Nsryjdtyk

I am learning to program with Python. Currently, I am trying to write a simple function that will check to see if a number that the user has entered is prime. The following portion of the function is throwing up an "invalid syntax" sign:

else:

    For x in range(1,b**(1/2)):

        If b%x==0:

            print(str(b) + " is not prime")

            break

"b" is a variable defined elsewhere in the function. It is an integer less than 500 that the user provides. I am getting an "invalid syntax" error pointing at the "x" in the "for x in range..." part of the code. I don't understand why this is the case and would greatly appreciate some insight into this problem.

If it helps, so far, the entire code looks as follows:

def check_prime():

   b = input("Enter an integer less than 500: ")

   if type(b)!='int':

       print("Please enter an integer")

   elif b > 500:

       print ("Please choose a smaller number")

   else:

       For x in range(1,b**(1/2)):

           If b%x==0:

              print(str(b) + " is not prime")

              break

       print (str(b)+ " is prime")

I am aware that the function will not work exactly as I intend just yet, but I do not know how to move forward until I resolve the issue of the syntax error. Thank you, in advance, for your help.

Use for and if instead of For and IF. additionally, Python will give you an error if you skip the indentation

'For' and 'If' should be 'for' and 'if'. Also, range takes two integers not a int and float.

b=9

for x in range(1,int(b**(1/2))):

    if b%x==0:

        print(str(b) + " is not prime")

        break