Replace color in image measured by Euclidean distance












10












$begingroup$


This script replaces the red hair in image to black color (replace one color to another)





Three major parts in this script




  • Not just replace color red to black, I hope the output image looks natural, so I will replace the color close to red to black. This "close" is measured by Euclidean distance.


  • And not just replace by black color, user can modify the red color's r, g, b value separately, like add more green.


  • Choose the area to be changed, rather than change the whole picture





Suggestions I am looking for:




  • I did some NumPy practice before, so any suggestions about NumPy are welcome.


  • I think the code to replace target area is not so elegant, I am not quite sure about this part:



    (c1, r1), (c2, r2) = area
    for i in range(r1, r2+1):
    l, r = i*h+c1, i*h+c2+1
    data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])





Full code:



import numpy as np
from PIL import Image
from scipy.spatial.distance import cdist

def replace_corlor(image, original_corlor, modification, area=None, distance=1000, output="new_test.jpg"):
print("[*] START Replace Color")
img = Image.open(image)
data = np.asarray(img, dtype="int32")
w,h,k = data.shape
data = np.reshape(data, (w*h,k))
distMatrix = cdist(data, np.array([original_corlor]))
D = distMatrix<=distance
D = np.reshape(D,w*h)
if area is None:
data[:,:k][D] = modification(data[:,:k][D])
else:
(c1, r1), (c2, r2) = area
for i in range(r1, r2+1):
l, r = i*h+c1, i*h+c2+1
data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])
data = np.reshape(data, (w,h,k))
img = Image.fromarray(np.asarray(np.clip(data, 0, 255), dtype="uint8"), "RGB")
img.save(output)
print("[*] DONE Replace Color")

if __name__ == "__main__":
def modification(color):
return color * [2,0,0]
# return [255,0,0]
replace_corlor("test.jpg",(36,35,30),modification, ((0,0),(400,100)))









share|improve this question











$endgroup$








  • 1




    $begingroup$
    I have no comments on your code, your Python is better than mine. :) But for color modification you could use the distance to the original_color value. The larger this distance (and the closer the distance is to the distance threshold), the less you modify the color. This way, you will get a smoother transition at the edges of the red region.
    $endgroup$
    – Cris Luengo
    Nov 14 '18 at 5:42










  • $begingroup$
    @CrisLuengo Ah good advice!, thank you ^^
    $endgroup$
    – Aries_is_there
    Nov 14 '18 at 5:56










  • $begingroup$
    Couple of points, firstly, it appears that the modification function only works if it operates on vectors, rather than a single pixel, as you're passing that function the whole image at once. In some ways, it is doing most of the work. Secondly, There's a typo in the variable name original_corlor, nothing major, just confused me for a second. I find the contents of the else clause very confusing, partly because of very short variable names.
    $endgroup$
    – gbartonowen
    Jan 30 at 18:18










  • $begingroup$
    @gbartonowen sorry I don't get what you mean "it operates on vectors, rather than a single pixel", there is a area in parameters, if you wanna just change one pixel, for example the first pixel, just set area=((0,0),(1,1)), and about the typo, you are totally right
    $endgroup$
    – Aries_is_there
    Feb 17 at 18:34










  • $begingroup$
    @Aries_is_there The modification function takes a 3D array of pixels, rather than a single pixel, which means you must formulate the function as numpy compatible operators. In this case it works fine but it looks like a happens to work rather than is meant to work like this
    $endgroup$
    – gbartonowen
    Feb 19 at 10:06
















10












$begingroup$


This script replaces the red hair in image to black color (replace one color to another)





Three major parts in this script




  • Not just replace color red to black, I hope the output image looks natural, so I will replace the color close to red to black. This "close" is measured by Euclidean distance.


  • And not just replace by black color, user can modify the red color's r, g, b value separately, like add more green.


  • Choose the area to be changed, rather than change the whole picture





Suggestions I am looking for:




  • I did some NumPy practice before, so any suggestions about NumPy are welcome.


