rearrangement of lists of strings
up vote
2
down vote
favorite
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis
. As always, thanks for suggestions!
string-manipulation
add a comment |
up vote
2
down vote
favorite
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis
. As always, thanks for suggestions!
string-manipulation
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis
. As always, thanks for suggestions!
string-manipulation
I have a list:
lis = {{"abc","def","ghi"},{"jkl","mno"}}
and wish to get:
res = {"abc def ghi","jkl mno"}
This:
Table[StringJoin[lis[[i]]], {i, Length[lis]}]
doesn't produce the desired " " between the original elements in lis
. As always, thanks for suggestions!
string-manipulation
string-manipulation
edited 2 hours ago
kglr
172k8194399
172k8194399
asked 2 hours ago
Suite401
937312
937312
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
4
down vote
You can use StringRiffle
:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
add a comment |
up vote
1
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
You can use StringRiffle
:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
add a comment |
up vote
4
down vote
You can use StringRiffle
:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
add a comment |
up vote
4
down vote
up vote
4
down vote
You can use StringRiffle
:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
You can use StringRiffle
:
StringRiffle /@ lis
{"abc def ghi", "jkl mno"}
answered 2 hours ago
kglr
172k8194399
172k8194399
add a comment |
add a comment |
up vote
1
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
add a comment |
up vote
1
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
add a comment |
up vote
1
down vote
up vote
1
down vote
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
Use Riffle
lis = {{"abc", "def", "ghi"}, {"jkl", "mno"}};
StringJoin[Riffle[#, " "]] & /@ lis
(* {"abc def ghi", "jkl mno"} *)
answered 2 hours ago
Bob Hanlon
57.5k23591
57.5k23591
add a comment |
add a comment |
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