multiple step gathering of columns in R
0
I have data.frame like this:
df<-data.frame(Time=c(1:100),Rome_population=c(1:100),Rome_gdp=c(1:100),Rome_LifeLenght=c(1:100),London_population=c(1:100),London_gdp=c(1:100),London_LifeLenght=c(1:100),Berlin_population=c(1:100),Berlin_gdp=c(1:100),Berlin_LifeLenght=c(1:100))
And I would like to have a data.frame like this:
df<-data.frame(Time,City,population,gdp,LifeLenght)
How can I make it? Possibly with tidyr?
Thanks!
r dataframe multiple-columns tidyr
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
asked Nov 23 '18 at 23:32
JordanJordan
205
add a comment |
0
I have data.frame like this:
df<-data.frame(Time=c(1:100),Rome_population=c(1:100),Rome_gdp=c(1:100),Rome_LifeLenght=c(1:100),London_population=c(1:100),London_gdp=c(1:100),London_LifeLenght=c(1:100),Berlin_population=c(1:100),Berlin_gdp=c(1:100),Berlin_LifeLenght=c(1:100))
And I would like to have a data.frame like this:
df<-data.frame(Time,City,population,gdp,LifeLenght)
How can I make it? Possibly with tidyr?
Thanks!
r dataframe multiple-columns tidyr
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
asked Nov 23 '18 at 23:32
JordanJordan
205
add a comment |
0
0
0
I have data.frame like this:
df<-data.frame(Time=c(1:100),Rome_population=c(1:100),Rome_gdp=c(1:100),Rome_LifeLenght=c(1:100),London_population=c(1:100),London_gdp=c(1:100),London_LifeLenght=c(1:100),Berlin_population=c(1:100),Berlin_gdp=c(1:100),Berlin_LifeLenght=c(1:100))
And I would like to have a data.frame like this:
df<-data.frame(Time,City,population,gdp,LifeLenght)
How can I make it? Possibly with tidyr?
Thanks!
r dataframe multiple-columns tidyr
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
asked Nov 23 '18 at 23:32
JordanJordan
205
I have data.frame like this:
df<-data.frame(Time=c(1:100),Rome_population=c(1:100),Rome_gdp=c(1:100),Rome_LifeLenght=c(1:100),London_population=c(1:100),London_gdp=c(1:100),London_LifeLenght=c(1:100),Berlin_population=c(1:100),Berlin_gdp=c(1:100),Berlin_LifeLenght=c(1:100))
And I would like to have a data.frame like this:
df<-data.frame(Time,City,population,gdp,LifeLenght)
How can I make it? Possibly with tidyr?
Thanks!
r dataframe multiple-columns tidyr
r dataframe multiple-columns tidyr
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
asked Nov 23 '18 at 23:32
JordanJordan
205
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
asked Nov 23 '18 at 23:32
JordanJordan
205
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
edited Nov 23 '18 at 23:55
Jack Brookes
2,4282519
2,4282519
asked Nov 23 '18 at 23:32
JordanJordan
205
asked Nov 23 '18 at 23:32
JordanJordan
205
asked Nov 23 '18 at 23:32
JordanJordan
205
205
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
1
Try:
df %>%
gather(key, value, Rome_population:Berlin_LifeLenght) %>%
separate(key, into = c("city", "stat"), sep = "_") %>%
spread(stat, value)
Output:
# A tibble: 300 x 5
Time city gdp LifeLenght population
<int> <chr> <int> <int> <int>
1 1 Berlin 1 1 1
2 1 London 1 1 1
3 1 Rome 1 1 1
4 2 Berlin 2 2 2
5 2 London 2 2 2
6 2 Rome 2 2 2
7 3 Berlin 3 3 3
8 3 London 3 3 3
9 3 Rome 3 3 3
10 4 Berlin 4 4 4
# ... with 290 more rows
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Try:
df %>%
gather(key, value, Rome_population:Berlin_LifeLenght) %>%
separate(key, into = c("city", "stat"), sep = "_") %>%
spread(stat, value)
Output:
# A tibble: 300 x 5
Time city gdp LifeLenght population
<int> <chr> <int> <int> <int>
1 1 Berlin 1 1 1
2 1 London 1 1 1
3 1 Rome 1 1 1
4 2 Berlin 2 2 2
5 2 London 2 2 2
6 2 Rome 2 2 2
7 3 Berlin 3 3 3
8 3 London 3 3 3
9 3 Rome 3 3 3
10 4 Berlin 4 4 4
# ... with 290 more rows
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
add a comment |
1
Try:
df %>%
gather(key, value, Rome_population:Berlin_LifeLenght) %>%
separate(key, into = c("city", "stat"), sep = "_") %>%
spread(stat, value)
Output:
# A tibble: 300 x 5
Time city gdp LifeLenght population
<int> <chr> <int> <int> <int>
1 1 Berlin 1 1 1
2 1 London 1 1 1
3 1 Rome 1 1 1
4 2 Berlin 2 2 2
5 2 London 2 2 2
6 2 Rome 2 2 2
7 3 Berlin 3 3 3
8 3 London 3 3 3
9 3 Rome 3 3 3
10 4 Berlin 4 4 4
# ... with 290 more rows
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
add a comment |
1
1
1
Try:
df %>%
gather(key, value, Rome_population:Berlin_LifeLenght) %>%
separate(key, into = c("city", "stat"), sep = "_") %>%
spread(stat, value)
Output:
# A tibble: 300 x 5
Time city gdp LifeLenght population
<int> <chr> <int> <int> <int>
1 1 Berlin 1 1 1
2 1 London 1 1 1
3 1 Rome 1 1 1
4 2 Berlin 2 2 2
5 2 London 2 2 2
6 2 Rome 2 2 2
7 3 Berlin 3 3 3
8 3 London 3 3 3
9 3 Rome 3 3 3
10 4 Berlin 4 4 4
# ... with 290 more rows
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
Try:
df %>%
gather(key, value, Rome_population:Berlin_LifeLenght) %>%
separate(key, into = c("city", "stat"), sep = "_") %>%
spread(stat, value)
Output:
# A tibble: 300 x 5
Time city gdp LifeLenght population
<int> <chr> <int> <int> <int>
1 1 Berlin 1 1 1
2 1 London 1 1 1
3 1 Rome 1 1 1
4 2 Berlin 2 2 2
5 2 London 2 2 2
6 2 Rome 2 2 2
7 3 Berlin 3 3 3
8 3 London 3 3 3
9 3 Rome 3 3 3
10 4 Berlin 4 4 4
# ... with 290 more rows
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
answered Nov 23 '18 at 23:45
Jack BrookesJack Brookes
2,4282519
2,4282519
add a comment |
add a comment |
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