  • I think the code to replace target area is not so elegant, I am not quite sure about this part:



    (c1, r1), (c2, r2) = area
    for i in range(r1, r2+1):
    l, r = i*h+c1, i*h+c2+1
    data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])





Full code:



import numpy as np
from PIL import Image
from scipy.spatial.distance import cdist

def replace_corlor(image, original_corlor, modification, area=None, distance=1000, output="new_test.jpg"):
print("[*] START Replace Color")
img = Image.open(image)
data = np.asarray(img, dtype="int32")
w,h,k = data.shape
data = np.reshape(data, (w*h,k))
distMatrix = cdist(data, np.array([original_corlor]))
D = distMatrix<=distance
D = np.reshape(D,w*h)
if area is None:
data[:,:k][D] = modification(data[:,:k][D])
else:
(c1, r1), (c2, r2) = area
for i in range(r1, r2+1):
l, r = i*h+c1, i*h+c2+1
data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])
data = np.reshape(data, (w,h,k))
img = Image.fromarray(np.asarray(np.clip(data, 0, 255), dtype="uint8"), "RGB")
img.save(output)
print("[*] DONE Replace Color")

if __name__ == "__main__":
def modification(color):
return color * [2,0,0]
# return [255,0,0]
replace_corlor("test.jpg",(36,35,30),modification, ((0,0),(400,100)))









share|improve this question











$endgroup$








  • 1




    $begingroup$
    I have no comments on your code, your Python is better than mine. :) But for color modification you could use the distance to the original_color value. The larger this distance (and the closer the distance is to the distance threshold), the less you modify the color. This way, you will get a smoother transition at the edges of the red region.
    $endgroup$
    – Cris Luengo
    Nov 14 '18 at 5:42










  • $begingroup$
    @CrisLuengo Ah good advice!, thank you ^^
    $endgroup$
    – Aries_is_there
    Nov 14 '18 at 5:56










  • $begingroup$
    Couple of points, firstly, it appears that the modification function only works if it operates on vectors, rather than a single pixel, as you're passing that function the whole image at once. In some ways, it is doing most of the work. Secondly, There's a typo in the variable name original_corlor, nothing major, just confused me for a second. I find the contents of the else clause very confusing, partly because of very short variable names.
    $endgroup$
    – gbartonowen
    Jan 30 at 18:18










  • $begingroup$
    @gbartonowen sorry I don't get what you mean "it operates on vectors, rather than a single pixel", there is a area in parameters, if you wanna just change one pixel, for example the first pixel, just set area=((0,0),(1,1)), and about the typo, you are totally right
    $endgroup$
    – Aries_is_there
    Feb 17 at 18:34










  • $begingroup$
    @Aries_is_there The modification function takes a 3D array of pixels, rather than a single pixel, which means you must formulate the function as numpy compatible operators. In this case it works fine but it looks like a happens to work rather than is meant to work like this
    $endgroup$
    – gbartonowen
    Feb 19 at 10:06














10












10








10


3



$begingroup$


This script replaces the red hair in image to black color (replace one color to another)





Three major parts in this script




  • Not just replace color red to black, I hope the output image looks natural, so I will replace the color close to red to black. This "close" is measured by Euclidean distance.


  • And not just replace by black color, user can modify the red color's r, g, b value separately, like add more green.


  • Choose the area to be changed, rather than change the whole picture





Suggestions I am looking for:




  • I did some NumPy practice before, so any suggestions about NumPy are welcome.


  • I think the code to replace target area is not so elegant, I am not quite sure about this part:



    (c1, r1), (c2, r2) = area
    for i in range(r1, r2+1):
    l, r = i*h+c1, i*h+c2+1
    data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])





Full code:



import numpy as np
from PIL import Image
from scipy.spatial.distance import cdist

def replace_corlor(image, original_corlor, modification, area=None, distance=1000, output="new_test.jpg"):
print("[*] START Replace Color")
img = Image.open(image)
data = np.asarray(img, dtype="int32")
w,h,k = data.shape
data = np.reshape(data, (w*h,k))
distMatrix = cdist(data, np.array([original_corlor]))
D = distMatrix<=distance
D = np.reshape(D,w*h)
if area is None:
data[:,:k][D] = modification(data[:,:k][D])
else:
(c1, r1), (c2, r2) = area
for i in range(r1, r2+1):
l, r = i*h+c1, i*h+c2+1
data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])
data = np.reshape(data, (w,h,k))
img = Image.fromarray(np.asarray(np.clip(data, 0, 255), dtype="uint8"), "RGB")
img.save(output)
print("[*] DONE Replace Color")

if __name__ == "__main__":
def modification(color):
return color * [2,0,0]
# return [255,0,0]
replace_corlor("test.jpg",(36,35,30),modification, ((0,0),(400,100)))









share|improve this question











$endgroup$




This script replaces the red hair in image to black color (replace one color to another)





Three major parts in this script




  • Not just replace color red to black, I hope the output image looks natural, so I will replace the color close to red to black. This "close" is measured by Euclidean distance.


