comment |
add a comment |
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It is integer value
– Milind
Nov 23 '18 at 23:36
1
commentCountis going to return a promise,.. Using deferred doesn't change things here, you could have just donereturn getData(url).– Keith
Nov 23 '18 at 23:36
Can you please show me example
– Milind
Nov 23 '18 at 23:38
Unless you say used
async / awaityour can't do something like"some string" + somePromise(), you need to resolve your promise first. If usingasync / await, this could be done ->"some string" + await somePromise()– Keith
Nov 23 '18 at 23:40
How we can do that
– Milind
Nov 23 '18 at 23:42