Entity Framework Core 2.1 : The specified field 'Model' could not be found for property 'Model' on entity...
I need to use Code First approach to generate Database by Entity Framework Core 2.1 but I get this error:
The specified field 'Model' could not be found for property 'Model' on entity type 'BarCodeDevice'.
Here are the classes I have used to do so
public class BarCodeDevice
{
public int SerialNumber { get; set; }
public string Model { get; set; }
public virtual ICollection<ClientBarCodeDevice> ClientBarCodeDeviceList { get; set; }
}
And the configuration class
public class BarCodeDeviceConfiguration : IEntityTypeConfiguration<BarCodeDevice>
{
public void Configure(EntityTypeBuilder<BarCodeDevice> builder)
{
builder.HasKey(x => x.SerialNumber);
builder.Property(t => t.Model)
.IsRequired()
.HasField("Model");
}
}
And The DbContext Class
public class SegregationDbContext : DbContext, IDisposable
{
public SegregationDbContext(DbContextOptions<SegregationDbContext> options) : base(options)
{ }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.ApplyConfiguration(new BarCodeDeviceConfiguration());
}
public DbSet<BarCodeDevice> BarCodeDevices { get; set; }
}
And finally the configuration
public void ConfigureServices(IServiceCollection services)
{
services.AddDbContext<SegregationDbContext>(options => options.UseSqlServer(Configuration.GetConnectionString("Default")));
services.AddMvc();
}
c#-4.0 entity-framework-core
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
add a comment |
I need to use Code First approach to generate Database by Entity Framework Core 2.1 but I get this error:
The specified field 'Model' could not be found for property 'Model' on entity type 'BarCodeDevice'.
Here are the classes I have used to do so
public class BarCodeDevice
{
public int SerialNumber { get; set; }
public string Model { get; set; }
public virtual ICollection<ClientBarCodeDevice> ClientBarCodeDeviceList { get; set; }
}
And the configuration class
public class BarCodeDeviceConfiguration : IEntityTypeConfiguration<BarCodeDevice>
{
public void Configure(EntityTypeBuilder<BarCodeDevice> builder)
{
builder.HasKey(x => x.SerialNumber);
builder.Property(t => t.Model)
.IsRequired()
.HasField("Model");
}
}
And The DbContext Class
public class SegregationDbContext : DbContext, IDisposable
{
public SegregationDbContext(DbContextOptions<SegregationDbContext> options) : base(options)
{ }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.ApplyConfiguration(new BarCodeDeviceConfiguration());
}
public DbSet<BarCodeDevice> BarCodeDevices { get; set; }
}
And finally the configuration
public void ConfigureServices(IServiceCollection services)
{
services.AddDbContext<SegregationDbContext>(options => options.UseSqlServer(Configuration.GetConnectionString("Default")));
services.AddMvc();
}
c#-4.0 entity-framework-core
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
add a comment |
I need to use Code First approach to generate Database by Entity Framework Core 2.1 but I get this error:
The specified field 'Model' could not be found for property 'Model' on entity type 'BarCodeDevice'.
Here are the classes I have used to do so
public class BarCodeDevice
{
public int SerialNumber { get; set; }
public string Model { get; set; }
public virtual ICollection<ClientBarCodeDevice> ClientBarCodeDeviceList { get; set; }
}
And the configuration class
public class BarCodeDeviceConfiguration : IEntityTypeConfiguration<BarCodeDevice>
{
public void Configure(EntityTypeBuilder<BarCodeDevice> builder)
{
builder.HasKey(x => x.SerialNumber);
builder.Property(t => t.Model)
.IsRequired()
.HasField("Model");
}
}
And The DbContext Class
public class SegregationDbContext : DbContext, IDisposable
{
public SegregationDbContext(DbContextOptions<SegregationDbContext> options) : base(options)
{ }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.ApplyConfiguration(new BarCodeDeviceConfiguration());
}
public DbSet<BarCodeDevice> BarCodeDevices { get; set; }
}
And finally the configuration
public void ConfigureServices(IServiceCollection services)
{
services.AddDbContext<SegregationDbContext>(options => options.UseSqlServer(Configuration.GetConnectionString("Default")));
services.AddMvc();
}
c#-4.0 entity-framework-core
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
I need to use Code First approach to generate Database by Entity Framework Core 2.1 but I get this error:
The specified field 'Model' could not be found for property 'Model' on entity type 'BarCodeDevice'.