  • And not just replace by black color, user can modify the red color's r, g, b value separately, like add more green.


  • Choose the area to be changed, rather than change the whole picture





Suggestions I am looking for:




  • I did some NumPy practice before, so any suggestions about NumPy are welcome.


  • I think the code to replace target area is not so elegant, I am not quite sure about this part:



    (c1, r1), (c2, r2) = area
    for i in range(r1, r2+1):
    l, r = i*h+c1, i*h+c2+1
    data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])





Full code:



import numpy as np
from PIL import Image
from scipy.spatial.distance import cdist

def replace_corlor(image, original_corlor, modification, area=None, distance=1000, output="new_test.jpg"):
print("[*] START Replace Color")
img = Image.open(image)
data = np.asarray(img, dtype="int32")
w,h,k = data.shape
data = np.reshape(data, (w*h,k))
distMatrix = cdist(data, np.array([original_corlor]))
D = distMatrix<=distance
D = np.reshape(D,w*h)
if area is None:
data[:,:k][D] = modification(data[:,:k][D])
else:
(c1, r1), (c2, r2) = area
for i in range(r1, r2+1):
l, r = i*h+c1, i*h+c2+1
data[l:r,:k][D[l:r]] = modification(data[l:r,:k][D[l:r]])
data = np.reshape(data, (w,h,k))
img = Image.fromarray(np.asarray(np.clip(data, 0, 255), dtype="uint8"), "RGB")
img.save(output)
print("[*] DONE Replace Color")

if __name__ == "__main__":
def modification(color):
return color * [2,0,0]
# return [255,0,0]
replace_corlor("test.jpg",(36,35,30),modification, ((0,0),(400,100)))






python python-3.x image numpy






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 5:32









Cris Luengo

2,544319




2,544319










asked Nov 11 '18 at 10:27









Aries_is_thereAries_is_there

692212




692212








  • 1




    $begingroup$
    I have no comments on your code, your Python is better than mine. :) But for color modification you could use the distance to the original_color value. The larger this distance (and the closer the distance is to the distance threshold), the less you modify the color. This way, you will get a smoother transition at the edges of the red region.
    $endgroup$
    – Cris Luengo
    Nov 14 '18 at 5:42










  • $begingroup$
    @CrisLuengo Ah good advice!, thank you ^^
    $endgroup$
    – Aries_is_there
    Nov 14 '18 at 5:56










  • $begingroup$
    Couple of points, firstly, it appears that the modification function only works if it operates on vectors, rather than a single pixel, as you're passing that function the whole image at once. In some ways, it is doing most of the work. Secondly, There's a typo in the variable name original_corlor, nothing major, just confused me for a second. I find the contents of the else clause very confusing, partly because of very short variable names.
    $endgroup$
    – gbartonowen
    Jan 30 at 18:18










  • $begingroup$
    @gbartonowen sorry I don't get what you mean "it operates on vectors, rather than a single pixel", there is a area in parameters, if you wanna just change one pixel, for example the first pixel, just set area=((0,0),(1,1)), and about the typo, you are totally right
    $endgroup$
    – Aries_is_there
    Feb 17 at 18:34










  • $begingroup$
    @Aries_is_there The modification function takes a 3D array of pixels, rather than a single pixel, which means you must formulate the function as numpy compatible operators. In this case it works fine but it looks like a happens to work rather than is meant to work like this
    $endgroup$
    – gbartonowen
    Feb 19 at 10:06














  • 1




    $begingroup$
    I have no comments on your code, your Python is better than mine. :) But for color modification you could use the distance to the original_color value. The larger this distance (and the closer the distance is to the distance threshold), the less you modify the color. This way, you will get a smoother transition at the edges of the red region.
    $endgroup$
    – Cris Luengo
    Nov 14 '18 at 5:42










  • $begingroup$
    @CrisLuengo Ah good advice!, thank you ^^
    $endgroup$
    – Aries_is_there
    Nov 14 '18 at 5:56










  • $begingroup$
    Couple of points, firstly, it appears that the modification function only works if it operates on vectors, rather than a single pixel, as you're passing that function the whole image at once. In some ways, it is doing most of the work. Secondly, There's a typo in the variable name original_corlor, nothing major, just confused me for a second. I find the contents of the else clause very confusing, partly because of very short variable names.
    $endgroup$
    – gbartonowen
    Jan 30 at 18:18










  • $begingroup$
    @gbartonowen sorry I don't get what you mean "it operates on vectors, rather than a single pixel", there is a area in parameters, if you wanna just change one pixel, for example the first pixel, just set area=((0,0),(1,1)), and about the typo, you are totally right
    $endgroup$
    – Aries_is_there
    Feb 17 at 18:34










  • $begingroup$
    @Aries_is_there The modification function takes a 3D array of pixels, rather than a single pixel, which means you must formulate the function as numpy compatible operators. In this case it works fine but it looks like a happens to work rather than is meant to work like this
    $endgroup$
    – gbartonowen
    Feb 19 at 10:06








1




1




$begingroup$
I have no comments on your code, your Python is better than mine. :) But for color modification you could use the distance to the original_color value. The larger this distance (and the closer the distance is to the distance threshold), the less you modify the color. This way, you will get a smoother transition at the edges of the red region.
$endgroup$
– Cris Luengo
Nov 14 '18 at 5:42




$begingroup$
I have no comments on your code, your Python is better than mine. :) But for color modification you could use the distance to the original_color value. The larger this distance (and the closer the distance is to the distance threshold), the less you modify the color. This way, you will get a smoother transition at the edges of the red region.
$endgroup$
– Cris Luengo
Nov 14 '18 at 5:42












$begingroup$
@CrisLuengo Ah good advice!, thank you ^^
$endgroup$
– Aries_is_there
Nov 14 '18 at 5:56




$begingroup$
@CrisLuengo Ah good advice!, thank you ^^
$endgroup$
– Aries_is_there
Nov 14 '18 at 5:56












$begingroup$
Couple of points, firstly, it appears that the modification function only works if it operates on vectors, rather than a single pixel, as you're passing that function the whole image at once. In some ways, it is doing most of the work. Secondly, There's a typo in the variable name original_corlor, nothing major, just confused me for a second. I find the contents of the else clause very confusing, partly because of very short variable names.
$endgroup$
– gbartonowen
Jan 30 at 18:18




$begingroup$
Couple of points, firstly, it appears that the modification function only works if it operates on vectors, rather than a single pixel, as you're passing that function the whole image at once. In some ways, it is doing most of the work. Secondly, There's a typo in the variable name original_corlor, nothing major, just confused me for a second. I find the contents of the else clause very confusing, partly because of very short variable names.
$endgroup$
– gbartonowen
Jan 30 at 18:18












$begingroup$
@gbartonowen sorry I don't get what you mean "it operates on vectors, rather than a single pixel", there is a area in parameters, if you wanna just change one pixel, for example the first pixel, just set area=((0,0),(1,1)), and about the typo, you are totally right
$endgroup$
– Aries_is_there
Feb 17 at 18:34




$begingroup$
@gbartonowen sorry I don't get what you mean "it operates on vectors, rather than a single pixel", there is a area in parameters, if you wanna just change one pixel, for example the first pixel, just set area=((0,0),(1,1)), and about the typo, you are totally right
$endgroup$
– Aries_is_there
Feb 17 at 18:34












$begingroup$
@Aries_is_there The modification function takes a 3D array of pixels, rather than a single pixel, which means you must formulate the function as numpy compatible operators. In this case it works fine but it looks like a happens to work rather than is meant to work like this
$endgroup$
– gbartonowen
Feb 19 at 10:06




$begingroup$
@Aries_is_there The modification function takes a 3D array of pixels, rather than a single pixel, which means you must formulate the function as numpy compatible operators. In this case it works fine but it looks like a happens to work rather than is meant to work like this
$endgroup$
– gbartonowen
Feb 19 at 10:06










1 Answer
1






active

oldest

votes


















0












$begingroup$

Nice code.
Let's look at the function signatures.
As gbartonowen noted, two typos on corlor for color.
The keyword defaults are lovely,
thank you for appropriately dealing with a magic number, and defaulting the filespec.
Lots of keywords will lead to a somewhat long signature, though, as reported by $ flake8:



E501 line too long (106 > 79 characters)


Recommend you always run such a linter before sharing code.
And heed the linter's advice.
In the same vein we see things like PEP-8 wants spaces in the w, h, k assignment,
or (w * h, k) expression.
And, this being python rather than java,
snake-case identifiers of d and dist_matrix would be much more appropriate.
Python convention says the Gentle Reader should expect D to be a class.
(Yes, I know this clashes with conventions of the mathematical community,
something had to give. Ok, on to more substantive comments.)