Here are the classes I have used to do so
public class BarCodeDevice
{
public int SerialNumber { get; set; }
public string Model { get; set; }
public virtual ICollection<ClientBarCodeDevice> ClientBarCodeDeviceList { get; set; }
}
And the configuration class
public class BarCodeDeviceConfiguration : IEntityTypeConfiguration<BarCodeDevice>
{
public void Configure(EntityTypeBuilder<BarCodeDevice> builder)
{
builder.HasKey(x => x.SerialNumber);
builder.Property(t => t.Model)
.IsRequired()
.HasField("Model");
}
}
And The DbContext Class
public class SegregationDbContext : DbContext, IDisposable
{
public SegregationDbContext(DbContextOptions<SegregationDbContext> options) : base(options)
{ }
protected override void OnModelCreating(ModelBuilder modelBuilder)
{
modelBuilder.ApplyConfiguration(new BarCodeDeviceConfiguration());
}
public DbSet<BarCodeDevice> BarCodeDevices { get; set; }
}
And finally the configuration
public void ConfigureServices(IServiceCollection services)
{
services.AddDbContext<SegregationDbContext>(options => options.UseSqlServer(Configuration.GetConnectionString("Default")));
services.AddMvc();
}
c#-4.0 entity-framework-core
c#-4.0 entity-framework-core
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
asked Nov 25 '18 at 10:14
amin mohammadiamin mohammadi
828
828
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
The problem is this fluent configuration line:
.HasField("Model")
HasField is used to specify the backing field for the property being configured, when the backing field name does not conform to the conventions.
But you Model property is auto property and there is no backing field called Model, hence the exception.
So either remove that line, e.g.
builder.Property(t => t.Model)
.IsRequired();
or if you want to force using the backing field with unknown name (which is the case with auto properties), use UsePropertyAccessMode method instead, e.g.
builder.Property(t => t.Model)
.IsRequired()
.UsePropertyAccessMode(PropertyAccessMode.Field);
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53466495%2fentity-framework-core-2-1-the-specified-field-model-could-not-be-found-for-p%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem is this fluent configuration line:
.HasField("Model")
HasField is used to specify the backing field for the property being configured, when the backing field name does not conform to the conventions.
But you Model property is auto property and there is no backing field called Model, hence the exception.
So either remove that line, e.g.
builder.Property(t => t.Model)
.IsRequired();
or if you want to force using the backing field with unknown name (which is the case with auto properties), use UsePropertyAccessMode method instead, e.g.
builder.Property(t => t.Model)
.IsRequired()
.UsePropertyAccessMode(PropertyAccessMode.Field);
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
add a comment |
The problem is this fluent configuration line:
.HasField("Model")
HasField is used to specify the backing field for the property being configured, when the backing field name does not conform to the conventions.
But you Model property is auto property and there is no backing field called Model, hence the exception.
So either remove that line, e.g.
builder.Property(t => t.Model)
.IsRequired();
or if you want to force using the backing field with unknown name (which is the case with auto properties), use UsePropertyAccessMode method instead, e.g.
builder.Property(t => t.Model)
.IsRequired()
.UsePropertyAccessMode(PropertyAccessMode.Field);
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
add a comment |
The problem is this fluent configuration line:
.HasField("Model")
HasField is used to specify the backing field for the property being configured, when the backing field name does not conform to the conventions.
But you Model property is auto property and there is no backing field called Model, hence the exception.
So either remove that line, e.g.
builder.Property(t => t.Model)
.IsRequired();
or if you want to force using the backing field with unknown name (which is the case with auto properties), use UsePropertyAccessMode method instead, e.g.
builder.Property(t => t.Model)
.IsRequired()
.UsePropertyAccessMode(PropertyAccessMode.Field);
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
The problem is this fluent configuration line:
.HasField("Model")
HasField is used to specify the backing field for the property being configured, when the backing field name does not conform to the conventions.
But you Model property is auto property and there is no backing field called Model, hence the exception.
So either remove that line, e.g.
builder.Property(t => t.Model)
.IsRequired();
or if you want to force using the backing field with unknown name (which is the case with auto properties), use UsePropertyAccessMode method instead, e.g.
builder.Property(t => t.Model)
.IsRequired()
.UsePropertyAccessMode(PropertyAccessMode.Field);
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
answered Nov 25 '18 at 11:19
Ivan StoevIvan Stoev
106k782135
106k782135
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53466495%2fentity-framework-core-2-1-the-specified-field-model-could-not-be-found-for-p%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