An identifier of data is always on the vague side,
it's a bit like naming your variable the_thing.
Yes, it's accurate, but often it could be a little more informative.
Consider a rename along these lines:



    img = np.asarray(Image.open(image), dtype='int32')


(Hmmm, as I look at that, maybe we'd like identifiers of in_file and out_file?)



The cdist() call, which defaults to Euclidean, is pretty interesting,
since RGB is not a perceptually uniform color scheme.
Consider mapping to Lab* colorspace and using that for comparisons.



It is slightly tricky for a naive caller to correctly pass in area,
so it warrants mention in the docstring you're going to write,
or at least in a comment.
Similarly for the modification signature.
Consider raising an error if c1 < c2 or r1 < r2 does not hold.



The l, r identifiers are well chosen,
and I eventually puzzled out their meaning,
but I wouldn't mind a comment mentioning "left, right",
as I kept thinking in terms of "row".
I also wouldn't mind seeing comments explaining the need for each reshape().



If speed is a concern, then figuring out how to get modification()
to broadcast values to a sub-rectangle would be the thing to focus on.



The saturating aspect of [2, 0, 0] is slightly surprising,
please comment on it, and how it deliberately interacts with clip().
Also, the list is not pythonic, this should definitely be the tuple (2, 0, 0).
A more descriptive name, perhaps red_modification, would be appropriate.



Protecting def modification so import won't see it
kind of make sense, but is a little weird.
You don't want that example to be part of your public API, that's fine.
But consider using def _modification in the usual way,
so the __main__ clause is just a one-liner.



Well, OK, two lines, as the magic tuple (36, 35, 30)
needs a name like dark_gray.



Looks good, ship it!






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    $begingroup$

    Nice code.
    Let's look at the function signatures.
    As gbartonowen noted, two typos on corlor for color.
    The keyword defaults are lovely,
    thank you for appropriately dealing with a magic number, and defaulting the filespec.
    Lots of keywords will lead to a somewhat long signature, though, as reported by $ flake8:



    E501 line too long (106 > 79 characters)


    Recommend you always run such a linter before sharing code.
    And heed the linter's advice.
    In the same vein we see things like PEP-8 wants spaces in the w, h, k assignment,
    or (w * h, k) expression.
    And, this being python rather than java,
    snake-case identifiers of d and dist_matrix would be much more appropriate.
    Python convention says the Gentle Reader should expect D to be a class.
    (Yes, I know this clashes with conventions of the mathematical community,
    something had to give. Ok, on to more substantive comments.)



    An identifier of data is always on the vague side,
    it's a bit like naming your variable the_thing.
    Yes, it's accurate, but often it could be a little more informative.
    Consider a rename along these lines:



        img = np.asarray(Image.open(image), dtype='int32')


    (Hmmm, as I look at that, maybe we'd like identifiers of in_file and out_file?)



    The cdist() call, which defaults to Euclidean, is pretty interesting,
    since RGB is not a perceptually uniform color scheme.
    Consider mapping to Lab* colorspace and using that for comparisons.



    It is slightly tricky for a naive caller to correctly pass in area,
    so it warrants mention in the docstring you're going to write,
    or at least in a comment.
    Similarly for the modification signature.
    Consider raising an error if c1 < c2 or r1 < r2 does not hold.



    The l, r identifiers are well chosen,
    and I eventually puzzled out their meaning,
    but I wouldn't mind a comment mentioning "left, right",
    as I kept thinking in terms of "row".
    I also wouldn't mind seeing comments explaining the need for each reshape().



    If speed is a concern, then figuring out how to get modification()
    to broadcast values to a sub-rectangle would be the thing to focus on.



    The saturating aspect of [2, 0, 0] is slightly surprising,
    please comment on it, and how it deliberately interacts with clip().
    Also, the list is not pythonic, this should definitely be the tuple (2, 0, 0).
    A more descriptive name, perhaps red_modification, would be appropriate.



    Protecting def modification so import won't see it
    kind of make sense, but is a little weird.
    You don't want that example to be part of your public API, that's fine.
    But consider using def _modification in the usual way,
    so the __main__ clause is just a one-liner.



    Well, OK, two lines, as the magic tuple (36, 35, 30)
    needs a name like dark_gray.



    Looks good, ship it!






    share|improve this answer











    $endgroup$


















      0












      $begingroup$

      Nice code.
      Let's look at the function signatures.
      As gbartonowen noted, two typos on corlor for color.
      The keyword defaults are lovely,
      thank you for appropriately dealing with a magic number, and defaulting the filespec.
      Lots of keywords will lead to a somewhat long signature, though, as reported by $ flake8:



      E501 line too long (106 > 79 characters)


      Recommend you always run such a linter before sharing code.
      And heed the linter's advice.
      In the same vein we see things like PEP-8 wants spaces in the w, h, k assignment,
      or (w * h, k) expression.
      And, this being python rather than java,
      snake-case identifiers of d and dist_matrix would be much more appropriate.
      Python convention says the Gentle Reader should expect D to be a class.
      (Yes, I know this clashes with conventions of the mathematical community,
      something had to give. Ok, on to more substantive comments.)



      An identifier of data is always on the vague side,
      it's a bit like naming your variable the_thing.
      Yes, it's accurate, but often it could be a little more informative.
      Consider a rename along these lines:



          img = np.asarray(Image.open(image), dtype='int32')


      (Hmmm, as I look at that, maybe we'd like identifiers of in_file and out_file?)



      The cdist() call, which defaults to Euclidean, is pretty interesting,
      since RGB is not a perceptually uniform color scheme.
      Consider mapping to Lab* colorspace and using that for comparisons.



      It is slightly tricky for a naive caller to correctly pass in area,
      so it warrants mention in the docstring you're going to write,
      or at least in a comment.
      Similarly for the modification signature.
      Consider raising an error if c1 < c2 or r1 < r2 does not hold.



      The l, r identifiers are well chosen,
      and I eventually puzzled out their meaning,
      but I wouldn't mind a comment mentioning "left, right",
      as I kept thinking in terms of "row".
      I also wouldn't mind seeing comments explaining the need for each reshape().



      If speed is a concern, then figuring out how to get modification()
      to broadcast values to a sub-rectangle would be the thing to focus on.



      The saturating aspect of [2, 0, 0] is slightly surprising,
      please comment on it, and how it deliberately interacts with clip().
      Also, the list is not pythonic, this should definitely be the tuple (2, 0, 0).
      A more descriptive name, perhaps red_modification, would be appropriate.



      Protecting def modification so import won't see it
      kind of make sense, but is a little weird.
      You don't want that example to be part of your public API, that's fine.
      But consider using def _modification in the usual way,
      so the __main__ clause is just a one-liner.



      Well, OK, two lines, as the magic tuple (36, 35, 30)
      needs a name like dark_gray.



      Looks good, ship it!






      share|improve this answer











      $endgroup$
















        0












        0








        0





        $begingroup$

        Nice code.
        Let's look at the function signatures.
        As gbartonowen noted, two typos on corlor for color.
        The keyword defaults are lovely,
        thank you for appropriately dealing with a magic number, and defaulting the filespec.
        Lots of keywords will lead to a somewhat long signature, though, as reported by $ flake8:



        E501 line too long (106 > 79 characters)


        Recommend you always run such a linter before sharing code.
        And heed the linter's advice.
        In the same vein we see things like PEP-8 wants spaces in the w, h, k assignment,
        or (w * h, k) expression.
        And, this being python rather than java,
        snake-case identifiers of d and dist_matrix would be much more appropriate.
        Python convention says the Gentle Reader should expect D to be a class.
        (Yes, I know this clashes with conventions of the mathematical community,
        something had to give. Ok, on to more substantive comments.)



        An identifier of data is always on the vague side,
        it's a bit like naming your variable the_thing.
        Yes, it's accurate, but often it could be a little more informative.
        Consider a rename along these lines:



            img = np.asarray(Image.open(image), dtype='int32')


        (Hmmm, as I look at that, maybe we'd like identifiers of in_file and out_file?)



        The cdist() call, which defaults to Euclidean, is pretty interesting,
        since RGB is not a perceptually uniform color scheme.
        Consider mapping to Lab* colorspace and using that for comparisons.



        It is slightly tricky for a naive caller to correctly pass in area,
        so it warrants mention in the docstring you're going to write,
        or at least in a comment.
        Similarly for the modification signature.
        Consider raising an error if c1 < c2 or r1 < r2 does not hold.



        The l, r identifiers are well chosen,
        and I eventually puzzled out their meaning,
        but I wouldn't mind a comment mentioning "left, right",
        as I kept thinking in terms of "row".
        I also wouldn't mind seeing comments explaining the need for each reshape().



        If speed is a concern, then figuring out how to get modification()
        to broadcast values to a sub-rectangle would be the thing to focus on.



        The saturating aspect of [2, 0, 0] is slightly surprising,
        please comment on it, and how it deliberately interacts with clip().
        Also, the list is not pythonic, this should definitely be the tuple (2, 0, 0).
        A more descriptive name, perhaps red_modification, would be appropriate.



        Protecting def modification so import won't see it
        kind of make sense, but is a little weird.
        You don't want that example to be part of your public API, that's fine.
        But consider using def _modification in the usual way,
        so the __main__ clause is just a one-liner.



        Well, OK, two lines, as the magic tuple (36, 35, 30)
        needs a name like dark_gray.



        Looks good, ship it!






        share|improve this answer











        $endgroup$



        Nice code.
        Let's look at the function signatures.
        As gbartonowen noted, two typos on corlor for color.
        The keyword defaults are lovely,
        thank you for appropriately dealing with a magic number, and defaulting the filespec.
        Lots of keywords will lead to a somewhat long signature, though, as reported by $ flake8:



        E501 line too long (106 > 79 characters)


        Recommend you always run such a linter before sharing code.
        And heed the linter's advice.
        In the same vein we see things like PEP-8 wants spaces in the w, h, k assignment,
        or (w * h, k) expression.
        And, this being python rather than java,
        snake-case identifiers of d and dist_matrix would be much more appropriate.
        Python convention says the Gentle Reader should expect D to be a class.
        (Yes, I know this clashes with conventions of the mathematical community,
        something had to give. Ok, on to more substantive comments.)



        An identifier of data is always on the vague side,
        it's a bit like naming your variable the_thing.
        Yes, it's accurate, but often it could be a little more informative.
        Consider a rename along these lines:



            img = np.asarray(Image.open(image), dtype='int32')


        (Hmmm, as I look at that, maybe we'd like identifiers of in_file and out_file?)



        The cdist() call, which defaults to Euclidean, is pretty interesting,
        since RGB is not a perceptually uniform color scheme.
        Consider mapping to Lab* colorspace and using that for comparisons.



        It is slightly tricky for a naive caller to correctly pass in area,
        so it warrants mention in the docstring you're going to write,
        or at least in a comment.
        Similarly for the modification signature.
        Consider raising an error if c1 < c2 or r1 < r2 does not hold.



        The l, r identifiers are well chosen,
        and I eventually puzzled out their meaning,
        but I wouldn't mind a comment mentioning "left, right",
        as I kept thinking in terms of "row".
        I also wouldn't mind seeing comments explaining the need for each reshape().



        If speed is a concern, then figuring out how to get modification()
        to broadcast values to a sub-rectangle would be the thing to focus on.



        The saturating aspect of [2, 0, 0] is slightly surprising,
        please comment on it, and how it deliberately interacts with clip().
        Also, the list is not pythonic, this should definitely be the tuple (2, 0, 0).
        A more descriptive name, perhaps red_modification, would be appropriate.



        Protecting def modification so import won't see it
        kind of make sense, but is a little weird.
        You don't want that example to be part of your public API, that's fine.
        But consider using def _modification in the usual way,
        so the __main__ clause is just a one-liner.



        Well, OK, two lines, as the magic tuple (36, 35, 30)
        needs a name like dark_gray.



        Looks good, ship it!







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 21 mins ago

























        answered 28 mins ago









        J_HJ_H

        4,487130




        4,487130






























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